Algebra Examples

$x \cdot 2 + 5 x - 24 = 0$

Step 1

Simplify the left side.

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Step 1.1

Simplify $x \cdot 2 + 5 x - 24$ .

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Step 1.1.1

Move $2$ to the left of $x$ .

$2 x + 5 x - 24 = 0$

Step 1.1.2

Add $2 x$ and $5 x$ .

$7 x - 24 = 0$

$7 x - 24 = 0$

$7 x - 24 = 0$

Step 2

Add $24$ to both sides of the equation.

$7 x = 24$

Step 3

Divide each term in $7 x = 24$ by $7$ and simplify.

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Step 3.1

Divide each term in $7 x = 24$ by $7$ .

$\frac{7 x}{7} = \frac{24}{7}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of $7$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{7 x}{7} = \frac{24}{7}$

Step 3.2.1.2

Divide $x$ by $1$ .

$x = \frac{24}{7}$

$x = \frac{24}{7}$

$x = \frac{24}{7}$

$x = \frac{24}{7}$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$