Algebra Examples

f (x) = x^{3} - x^{2} + 10

$f (x) = x^{3} - x^{2} + 10$

g (x) = 3 x^{2} + 2 x - 10

$g (x) = 3 x^{2} + 2 x - 10$

h (x) = 2 x^{3} + 2 x^{2} - 3 x

$h (x) = 2 x^{3} + 2 x^{2} - 3 x$

Step 1

Set up the composite result function.

f (g (h (x)))

$f (g (h (x)))$

Step 2

Evaluate

f (g (2 x^{3} + 2 x^{2} - 3 x))

$f (g (2 x^{3} + 2 x^{2} - 3 x))$ by substituting in the value of

h

$h$ into

g

$g$ .

f (g (2 x^{3} + 2 x^{2} - 3 x)) = f (3 {(2 x^{3} + 2 x^{2} - 3 x)}^{2} + 2 (2 x^{3} + 2 x^{2} - 3 x) - 10)

$f (g (2 x^{3} + 2 x^{2} - 3 x)) = f (3 {(2 x^{3} + 2 x^{2} - 3 x)}^{2} + 2 (2 x^{3} + 2 x^{2} - 3 x) - 10)$

Step 3

Evaluate

f (3 {(2 x^{3} + 2 x^{2} - 3 x)}^{2} + 2 (2 x^{3} + 2 x^{2} - 3 x) - 10)

$f (3 {(2 x^{3} + 2 x^{2} - 3 x)}^{2} + 2 (2 x^{3} + 2 x^{2} - 3 x) - 10)$ by substituting in the value of

g

$g$ into

f

$f$ .

f (3 {(2 x^{3} + 2 x^{2} - 3 x)}^{2} + 2 (2 x^{3} + 2 x^{2} - 3 x) - 10) = {(3 {(2 x^{3} + 2 x^{2} - 3 x)}^{2} + 2 (2 x^{3} + 2 x^{2} - 3 x) - 10)}^{3} - {(3 {(2 x^{3} + 2 x^{2} - 3 x)}^{2} + 2 (2 x^{3} + 2 x^{2} - 3 x) - 10)}^{2} + 10

$f (3 {(2 x^{3} + 2 x^{2} - 3 x)}^{2} + 2 (2 x^{3} + 2 x^{2} - 3 x) - 10) = {(3 {(2 x^{3} + 2 x^{2} - 3 x)}^{2} + 2 (2 x^{3} + 2 x^{2} - 3 x) - 10)}^{3} - {(3 {(2 x^{3} + 2 x^{2} - 3 x)}^{2} + 2 (2 x^{3} + 2 x^{2} - 3 x) - 10)}^{2} + 10$

Step 4

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

(- \infty, \infty)

$(- \infty, \infty)$

Set-Builder Notation:

${x | x \in ℝ}$

Step 5