Algebra Examples

\sqrt[3]{\frac{6}{7}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}

$\sqrt[3]{\frac{6}{7}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1

Move all terms to the left side of the equation and simplify.

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Step 1.1

Simplify the left side.

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Step 1.1.1

Simplify

\sqrt[3]{\frac{6}{7}}

$\sqrt[3]{\frac{6}{7}}$ .

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Step 1.1.1.1

Rewrite

\sqrt[3]{\frac{6}{7}}

$\sqrt[3]{\frac{6}{7}}$ as

\frac{\sqrt[3]{6}}{\sqrt[3]{7}}

$\frac{\sqrt[3]{6}}{\sqrt[3]{7}}$ .

\frac{\sqrt[3]{6}}{\sqrt[3]{7}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}

$\frac{\sqrt[3]{6}}{\sqrt[3]{7}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.2

Multiply

\frac{\sqrt[3]{6}}{\sqrt[3]{7}}

$\frac{\sqrt[3]{6}}{\sqrt[3]{7}}$ by

\frac{{\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{2}}

$\frac{{\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{2}}$ .

\frac{\sqrt[3]{6}}{\sqrt[3]{7}} \cdot \frac{{\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{2}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}

$\frac{\sqrt[3]{6}}{\sqrt[3]{7}} \cdot \frac{{\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{2}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.3

Combine and simplify the denominator.

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Step 1.1.1.3.1

Multiply

\frac{\sqrt[3]{6}}{\sqrt[3]{7}}

$\frac{\sqrt[3]{6}}{\sqrt[3]{7}}$ by

\frac{{\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{2}}

$\frac{{\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{2}}$ .

\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{\sqrt[3]{7} {\sqrt[3]{7}}^{2}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}

$\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{\sqrt[3]{7} {\sqrt[3]{7}}^{2}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.3.2

Raise

\sqrt[3]{7}

$\sqrt[3]{7}$ to the power of

1

$1$ .

\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{1} {\sqrt[3]{7}}^{2}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}

$\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{1} {\sqrt[3]{7}}^{2}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.3.3

Use the power rule

a^{m} a^{n} = a^{m + n}

$a^{m} a^{n} = a^{m + n}$ to combine exponents.

\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{1 + 2}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}

$\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{1 + 2}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.3.4

Add

1

$1$ and

2

$2$ .

\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{3}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}

$\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{3}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.3.5

Rewrite

{\sqrt[3]{7}}^{3}

${\sqrt[3]{7}}^{3}$ as

7

$7$ .

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Step 1.1.1.3.5.1

Use

\sqrt[n]{a^{x}} = a^{\frac{x}{n}}

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite

\sqrt[3]{7}

$\sqrt[3]{7}$ as

7^{\frac{1}{3}}

$7^{\frac{1}{3}}$ .

\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{{(7^{\frac{1}{3}})}^{3}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}

$\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{{(7^{\frac{1}{3}})}^{3}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.3.5.2

Apply the power rule and multiply exponents,

{(a^{m})}^{n} = a^{m n}

${(a^{m})}^{n} = a^{m n}$ .

\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{7^{\frac{1}{3} \cdot 3}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}

$\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{7^{\frac{1}{3} \cdot 3}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.3.5.3

Combine

$\frac{1}{3}$ and

$3$ .

$\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{7^{\frac{3}{3}}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.3.5.4

Cancel the common factor of

$3$ .

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Step 1.1.1.3.5.4.1

Cancel the common factor.

$\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{7^{\frac{3}{3}}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.3.5.4.2

Rewrite the expression.

$\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{7^{1}} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.3.5.5

Evaluate the exponent.

$\frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{7} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.4

Simplify the numerator.

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Step 1.1.1.4.1

Rewrite

${\sqrt[3]{7}}^{2}$ as

$\sqrt[3]{7^{2}}$ .

$\frac{\sqrt[3]{6} \sqrt[3]{7^{2}}}{7} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.4.2

Raise

$7$ to the power of

$2$ .

