Algebra Examples

$(6 x^{3} + 12 - 47 x^{2} + 17 x) \div (6 x - 5)$

Step 1

Expand $6 x^{3} + 12 - 47 x^{2} + 17 x$ .

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Step 1.1

Move $12$ .

$\frac{6 x^{3} - 47 x^{2} + 12 + 17 x}{6 x - 5}$

Step 1.2

Move $12$ .

$\frac{6 x^{3} - 47 x^{2} + 17 x + 12}{6 x - 5}$

Step 2

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$6 x$

$5$

$6 x^{3}$

$47 x^{2}$

$17 x$

$12$

Step 3

Divide the highest order term in the dividend $6 x^{3}$ by the highest order term in divisor $6 x$ .

					$x^{2}$
	$6 x$	-	$5$		$6 x^{3}$	-	$47 x^{2}$	+	$17 x$	+	$12$

Step 4

Multiply the new quotient term by the divisor.

				$x^{2}$
$6 x$	-	$5$		$6 x^{3}$	-	$47 x^{2}$	+	$17 x$	+	$12$
			+	$6 x^{3}$	-	$5 x^{2}$

Step 5

The expression needs to be subtracted from the dividend, so change all the signs in $6 x^{3} - 5 x^{2}$

				$x^{2}$
$6 x$	-	$5$		$6 x^{3}$	-	$47 x^{2}$	+	$17 x$	+	$12$
			-	$6 x^{3}$	+	$5 x^{2}$

Step 6

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$
$6 x$	-	$5$		$6 x^{3}$	-	$47 x^{2}$	+	$17 x$	+	$12$
			-	$6 x^{3}$	+	$5 x^{2}$
					-	$42 x^{2}$

Step 7

Pull the next terms from the original dividend down into the current dividend.

				$x^{2}$
$6 x$	-	$5$		$6 x^{3}$	-	$47 x^{2}$	+	$17 x$	+	$12$
			-	$6 x^{3}$	+	$5 x^{2}$
					-	$42 x^{2}$	+	$17 x$

Step 8

Divide the highest order term in the dividend $- 42 x^{2}$ by the highest order term in divisor $6 x$ .

				$x^{2}$	-	$7 x$
$6 x$	-	$5$		$6 x^{3}$	-	$47 x^{2}$	+	$17 x$	+	$12$
			-	$6 x^{3}$	+	$5 x^{2}$
					-	$42 x^{2}$	+	$17 x$

Step 9

Multiply the new quotient term by the divisor.

				$x^{2}$	-	$7 x$
$6 x$	-	$5$		$6 x^{3}$	-	$47 x^{2}$	+	$17 x$	+	$12$
			-	$6 x^{3}$	+	$5 x^{2}$
					-	$42 x^{2}$	+	$17 x$
					-	$42 x^{2}$	+	$35 x$

Step 10

The expression needs to be subtracted from the dividend, so change all the signs in $- 42 x^{2} + 35 x$

				$x^{2}$	-	$7 x$
$6 x$	-	$5$		$6 x^{3}$	-	$47 x^{2}$	+	$17 x$	+	$12$
			-	$6 x^{3}$	+	$5 x^{2}$
					-	$42 x^{2}$	+	$17 x$
					+	$42 x^{2}$	-	$35 x$

Step 11

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$	-	$7 x$
$6 x$	-	$5$		$6 x^{3}$	-	$47 x^{2}$	+	$17 x$	+	$12$
			-	$6 x^{3}$	+	$5 x^{2}$
					-	$42 x^{2}$	+	$17 x$
					+	$42 x^{2}$	-	$35 x$
							-	$18 x$

Step 12

Pull the next terms from the original dividend down into the current dividend.

				$x^{2}$	-	$7 x$
$6 x$	-	$5$		$6 x^{3}$	-	$47 x^{2}$	+	$17 x$	+	$12$
			-	$6 x^{3}$	+	$5 x^{2}$
					-	$42 x^{2}$	+	$17 x$
					+	$42 x^{2}$	-	$35 x$
							-	$18 x$	+	$12$

Step 13

Divide the highest order term in the dividend $- 18 x$ by the highest order term in divisor $6 x$ .

				$x^{2}$	-	$7 x$	-	$3$
$6 x$	-	$5$		$6 x^{3}$	-	$47 x^{2}$	+	$17 x$	+	$12$
			-	$6 x^{3}$	+	$5 x^{2}$
					-	$42 x^{2}$	+	$17 x$
					+	$42 x^{2}$	-	$35 x$
							-	$18 x$	+	$12$

Step 14

Multiply the new quotient term by the divisor.

				$x^{2}$	-	$7 x$	-	$3$
$6 x$	-	$5$		$6 x^{3}$	-	$47 x^{2}$	+	$17 x$	+	$12$
			-	$6 x^{3}$	+	$5 x^{2}$
					-	$42 x^{2}$	+	$17 x$
					+	$42 x^{2}$	-	$35 x$
							-	$18 x$	+	$12$
							-	$18 x$	+	$15$

Step 15

The expression needs to be subtracted from the dividend, so change all the signs in $- 18 x + 15$

				$x^{2}$	-	$7 x$	-	$3$
$6 x$	-	$5$		$6 x^{3}$	-	$47 x^{2}$	+	$17 x$	+	$12$
			-	$6 x^{3}$	+	$5 x^{2}$
					-	$42 x^{2}$	+	$17 x$
					+	$42 x^{2}$	-	$35 x$
							-	$18 x$	+	$12$
							+	$18 x$	-	$15$

Step 16

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$	-	$7 x$	-	$3$
$6 x$	-	$5$		$6 x^{3}$	-	$47 x^{2}$	+	$17 x$	+	$12$
			-	$6 x^{3}$	+	$5 x^{2}$
					-	$42 x^{2}$	+	$17 x$
					+	$42 x^{2}$	-	$35 x$
							-	$18 x$	+	$12$
							+	$18 x$	-	$15$
									-	$3$

Step 17

The final answer is the quotient plus the remainder over the divisor.

$x^{2} - 7 x - 3 - \frac{3}{6 x - 5}$