Algebra Examples

$(- 5, 2)$ , $y = - x - 3$ $y = 3 x + 10$

Step 1

Simplify $- (- 5) - 3$ .

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Step 1.1

Multiply $- 1$ by $- 5$ .

$2 = 5 - 3$

$2 = 3 (- 5) + 10$

Step 1.2

Subtract $3$ from $5$ .

$2 = 2$

$2 = 3 (- 5) + 10$

$2 = 2$

$2 = 3 (- 5) + 10$

Step 2

Since $2 = 2$ , the equation will always be true.

Always true

$2 = 3 (- 5) + 10$

Step 3

Simplify $3 (- 5) + 10$ .

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Step 3.1

Multiply $3$ by $- 5$ .

$2 = - 15 + 10$

Always true

Step 3.2

Add $- 15$ and $10$ .

$2 = - 5$

Always true

$2 = - 5$

Always true

Step 4

Since $2 \neq - 5$ , there are no solutions.

No solution

Step 5

The ordered pair is not a solution to the system of equations.

$(- 5, 2)$ is not a solution