Algebra Examples

$3 a = - b + c$

Step 1

Rewrite the equation as $- b + c = 3 a$ .

$- b + c = 3 a$

Step 2

Subtract $c$ from both sides of the equation.

$- b = 3 a - c$

Step 3

Divide each term in $- b = 3 a - c$ by $- 1$ and simplify.

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Step 3.1

Divide each term in $- b = 3 a - c$ by $- 1$ .

$\frac{- b}{- 1} = \frac{3 a}{- 1} + \frac{- c}{- 1}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Dividing two negative values results in a positive value.

$\frac{b}{1} = \frac{3 a}{- 1} + \frac{- c}{- 1}$

Step 3.2.2

Divide $b$ by $1$ .

$b = \frac{3 a}{- 1} + \frac{- c}{- 1}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Simplify each term.

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Step 3.3.1.1

Move the negative one from the denominator of $\frac{3 a}{- 1}$ .

$b = - 1 \cdot (3 a) + \frac{- c}{- 1}$

Step 3.3.1.2

Rewrite $- 1 \cdot (3 a)$ as $- (3 a)$ .

$b = - (3 a) + \frac{- c}{- 1}$

Step 3.3.1.3

Multiply $3$ by $- 1$ .

$b = - 3 a + \frac{- c}{- 1}$

Step 3.3.1.4

Dividing two negative values results in a positive value.

$b = - 3 a + \frac{c}{1}$

Step 3.3.1.5

Divide $c$ by $1$ .

$b = - 3 a + c$