Algebra Examples

y = 2 x - 3

$y = 2 x - 3$

2 x = y - 3

$2 x = y - 3$

Step 1

Replace all occurrences of

y

$y$ with

2 x - 3

$2 x - 3$ in each equation.

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Step 1.1

Replace all occurrences of

y

$y$ in

2 x = y - 3

$2 x = y - 3$ with

2 x - 3

$2 x - 3$ .

2 x = (2 x - 3) - 3

$2 x = (2 x - 3) - 3$

y = 2 x - 3

$y = 2 x - 3$

Step 1.2

Simplify the right side.

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Step 1.2.1

Subtract

3

$3$ from

- 3

$- 3$ .

2 x = 2 x - 6

$2 x = 2 x - 6$

y = 2 x - 3

$y = 2 x - 3$

2 x = 2 x - 6

$2 x = 2 x - 6$

y = 2 x - 3

$y = 2 x - 3$

2 x = 2 x - 6

$2 x = 2 x - 6$

y = 2 x - 3

$y = 2 x - 3$

Step 2

Solve for

x

$x$ in

2 x = 2 x - 6

$2 x = 2 x - 6$ .

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Step 2.1

Move all terms containing

x

$x$ to the left side of the equation.

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Step 2.1.1

Subtract

2 x

$2 x$ from both sides of the equation.

2 x - 2 x = - 6

$2 x - 2 x = - 6$

y = 2 x - 3

$y = 2 x - 3$

Step 2.1.2

Subtract

2 x

$2 x$ from

2 x

$2 x$ .

0 = - 6

$0 = - 6$

y = 2 x - 3

$y = 2 x - 3$

0 = - 6

$0 = - 6$

y = 2 x - 3

$y = 2 x - 3$

Step 2.2

Since

0 \neq - 6

$0 \neq - 6$ , there are no solutions.

No solution

y = 2 x - 3

$y = 2 x - 3$

No solution

Step 3

[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$