Algebra Examples

g (- 1) = \frac{- 1}{\sqrt{1 - {(- 1)}^{2}}}

$g (- 1) = \frac{- 1}{\sqrt{1 - {(- 1)}^{2}}}$

Step 1

Replace the variable

- 1

$- 1$ with

- 1

$- 1$ in the expression.

g (- 1) = \frac{- 1}{\sqrt{1 - {(- 1)}^{2}}}

$g (- 1) = \frac{- 1}{\sqrt{1 - {(- 1)}^{2}}}$

Step 2

Multiply

- 1

$- 1$ by

{(- 1)}^{2}

${(- 1)}^{2}$ by adding the exponents.

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Step 2.1

Multiply

- 1

$- 1$ by

{(- 1)}^{2}

${(- 1)}^{2}$ .

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Step 2.1.1

Raise

- 1

$- 1$ to the power of

1

$1$ .

g (- 1) = \frac{- 1}{\sqrt{1 + (- 1) {(- 1)}^{2}}}

$g (- 1) = \frac{- 1}{\sqrt{1 + (- 1) {(- 1)}^{2}}}$

Step 2.1.2

Use the power rule

a^{m} a^{n} = a^{m + n}

$a^{m} a^{n} = a^{m + n}$ to combine exponents.

g (- 1) = \frac{- 1}{\sqrt{1 + {(- 1)}^{1 + 2}}}

$g (- 1) = \frac{- 1}{\sqrt{1 + {(- 1)}^{1 + 2}}}$

g (- 1) = \frac{- 1}{\sqrt{1 + {(- 1)}^{1 + 2}}}

$g (- 1) = \frac{- 1}{\sqrt{1 + {(- 1)}^{1 + 2}}}$

Step 2.2

Add

1

$1$ and

2

$2$ .

g (- 1) = \frac{- 1}{\sqrt{1 + {(- 1)}^{3}}}

$g (- 1) = \frac{- 1}{\sqrt{1 + {(- 1)}^{3}}}$

g (- 1) = \frac{- 1}{\sqrt{1 + {(- 1)}^{3}}}

$g (- 1) = \frac{- 1}{\sqrt{1 + {(- 1)}^{3}}}$

Step 3

Raise

- 1

$- 1$ to the power of

3

$3$ .

g (- 1) = \frac{- 1}{\sqrt{1 - 1}}

$g (- 1) = \frac{- 1}{\sqrt{1 - 1}}$

Step 4

Subtract

1

$1$ from

1

$1$ .

g (- 1) = \frac{- 1}{\sqrt{0}}

$g (- 1) = \frac{- 1}{\sqrt{0}}$

Step 5

Rewrite

0

$0$ as

0^{2}

$0^{2}$ .

g (- 1) = \frac{- 1}{\sqrt{0^{2}}}

$g (- 1) = \frac{- 1}{\sqrt{0^{2}}}$

Step 6

Pull terms out from under the radical, assuming positive real numbers.

g (- 1) = \frac{- 1}{0}

$g (- 1) = \frac{- 1}{0}$

Step 7

The expression contains a division by

0

$0$ . The expression is undefined.

Undefined