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Algebra Examples
Step 1
Step 1.1
Replace all occurrences of in with .
Step 1.2
Simplify the right side.
Step 1.2.1
Simplify .
Step 1.2.1.1
Simplify each term.
Step 1.2.1.1.1
Apply the distributive property.
Step 1.2.1.1.2
Simplify.
Step 1.2.1.1.2.1
Multiply .
Step 1.2.1.1.2.1.1
Multiply by .
Step 1.2.1.1.2.1.2
Multiply by .
Step 1.2.1.1.2.2
Multiply by .
Step 1.2.1.1.2.3
Multiply by .
Step 1.2.1.2
Add and .
Step 2
Step 2.1
Rewrite the equation as .
Step 2.2
Subtract from both sides of the equation.
Step 2.3
Combine the opposite terms in .
Step 2.3.1
Subtract from .
Step 2.3.2
Add and .
Step 2.4
Factor out of .
Step 2.4.1
Factor out of .
Step 2.4.2
Factor out of .
Step 2.4.3
Factor out of .
Step 2.5
If any individual factor on the left side of the equation is equal to , the entire expression will be equal to .
Step 2.6
Set equal to .
Step 2.7
Set equal to and solve for .
Step 2.7.1
Set equal to .
Step 2.7.2
Subtract from both sides of the equation.
Step 2.8
The final solution is all the values that make true.
Step 3
Step 3.1
Replace all occurrences of in with .
Step 3.2
Simplify the right side.
Step 3.2.1
Simplify .
Step 3.2.1.1
Simplify each term.
Step 3.2.1.1.1
Raising to any positive power yields .
Step 3.2.1.1.2
Multiply by .
Step 3.2.1.1.3
Multiply by .
Step 3.2.1.2
Simplify by adding and subtracting.
Step 3.2.1.2.1
Add and .
Step 3.2.1.2.2
Subtract from .
Step 4
Step 4.1
Replace all occurrences of in with .
Step 4.2
Simplify the right side.
Step 4.2.1
Simplify .
Step 4.2.1.1
Simplify each term.
Step 4.2.1.1.1
Raise to the power of .
Step 4.2.1.1.2
Multiply by .
Step 4.2.1.1.3
Multiply by .
Step 4.2.1.2
Simplify by adding and subtracting.
Step 4.2.1.2.1
Add and .
Step 4.2.1.2.2
Subtract from .
Step 5
The solution to the system is the complete set of ordered pairs that are valid solutions.
Step 6
The result can be shown in multiple forms.
Point Form:
Equation Form:
Step 7