Algebra Examples

3 a = - b + c

$3 a = - b + c$

Step 1

Rewrite the equation as

- b + c = 3 a

$- b + c = 3 a$ .

- b + c = 3 a

$- b + c = 3 a$

Step 2

Subtract

c

$c$ from both sides of the equation.

- b = 3 a - c

$- b = 3 a - c$

Step 3

Divide each term in

- b = 3 a - c

$- b = 3 a - c$ by

- 1

$- 1$ and simplify.

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Step 3.1

Divide each term in

- b = 3 a - c

$- b = 3 a - c$ by

- 1

$- 1$ .

\frac{- b}{- 1} = \frac{3 a}{- 1} + \frac{- c}{- 1}

$\frac{- b}{- 1} = \frac{3 a}{- 1} + \frac{- c}{- 1}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Dividing two negative values results in a positive value.

\frac{b}{1} = \frac{3 a}{- 1} + \frac{- c}{- 1}

$\frac{b}{1} = \frac{3 a}{- 1} + \frac{- c}{- 1}$

Step 3.2.2

Divide

b

$b$ by

1

$1$ .

b = \frac{3 a}{- 1} + \frac{- c}{- 1}

$b = \frac{3 a}{- 1} + \frac{- c}{- 1}$

b = \frac{3 a}{- 1} + \frac{- c}{- 1}

$b = \frac{3 a}{- 1} + \frac{- c}{- 1}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Simplify each term.

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Step 3.3.1.1

Move the negative one from the denominator of

\frac{3 a}{- 1}

$\frac{3 a}{- 1}$ .

b = - 1 \cdot (3 a) + \frac{- c}{- 1}

$b = - 1 \cdot (3 a) + \frac{- c}{- 1}$

Step 3.3.1.2

Rewrite

- 1 \cdot (3 a)

$- 1 \cdot (3 a)$ as

- (3 a)

$- (3 a)$ .

b = - (3 a) + \frac{- c}{- 1}

$b = - (3 a) + \frac{- c}{- 1}$

Step 3.3.1.3

Multiply

3

$3$ by

- 1

$- 1$ .

b = - 3 a + \frac{- c}{- 1}

$b = - 3 a + \frac{- c}{- 1}$

Step 3.3.1.4

Dividing two negative values results in a positive value.

b = - 3 a + \frac{c}{1}

$b = - 3 a + \frac{c}{1}$

Step 3.3.1.5

Divide

c

$c$ by

1

$1$ .

b = - 3 a + c

$b = - 3 a + c$

b = - 3 a + c

$b = - 3 a + c$

b = - 3 a + c

$b = - 3 a + c$

b = - 3 a + c

$b = - 3 a + c$

3 a = - b + c

$3 a = - b + c$

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