Algebra Examples

$2 x + 3 y = 12$ for $y$

Step 1

Subtract $2 x$ from both sides of the equation.

$3 y = 12 - 2 x$

Step 2

Divide each term in $3 y = 12 - 2 x$ by $3$ and simplify.

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Step 2.1

Divide each term in $3 y = 12 - 2 x$ by $3$ .

$\frac{3 y}{3} = \frac{12}{3} + \frac{- 2 x}{3}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of $3$ .

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Step 2.2.1.1

Cancel the common factor.

$\frac{3 y}{3} = \frac{12}{3} + \frac{- 2 x}{3}$

Step 2.2.1.2

Divide $y$ by $1$ .

$y = \frac{12}{3} + \frac{- 2 x}{3}$

$y = \frac{12}{3} + \frac{- 2 x}{3}$

$y = \frac{12}{3} + \frac{- 2 x}{3}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Simplify each term.

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Step 2.3.1.1

Divide $12$ by $3$ .

$y = 4 + \frac{- 2 x}{3}$

Step 2.3.1.2

Move the negative in front of the fraction.

$y = 4 - \frac{2 x}{3}$

$y = 4 - \frac{2 x}{3}$

$y = 4 - \frac{2 x}{3}$

$y = 4 - \frac{2 x}{3}$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$