$\frac{\sqrt[3]{6} \sqrt[3]{49}}{7} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.5

Simplify the numerator.

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Step 1.1.1.5.1

Combine using the product rule for radicals.

$\frac{\sqrt[3]{6 \cdot 49}}{7} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.1.1.5.2

Multiply

$6$ by

$49$ .

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}}$

Step 1.2

Simplify the right side.

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Step 1.2.1

Simplify

$\frac{\sqrt[3]{6}}{\sqrt[3]{7}}$ .

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Step 1.2.1.1

Multiply

$\frac{\sqrt[3]{6}}{\sqrt[3]{7}}$ by

$\frac{{\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{2}}$ .

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6}}{\sqrt[3]{7}} \cdot \frac{{\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{2}}$

Step 1.2.1.2

Combine and simplify the denominator.

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Step 1.2.1.2.1

Multiply

$\frac{\sqrt[3]{6}}{\sqrt[3]{7}}$ by

$\frac{{\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{2}}$ .

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{\sqrt[3]{7} {\sqrt[3]{7}}^{2}}$

Step 1.2.1.2.2

Raise

$\sqrt[3]{7}$ to the power of

$1$ .

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{1} {\sqrt[3]{7}}^{2}}$

Step 1.2.1.2.3

Use the power rule

$a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{1 + 2}}$

Step 1.2.1.2.4

Add

$1$ and

$2$ .

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{{\sqrt[3]{7}}^{3}}$

Step 1.2.1.2.5

Rewrite

${\sqrt[3]{7}}^{3}$ as

$7$ .

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Step 1.2.1.2.5.1

Use

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite

$\sqrt[3]{7}$ as

$7^{\frac{1}{3}}$ .

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{{(7^{\frac{1}{3}})}^{3}}$

Step 1.2.1.2.5.2

Apply the power rule and multiply exponents,

${(a^{m})}^{n} = a^{m n}$ .

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{7^{\frac{1}{3} \cdot 3}}$

Step 1.2.1.2.5.3

Combine

$\frac{1}{3}$ and

$3$ .

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{7^{\frac{3}{3}}}$

Step 1.2.1.2.5.4

Cancel the common factor of

$3$ .

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Step 1.2.1.2.5.4.1

Cancel the common factor.

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{7^{\frac{3}{3}}}$

Step 1.2.1.2.5.4.2

Rewrite the expression.

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{7^{1}}$

Step 1.2.1.2.5.5

Evaluate the exponent.

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6} {\sqrt[3]{7}}^{2}}{7}$

Step 1.2.1.3

Simplify the numerator.

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Step 1.2.1.3.1

Rewrite

${\sqrt[3]{7}}^{2}$ as

$\sqrt[3]{7^{2}}$ .

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6} \sqrt[3]{7^{2}}}{7}$

Step 1.2.1.3.2

Raise

$7$ to the power of

$2$ .

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6} \sqrt[3]{49}}{7}$

Step 1.2.1.4

Simplify the numerator.

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Step 1.2.1.4.1

Combine using the product rule for radicals.

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{6 \cdot 49}}{7}$

Step 1.2.1.4.2

Multiply

$6$ by

$49$ .

$\frac{\sqrt[3]{294}}{7} = \frac{\sqrt[3]{294}}{7}$

Step 1.3

Subtract

$\frac{\sqrt[3]{294}}{7}$ from both sides of the equation.

$\frac{\sqrt[3]{294}}{7} - \frac{\sqrt[3]{294}}{7} = 0$

Step 1.4

Simplify

$\frac{\sqrt[3]{294}}{7} - \frac{\sqrt[3]{294}}{7}$ .

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Step 1.4.1

Combine the numerators over the common denominator.

$\frac{\sqrt[3]{294} - \sqrt[3]{294}}{7} = 0$

Step 1.4.2

Subtract

$\sqrt[3]{294}$ from

$\sqrt[3]{294}$ .

$\frac{0}{7} = 0$

Step 1.4.3

Divide

$0$ by

$7$ .

$0 = 0$

Step 2

Since

$0 = 0$ , the equation will always be true.

Always true