Algebra Examples

$f (- 1) = 3 {(2)}^{x}$

Step 1

Divide each term in $f (- 1) = 3 \cdot 2^{x}$ by $- 1$ .

$\frac{f \cdot - 1}{- 1} = \frac{3 \cdot 2^{x}}{- 1}$

Step 2

Simplify the left side.

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Step 2.1

Move the negative one from the denominator of $\frac{f \cdot - 1}{- 1}$ .

$- 1 \cdot (f \cdot - 1) = \frac{3 \cdot 2^{x}}{- 1}$

Step 2.2

Rewrite $- 1 \cdot (f \cdot - 1)$ as $- (f \cdot - 1)$ .

$- (f \cdot - 1) = \frac{3 \cdot 2^{x}}{- 1}$

Step 2.3

Move $- 1$ to the left of $f$ .

$- (- 1 \cdot f) = \frac{3 \cdot 2^{x}}{- 1}$

Step 2.4

Rewrite $- 1 f$ as $- f$ .

$- - f = \frac{3 \cdot 2^{x}}{- 1}$

Step 2.5

Multiply $- - f$ .

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Step 2.5.1

Multiply $- 1$ by $- 1$ .

$1 f = \frac{3 \cdot 2^{x}}{- 1}$

Step 2.5.2

Multiply $f$ by $1$ .

$f = \frac{3 \cdot 2^{x}}{- 1}$

Step 3

Simplify the right side.

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Step 3.1

Move the negative one from the denominator of $\frac{3 \cdot 2^{x}}{- 1}$ .

$f = - 1 \cdot (3 \cdot 2^{x})$

Step 3.2

Rewrite $- 1 \cdot (3 \cdot 2^{x})$ as $- (3 \cdot 2^{x})$ .

$f = - (3 \cdot 2^{x})$

Step 3.3

Multiply $3$ by $- 1$ .

$f = - 3 \cdot 2^{x}$