Algebra Examples

$(2 x^{3} - 5 x^{2} + 14) \div (x^{2} - x - 2)$

Step 1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x^{2}$

$x$

$2$

$2 x^{3}$

$5 x^{2}$

$0 x$

$14$

Step 2

Divide the highest order term in the dividend $2 x^{3}$ by the highest order term in divisor $x^{2}$ .

$2 x$

$x^{2}$

$x$

$2$

$2 x^{3}$

$5 x^{2}$

$0 x$

$14$

Step 3

Multiply the new quotient term by the divisor.

$2 x$

$x^{2}$

$x$

$2$

$2 x^{3}$

$5 x^{2}$

$0 x$

$14$

$2 x^{3}$

$2 x^{2}$

$4 x$

Step 4

The expression needs to be subtracted from the dividend, so change all the signs in $2 x^{3} - 2 x^{2} - 4 x$

$2 x$

$x^{2}$

$x$

$2$

$2 x^{3}$

$5 x^{2}$

$0 x$

$14$

$2 x^{3}$

$2 x^{2}$

$4 x$

Step 5

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$2 x$

$x^{2}$

$x$

$2$

$2 x^{3}$

$5 x^{2}$

$0 x$

$14$

$2 x^{3}$

$2 x^{2}$

$4 x$

$3 x^{2}$

$4 x$

Step 6

Pull the next terms from the original dividend down into the current dividend.

$2 x$

$x^{2}$

$x$

$2$

$2 x^{3}$

$5 x^{2}$

$0 x$

$14$

$2 x^{3}$

$2 x^{2}$

$4 x$

$3 x^{2}$

$4 x$

$14$

Step 7

Divide the highest order term in the dividend $- 3 x^{2}$ by the highest order term in divisor $x^{2}$ .

$2 x$

$3$

$x^{2}$

$x$

$2$

$2 x^{3}$

$5 x^{2}$

$0 x$

$14$

$2 x^{3}$

$2 x^{2}$

$4 x$

$3 x^{2}$

$4 x$

$14$

Step 8

Multiply the new quotient term by the divisor.

$2 x$

$3$

$x^{2}$

$x$

$2$

$2 x^{3}$

$5 x^{2}$

$0 x$

$14$

$2 x^{3}$

$2 x^{2}$

$4 x$

$3 x^{2}$

$4 x$

$14$

$3 x^{2}$

$3 x$

$6$

Step 9

The expression needs to be subtracted from the dividend, so change all the signs in $- 3 x^{2} + 3 x + 6$

$2 x$

$3$

$x^{2}$

$x$

$2$

$2 x^{3}$

$5 x^{2}$

$0 x$

$14$

$2 x^{3}$

$2 x^{2}$

$4 x$

$3 x^{2}$

$4 x$

$14$

$3 x^{2}$

$3 x$

$6$

Step 10

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$2 x$

$3$

$x^{2}$

$x$

$2$

$2 x^{3}$

$5 x^{2}$

$0 x$

$14$

$2 x^{3}$

$2 x^{2}$

$4 x$

$3 x^{2}$

$4 x$

$14$

$3 x^{2}$

$3 x$

$6$

$x$

$8$

Step 11

The final answer is the quotient plus the remainder over the divisor.

$2 x - 3 + \frac{x + 8}{x^{2} - x - 2}$