Algebra Examples

$y + 4 z = 2$ $- x + 2 y - 2 z = - 9$ $2 x - 4 y + z = 15$

Step 1

Subtract $4 z$ from both sides of the equation.

$y = 2 - 4 z$

$- x + 2 y - 2 z = - 9$

$2 x - 4 y + z = 15$

Step 2

Replace all occurrences of $y$ with $2 - 4 z$ in each equation.

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Step 2.1

Replace all occurrences of $y$ in $- x + 2 y - 2 z = - 9$ with $2 - 4 z$ .

$- x + 2 (2 - 4 z) - 2 z = - 9$

$y = 2 - 4 z$

$2 x - 4 y + z = 15$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify $- x + 2 (2 - 4 z) - 2 z$ .

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Step 2.2.1.1

Simplify each term.

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Step 2.2.1.1.1

Apply the distributive property.

$- x + 2 \cdot 2 + 2 (- 4 z) - 2 z = - 9$

$y = 2 - 4 z$

$2 x - 4 y + z = 15$

Step 2.2.1.1.2

Multiply $2$ by $2$ .

$- x + 4 + 2 (- 4 z) - 2 z = - 9$

$y = 2 - 4 z$

$2 x - 4 y + z = 15$

Step 2.2.1.1.3

Multiply $- 4$ by $2$ .

$- x + 4 - 8 z - 2 z = - 9$

$y = 2 - 4 z$

$2 x - 4 y + z = 15$

$- x + 4 - 8 z - 2 z = - 9$

$y = 2 - 4 z$

$2 x - 4 y + z = 15$

Step 2.2.1.2

Subtract $2 z$ from $- 8 z$ .

$- x + 4 - 10 z = - 9$

$y = 2 - 4 z$

$2 x - 4 y + z = 15$

$- x + 4 - 10 z = - 9$

$y = 2 - 4 z$

$2 x - 4 y + z = 15$

$- x + 4 - 10 z = - 9$

$y = 2 - 4 z$

$2 x - 4 y + z = 15$

Step 2.3

Replace all occurrences of $y$ in $2 x - 4 y + z = 15$ with $2 - 4 z$ .

$2 x - 4 (2 - 4 z) + z = 15$

$- x + 4 - 10 z = - 9$

$y = 2 - 4 z$

Step 2.4

Simplify the left side.

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Step 2.4.1

Simplify $2 x - 4 (2 - 4 z) + z$ .

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Step 2.4.1.1

Simplify each term.

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Step 2.4.1.1.1

Apply the distributive property.

$2 x - 4 \cdot 2 - 4 (- 4 z) + z = 15$

$- x + 4 - 10 z = - 9$

$y = 2 - 4 z$

Step 2.4.1.1.2

Multiply $- 4$ by $2$ .

$2 x - 8 - 4 (- 4 z) + z = 15$

$- x + 4 - 10 z = - 9$

$y = 2 - 4 z$

Step 2.4.1.1.3

Multiply $- 4$ by $- 4$ .

$2 x - 8 + 16 z + z = 15$

$- x + 4 - 10 z = - 9$

$y = 2 - 4 z$

$2 x - 8 + 16 z + z = 15$

$- x + 4 - 10 z = - 9$

$y = 2 - 4 z$

Step 2.4.1.2

Add $16 z$ and $z$ .

$2 x - 8 + 17 z = 15$

$- x + 4 - 10 z = - 9$

$y = 2 - 4 z$

$2 x - 8 + 17 z = 15$

$- x + 4 - 10 z = - 9$

$y = 2 - 4 z$

$2 x - 8 + 17 z = 15$

$- x + 4 - 10 z = - 9$

$y = 2 - 4 z$

$2 x - 8 + 17 z = 15$

$- x + 4 - 10 z = - 9$

$y = 2 - 4 z$

Step 3

Reorder $2$ and $- 4 z$ .

$y = - 4 z + 2$

$2 x - 8 + 17 z = 15$

$- x + 4 - 10 z = - 9$

Step 4

Solve for $x$ in $2 x - 8 + 17 z = 15$ .

