Algebra Examples

$y = \sqrt[3]{x + 2}$

Step 1

Substitute $- 2$ for $x$ and find the result for $y$ .

$y = \sqrt[3]{(- 2) + 2}$

Step 2

Simplify $\sqrt[3]{(- 2) + 2}$ .

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Step 2.1

Add $- 2$ and $2$ .

$y = \sqrt[3]{0}$

Step 2.2

Rewrite $0$ as $0^{3}$ .

$y = \sqrt[3]{0^{3}}$

Step 2.3

Pull terms out from under the radical, assuming real numbers.

$y = 0$

Step 3

Substitute $- 1$ for $x$ and find the result for $y$ .

$y = \sqrt[3]{(- 1) + 2}$

Step 4

Simplify $\sqrt[3]{(- 1) + 2}$ .

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Step 4.1

Add $- 1$ and $2$ .

$y = \sqrt[3]{1}$

Step 4.2

Any root of $1$ is $1$ .

$y = 1$

Step 5

Substitute $0$ for $x$ and find the result for $y$ .

$y = \sqrt[3]{(0) + 2}$

Step 6

Add $0$ and $2$ .

$y = \sqrt[3]{2}$

Step 7

Substitute $1$ for $x$ and find the result for $y$ .

$y = \sqrt[3]{(1) + 2}$

Step 8

Add $1$ and $2$ .

$y = \sqrt[3]{3}$

Step 9

Substitute $2$ for $x$ and find the result for $y$ .

$y = \sqrt[3]{(2) + 2}$

Step 10

Add $2$ and $2$ .

$y = \sqrt[3]{4}$

Step 11

This is a table of possible values to use when graphing the equation.

$\begin{array}{c} x & y \\ - 2 & 0 \\ - 1 & 1 \\ 0 & \sqrt[3]{2} \\ 1 & \sqrt[3]{3} \\ 2 & \sqrt[3]{4} \end{array}$

Step 12