Algebra Examples

$\frac{\sqrt[4]{7 x - 5}}{2} = \sqrt[4]{x - 2}$

Step 1

Solve for $\sqrt[4]{7 x - 5}$ .

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Step 1.1

Multiply both sides of the equation by $2$ .

$2 \frac{\sqrt[4]{7 x - 5}}{2} = 2 \sqrt[4]{x - 2}$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of $2$ .

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Step 1.2.1.1

Cancel the common factor.

$2 \frac{\sqrt[4]{7 x - 5}}{2} = 2 \sqrt[4]{x - 2}$

Step 1.2.1.2

Rewrite the expression.

$\sqrt[4]{7 x - 5} = 2 \sqrt[4]{x - 2}$

Step 2

To remove the radical on the left side of the equation, raise both sides of the equation to the power of $4$ .

${\sqrt[4]{7 x - 5}}^{4} = {(2 \sqrt[4]{x - 2})}^{4}$

Step 3

Simplify each side of the equation.

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Step 3.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[4]{7 x - 5}$ as ${(7 x - 5)}^{\frac{1}{4}}$ .

${({(7 x - 5)}^{\frac{1}{4}})}^{4} = {(2 \sqrt[4]{x - 2})}^{4}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Simplify ${({(7 x - 5)}^{\frac{1}{4}})}^{4}$ .

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Step 3.2.1.1

Multiply the exponents in ${({(7 x - 5)}^{\frac{1}{4}})}^{4}$ .

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Step 3.2.1.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(7 x - 5)}^{\frac{1}{4} \cdot 4} = {(2 \sqrt[4]{x - 2})}^{4}$

Step 3.2.1.1.2

Cancel the common factor of $4$ .

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Step 3.2.1.1.2.1

Cancel the common factor.

${(7 x - 5)}^{\frac{1}{4} \cdot 4} = {(2 \sqrt[4]{x - 2})}^{4}$

Step 3.2.1.1.2.2

Rewrite the expression.

${(7 x - 5)}^{1} = {(2 \sqrt[4]{x - 2})}^{4}$

Step 3.2.1.2

Simplify.

$7 x - 5 = {(2 \sqrt[4]{x - 2})}^{4}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Simplify ${(2 \sqrt[4]{x - 2})}^{4}$ .

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Step 3.3.1.1

Simplify the expression.

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Step 3.3.1.1.1

Apply the product rule to $2 \sqrt[4]{x - 2}$ .

$7 x - 5 = 2^{4} {\sqrt[4]{x - 2}}^{4}$

Step 3.3.1.1.2

Raise $2$ to the power of $4$ .

$7 x - 5 = 16 {\sqrt[4]{x - 2}}^{4}$

Step 3.3.1.2

Rewrite ${\sqrt[4]{x - 2}}^{4}$ as $x - 2$ .

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Step 3.3.1.2.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[4]{x - 2}$ as ${(x - 2)}^{\frac{1}{4}}$ .

$7 x - 5 = 16 {({(x - 2)}^{\frac{1}{4}})}^{4}$

Step 3.3.1.2.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$7 x - 5 = 16 {(x - 2)}^{\frac{1}{4} \cdot 4}$

Step 3.3.1.2.3

Combine $\frac{1}{4}$ and $4$ .

$7 x - 5 = 16 {(x - 2)}^{\frac{4}{4}}$

Step 3.3.1.2.4

Cancel the common factor of $4$ .

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Step 3.3.1.2.4.1

Cancel the common factor.

$7 x - 5 = 16 {(x - 2)}^{\frac{4}{4}}$

Step 3.3.1.2.4.2

Rewrite the expression.

$7 x - 5 = 16 {(x - 2)}^{1}$

Step 3.3.1.2.5

Simplify.

$7 x - 5 = 16 (x - 2)$

Step 3.3.1.3

Apply the distributive property.

$7 x - 5 = 16 x + 16 \cdot - 2$

Step 3.3.1.4

Multiply $16$ by $- 2$ .

$7 x - 5 = 16 x - 32$

Step 4

Solve for $x$ .

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Step 4.1

Move all terms containing $x$ to the left side of the equation.

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Step 4.1.1

Subtract $16 x$ from both sides of the equation.

$7 x - 5 - 16 x = - 32$

Step 4.1.2

Subtract $16 x$ from $7 x$ .

$- 9 x - 5 = - 32$

Step 4.2

Move all terms not containing $x$ to the right side of the equation.

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Step 4.2.1

Add $5$ to both sides of the equation.

$- 9 x = - 32 + 5$

Step 4.2.2

Add $- 32$ and $5$ .

$- 9 x = - 27$

Step 4.3

Divide each term in $- 9 x = - 27$ by $- 9$ and simplify.

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Step 4.3.1

Divide each term in $- 9 x = - 27$ by $- 9$ .

$\frac{- 9 x}{- 9} = \frac{- 27}{- 9}$

Step 4.3.2

Simplify the left side.

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Step 4.3.2.1

Cancel the common factor of $- 9$ .

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Step 4.3.2.1.1

Cancel the common factor.

$\frac{- 9 x}{- 9} = \frac{- 27}{- 9}$

Step 4.3.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 27}{- 9}$

Step 4.3.3

Simplify the right side.

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Step 4.3.3.1

Divide $- 27$ by $- 9$ .

$x = 3$