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Step 4.1

Move all terms not containing $x$ to the right side of the equation.

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Step 4.1.1

Add $8$ to both sides of the equation.

$2 x + 17 z = 15 + 8$

$y = - 4 z + 2$

$- x + 4 - 10 z = - 9$

Step 4.1.2

Subtract $17 z$ from both sides of the equation.

$2 x = 15 + 8 - 17 z$

$y = - 4 z + 2$

$- x + 4 - 10 z = - 9$

Step 4.1.3

Add $15$ and $8$ .

$2 x = 23 - 17 z$

$y = - 4 z + 2$

$- x + 4 - 10 z = - 9$

$2 x = 23 - 17 z$

$y = - 4 z + 2$

$- x + 4 - 10 z = - 9$

Step 4.2

Divide each term in $2 x = 23 - 17 z$ by $2$ and simplify.

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Step 4.2.1

Divide each term in $2 x = 23 - 17 z$ by $2$ .

$\frac{2 x}{2} = \frac{23}{2} + \frac{- 17 z}{2}$

$y = - 4 z + 2$

$- x + 4 - 10 z = - 9$

Step 4.2.2

Simplify the left side.

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Step 4.2.2.1

Cancel the common factor of $2$ .

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Step 4.2.2.1.1

Cancel the common factor.

$\frac{2 x}{2} = \frac{23}{2} + \frac{- 17 z}{2}$

$y = - 4 z + 2$

$- x + 4 - 10 z = - 9$

Step 4.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{23}{2} + \frac{- 17 z}{2}$

$y = - 4 z + 2$

$- x + 4 - 10 z = - 9$

$x = \frac{23}{2} + \frac{- 17 z}{2}$

$y = - 4 z + 2$

$- x + 4 - 10 z = - 9$

$x = \frac{23}{2} + \frac{- 17 z}{2}$

$y = - 4 z + 2$

$- x + 4 - 10 z = - 9$

Step 4.2.3

Simplify the right side.

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Step 4.2.3.1

Move the negative in front of the fraction.

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$- x + 4 - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$- x + 4 - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$- x + 4 - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$- x + 4 - 10 z = - 9$

Step 5

Replace all occurrences of $x$ with $\frac{23}{2} - \frac{17 z}{2}$ in each equation.

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Step 5.1

Replace all occurrences of $x$ in $- x + 4 - 10 z = - 9$ with $\frac{23}{2} - \frac{17 z}{2}$ .

$- (\frac{23}{2} - \frac{17 z}{2}) + 4 - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2

Simplify the left side.

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Step 5.2.1

Simplify $- (\frac{23}{2} - \frac{17 z}{2}) + 4 - 10 z$ .

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Step 5.2.1.1

Simplify each term.

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Step 5.2.1.1.1

Apply the distributive property.

$- \frac{23}{2} + \frac{17 z}{2} + 4 - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.1.2

Multiply $- - \frac{17 z}{2}$ .

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Step 5.2.1.1.2.1

Multiply $- 1$ by $- 1$ .

$- \frac{23}{2} + 1 (\frac{17 z}{2}) + 4 - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.1.2.2

Multiply $\frac{17 z}{2}$ by $1$ .

$- \frac{23}{2} + \frac{17 z}{2} + 4 - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$- \frac{23}{2} + \frac{17 z}{2} + 4 - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$- \frac{23}{2} + \frac{17 z}{2} + 4 - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.2

To write $4$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{17 z}{2} - \frac{23}{2} + 4 \cdot \frac{2}{2} - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.3

Combine $4$ and $\frac{2}{2}$ .

$\frac{17 z}{2} - \frac{23}{2} + \frac{4 \cdot 2}{2} - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.4

Combine the numerators over the common denominator.

$\frac{17 z}{2} + \frac{- 23 + 4 \cdot 2}{2} - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.5

Simplify the numerator.

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Step 5.2.1.5.1

Multiply $4$ by $2$ .

$\frac{17 z}{2} + \frac{- 23 + 8}{2} - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.5.2

Add $- 23$ and $8$ .

