Algebra Examples

(- 5, 2)

$(- 5, 2)$ ,

y = - x - 3

$y = - x - 3$

y = 3 x + 10

$y = 3 x + 10$

Step 1

Simplify

- (- 5) - 3

$- (- 5) - 3$ .

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Step 1.1

Multiply

- 1

$- 1$ by

- 5

$- 5$ .

2 = 5 - 3

$2 = 5 - 3$

2 = 3 (- 5) + 10

$2 = 3 (- 5) + 10$

Step 1.2

Subtract

3

$3$ from

5

$5$ .

2 = 2

$2 = 2$

2 = 3 (- 5) + 10

$2 = 3 (- 5) + 10$

2 = 2

$2 = 2$

2 = 3 (- 5) + 10

$2 = 3 (- 5) + 10$

Step 2

Since

2 = 2

$2 = 2$ , the equation will always be true.

Always true

2 = 3 (- 5) + 10

$2 = 3 (- 5) + 10$

Step 3

Simplify

3 (- 5) + 10

$3 (- 5) + 10$ .

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Step 3.1

Multiply

3

$3$ by

- 5

$- 5$ .

2 = - 15 + 10

$2 = - 15 + 10$

Always true

Step 3.2

Add

- 15

$- 15$ and

10

$10$ .

2 = - 5

$2 = - 5$

Always true

2 = - 5

$2 = - 5$

Always true

Step 4

Since

2 \neq - 5

$2 \neq - 5$ , there are no solutions.

No solution

Step 5

The ordered pair is not a solution to the system of equations.

(- 5, 2)

$(- 5, 2)$ is not a solution