Algebra Examples

$(- 2, 3)$ and slope $m = 9$

Step 1

Use the slope $9$ and a given point $(- 2, 3)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (3) = 9 \cdot (x - (- 2))$

Step 2

Simplify the equation and keep it in point-slope form.

$y - 3 = 9 \cdot (x + 2)$

Step 3

Solve for $y$ .

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Step 3.1

Simplify $9 \cdot (x + 2)$ .

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Step 3.1.1

Rewrite.

$y - 3 = 0 + 0 + 9 \cdot (x + 2)$

Step 3.1.2

Simplify by adding zeros.

$y - 3 = 9 \cdot (x + 2)$

Step 3.1.3

Apply the distributive property.

$y - 3 = 9 x + 9 \cdot 2$

Step 3.1.4

Multiply $9$ by $2$ .

$y - 3 = 9 x + 18$

Step 3.2

Move all terms not containing $y$ to the right side of the equation.

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Step 3.2.1

Add $3$ to both sides of the equation.

$y = 9 x + 18 + 3$

Step 3.2.2

Add $18$ and $3$ .

$y = 9 x + 21$

Step 4

List the equation in different forms.

Slope-intercept form:

$y = 9 x + 21$

Point-slope form:

$y - 3 = 9 \cdot (x + 2)$

Step 5