$\frac{17 z}{2} + \frac{- 15}{2} - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$\frac{17 z}{2} + \frac{- 15}{2} - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.6

Move the negative in front of the fraction.

$\frac{17 z}{2} - \frac{15}{2} - 10 z = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.7

To write $- 10 z$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{17 z}{2} - 10 z \cdot \frac{2}{2} - \frac{15}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.8

Combine $- 10 z$ and $\frac{2}{2}$ .

$\frac{17 z}{2} + \frac{- 10 z \cdot 2}{2} - \frac{15}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.9

Combine the numerators over the common denominator.

$\frac{17 z - 10 z \cdot 2}{2} - \frac{15}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.10

Combine the numerators over the common denominator.

$\frac{17 z - 10 z \cdot 2 - 15}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.11

Multiply $2$ by $- 10$ .

$\frac{17 z - 20 z - 15}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.12

Subtract $20 z$ from $17 z$ .

$\frac{- 3 z - 15}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.13

Factor $3$ out of $- 3 z - 15$ .

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Step 5.2.1.13.1

Factor $3$ out of $- 3 z$ .

$\frac{3 (- z) - 15}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.13.2

Factor $3$ out of $- 15$ .

$\frac{3 (- z) + 3 (- 5)}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.13.3

Factor $3$ out of $3 (- z) + 3 (- 5)$ .

$\frac{3 (- z - 5)}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$\frac{3 (- z - 5)}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.14

Factor $- 1$ out of $- z$ .

$\frac{3 (- (z) - 5)}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.15

Rewrite $- 5$ as $- 1 (5)$ .

$\frac{3 (- (z) - 1 \cdot 5)}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.16

Factor $- 1$ out of $- (z) - 1 (5)$ .

$\frac{3 (- (z + 5))}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.17

Simplify the expression.

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Step 5.2.1.17.1

Rewrite $- (z + 5)$ as $- 1 (z + 5)$ .

$\frac{3 (- 1 (z + 5))}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 5.2.1.17.2

Move the negative in front of the fraction.

$- \frac{3 (z + 5)}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$- \frac{3 (z + 5)}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$- \frac{3 (z + 5)}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$- \frac{3 (z + 5)}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$- \frac{3 (z + 5)}{2} = - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6

Solve for $z$ in $- \frac{3 (z + 5)}{2} = - 9$ .

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Step 6.1

Multiply both sides of the equation by $- \frac{2}{3}$ .

$- \frac{2}{3} \cdot (- \frac{3 (z + 5)}{2}) = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2

Simplify both sides of the equation.

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Step 6.2.1

Simplify the left side.

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Step 6.2.1.1

Simplify $- \frac{2}{3} (- \frac{3 (z + 5)}{2})$ .

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Step 6.2.1.1.1

Cancel the common factor of $2$ .

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Step 6.2.1.1.1.1

Move the leading negative in $- \frac{2}{3}$ into the numerator.

$\frac{- 2}{3} \cdot (- \frac{3 (z + 5)}{2}) = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2.1.1.1.2

Move the leading negative in $- \frac{3 (z + 5)}{2}$ into the numerator.

$\frac{- 2}{3} \cdot \frac{- 3 (z + 5)}{2} = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2.1.1.1.3

Factor $2$ out of $- 2$ .

$\frac{2 (- 1)}{3} \cdot \frac{- 3 (z + 5)}{2} = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2.1.1.1.4

Cancel the common factor.

$\frac{2 \cdot - 1}{3} \cdot \frac{- 3 (z + 5)}{2} = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2.1.1.1.5

Rewrite the expression.

$\frac{- 1}{3} \cdot (- 3 (z + 5)) = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$\frac{- 1}{3} \cdot (- 3 (z + 5)) = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2.1.1.2

Cancel the common factor of $3$ .

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Step 6.2.1.1.2.1

Factor $3$ out of $- 3 (z + 5)$ .

$\frac{- 1}{3} \cdot (3 (- (z + 5))) = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2.1.1.2.2

Cancel the common factor.

$\frac{- 1}{3} \cdot (3 (- (z + 5))) = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2.1.1.2.3

Rewrite the expression.

