Algebra Examples

$5 (y + 1) - y = 4 (y - 1) + 9$

Step 1

Simplify $5 (y + 1) - y$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

$5 y + 5 \cdot 1 - y = 4 (y - 1) + 9$

Step 1.1.2

Multiply $5$ by $1$ .

$5 y + 5 - y = 4 (y - 1) + 9$

$5 y + 5 - y = 4 (y - 1) + 9$

Step 1.2

Subtract $y$ from $5 y$ .

$4 y + 5 = 4 (y - 1) + 9$

$4 y + 5 = 4 (y - 1) + 9$

Step 2

Simplify $4 (y - 1) + 9$ .

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Step 2.1

Simplify each term.

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Step 2.1.1

Apply the distributive property.

$4 y + 5 = 4 y + 4 \cdot - 1 + 9$

Step 2.1.2

Multiply $4$ by $- 1$ .

$4 y + 5 = 4 y - 4 + 9$

$4 y + 5 = 4 y - 4 + 9$

Step 2.2

Add $- 4$ and $9$ .

$4 y + 5 = 4 y + 5$

$4 y + 5 = 4 y + 5$

Step 3

Move all terms containing $y$ to the left side of the equation.

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Step 3.1

Subtract $4 y$ from both sides of the equation.

$4 y + 5 - 4 y = 5$

Step 3.2

Combine the opposite terms in $4 y + 5 - 4 y$ .

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Step 3.2.1

Subtract $4 y$ from $4 y$ .

$0 + 5 = 5$

Step 3.2.2

Add $0$ and $5$ .

$5 = 5$

$5 = 5$

$5 = 5$

Step 4

Since $5 = 5$ , the equation will always be true.

Always true

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$