Algebra Examples

$S_{t} = \frac{A}{5 T} + 0.05 d$

Step 1

Rewrite the equation as $\frac{A}{5 T} + 0.05 d = S_{t}$ .

$\frac{A}{5 T} + 0.05 d = S_{t}$

Step 2

Subtract $0.05 d$ from both sides of the equation.

$\frac{A}{5 T} = S_{t} - 0.05 d$

Step 3

Multiply both sides by $5 T$ .

$\frac{A}{5 T} (5 T) = (S_{t} - 0.05 d) (5 T)$

Step 4

Simplify.

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Step 4.1

Simplify the left side.

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Step 4.1.1

Simplify $\frac{A}{5 T} (5 T)$ .

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Step 4.1.1.1

Rewrite using the commutative property of multiplication.

$5 \frac{A}{5 T} T = (S_{t} - 0.05 d) (5 T)$

Step 4.1.1.2

Cancel the common factor of $5$ .

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Step 4.1.1.2.1

Factor $5$ out of $5 T$ .

$5 \frac{A}{5 (T)} T = (S_{t} - 0.05 d) (5 T)$

Step 4.1.1.2.2

Cancel the common factor.

$5 \frac{A}{5 T} T = (S_{t} - 0.05 d) (5 T)$

Step 4.1.1.2.3

Rewrite the expression.

$\frac{A}{T} T = (S_{t} - 0.05 d) (5 T)$

Step 4.1.1.3

Cancel the common factor of $T$ .

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Step 4.1.1.3.1

Cancel the common factor.

$\frac{A}{T} T = (S_{t} - 0.05 d) (5 T)$

Step 4.1.1.3.2

Rewrite the expression.

$A = (S_{t} - 0.05 d) (5 T)$

Step 4.2

Simplify the right side.

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Step 4.2.1

Simplify $(S_{t} - 0.05 d) (5 T)$ .

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Step 4.2.1.1

Apply the distributive property.

$A = S_{t} (5 T) - 0.05 d (5 T)$

Step 4.2.1.2

Simplify the expression.

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Step 4.2.1.2.1

Rewrite using the commutative property of multiplication.

$A = 5 S_{t} T - 0.05 d (5 T)$

Step 4.2.1.2.2

Rewrite using the commutative property of multiplication.

$A = 5 S_{t} T - 0.05 \cdot 5 d T$

Step 4.2.1.2.3

Multiply $- 0.05$ by $5$ .

$A = 5 S_{t} T - 0.25 d T$