$z + 5 = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$z + 5 = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2.1.1.3

Multiply.

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Step 6.2.1.1.3.1

Multiply $- 1$ by $- 1$ .

$1 (z + 5) = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2.1.1.3.2

Multiply $z + 5$ by $1$ .

$z + 5 = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$z + 5 = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$z + 5 = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$z + 5 = - \frac{2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2.2

Simplify the right side.

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Step 6.2.2.1

Simplify $- \frac{2}{3} \cdot - 9$ .

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Step 6.2.2.1.1

Cancel the common factor of $3$ .

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Step 6.2.2.1.1.1

Move the leading negative in $- \frac{2}{3}$ into the numerator.

$z + 5 = \frac{- 2}{3} \cdot - 9$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2.2.1.1.2

Factor $3$ out of $- 9$ .

$z + 5 = \frac{- 2}{3} \cdot (3 (- 3))$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2.2.1.1.3

Cancel the common factor.

$z + 5 = \frac{- 2}{3} \cdot (3 \cdot - 3)$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2.2.1.1.4

Rewrite the expression.

$z + 5 = - 2 \cdot - 3$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$z + 5 = - 2 \cdot - 3$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.2.2.1.2

Multiply $- 2$ by $- 3$ .

$z + 5 = 6$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$z + 5 = 6$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$z + 5 = 6$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$z + 5 = 6$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.3

Move all terms not containing $z$ to the right side of the equation.

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Step 6.3.1

Subtract $5$ from both sides of the equation.

$z = 6 - 5$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 6.3.2

Subtract $5$ from $6$ .

$z = 1$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$z = 1$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

$z = 1$

$x = \frac{23}{2} - \frac{17 z}{2}$

$y = - 4 z + 2$

Step 7

Replace all occurrences of $z$ with $1$ in each equation.

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Step 7.1

Replace all occurrences of $z$ in $x = \frac{23}{2} - \frac{17 z}{2}$ with $1$ .

$x = \frac{23}{2} - \frac{17 (1)}{2}$

$z = 1$

$y = - 4 z + 2$

Step 7.2

Simplify the right side.

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Step 7.2.1

Simplify $\frac{23}{2} - \frac{17 (1)}{2}$ .

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Step 7.2.1.1

Combine the numerators over the common denominator.

$x = \frac{23 - 17 \cdot 1}{2}$

$z = 1$

$y = - 4 z + 2$

Step 7.2.1.2

Simplify the expression.

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Step 7.2.1.2.1

Multiply $- 17$ by $1$ .

$x = \frac{23 - 17}{2}$

$z = 1$

$y = - 4 z + 2$

Step 7.2.1.2.2

Subtract $17$ from $23$ .

$x = \frac{6}{2}$

$z = 1$

$y = - 4 z + 2$

Step 7.2.1.2.3

Divide $6$ by $2$ .

$x = 3$

$z = 1$

$y = - 4 z + 2$

$x = 3$

$z = 1$

$y = - 4 z + 2$

$x = 3$

$z = 1$

$y = - 4 z + 2$

$x = 3$

$z = 1$

$y = - 4 z + 2$

Step 7.3

Replace all occurrences of $z$ in $y = - 4 z + 2$ with $1$ .

$y = - 4 \cdot 1 + 2$

$x = 3$

$z = 1$

Step 7.4

Simplify the right side.

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Step 7.4.1

Simplify $- 4 \cdot 1 + 2$ .

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Step 7.4.1.1

Multiply $- 4$ by $1$ .

$y = - 4 + 2$

$x = 3$

$z = 1$

Step 7.4.1.2

Add $- 4$ and $2$ .

$y = - 2$

$x = 3$

$z = 1$

$y = - 2$

$x = 3$

$z = 1$

$y = - 2$

$x = 3$

$z = 1$

$y = - 2$

$x = 3$

$z = 1$

Step 8

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(3, - 2, 1)$

Step 9

The result can be shown in multiple forms.

Point Form:

$(3, - 2, 1)$

Equation Form:

$x = 3, y = - 2, z = 1$