Algebra Examples

$f (x) = {(x - 6)}^{2}$ , $[6, \infty)$

Step 1

Find the range of the given function.

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Step 1.1

The range is the set of all valid $y$ values. Use the graph to find the range.

$[0, \infty)$

Step 1.2

Convert $[0, \infty)$ to an inequality.

$y \geq 0$

Step 2

Find the inverse.

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Step 2.1

Interchange the variables.

$x = {(y - 6)}^{2}$

Step 2.2

Solve for $y$ .

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Step 2.2.1

Rewrite the equation as ${(y - 6)}^{2} = x$ .

${(y - 6)}^{2} = x$

Step 2.2.2

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$y - 6 = \pm \sqrt{x}$

Step 2.2.3

The complete solution is the result of both the positive and negative portions of the solution.

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Step 2.2.3.1

First, use the positive value of the $\pm$ to find the first solution.

$y - 6 = \sqrt{x}$

Step 2.2.3.2

Add $6$ to both sides of the equation.

$y = \sqrt{x} + 6$

Step 2.2.3.3

Next, use the negative value of the $\pm$ to find the second solution.

$y - 6 = - \sqrt{x}$

Step 2.2.3.4

Add $6$ to both sides of the equation.

$y = - \sqrt{x} + 6$

Step 2.2.3.5

The complete solution is the result of both the positive and negative portions of the solution.

$y = \sqrt{x} + 6$

$y = - \sqrt{x} + 6$

$y = \sqrt{x} + 6$

$y = - \sqrt{x} + 6$

$y = \sqrt{x} + 6$

$y = - \sqrt{x} + 6$

Step 2.3

Replace $y$ with $f^{- 1} (x)$ to show the final answer.

$f^{- 1} (x) = \sqrt{x} + 6, - \sqrt{x} + 6$

Step 3

Find the inverse using the domain and the range of the original function.

$f^{- 1} (x) = \sqrt{x} + 6, x \geq 0$

Step 4