Algebra Examples

$\frac{\sqrt{- 1}}{(3 + 8 i) - (2 + 5 i)}$

Step 1

Rewrite $\sqrt{- 1}$ as $i$ .

$\frac{i}{(3 + 8 i) - (2 + 5 i)}$

Step 2

Simplify the denominator.

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Step 2.1

Apply the distributive property.

$\frac{i}{3 + 8 i - 1 \cdot 2 - (5 i)}$

Step 2.2

Multiply $- 1$ by $2$ .

$\frac{i}{3 + 8 i - 2 - (5 i)}$

Step 2.3

Multiply $5$ by $- 1$ .

$\frac{i}{3 + 8 i - 2 - 5 i}$

Step 2.4

Subtract $2$ from $3$ .

$\frac{i}{1 + 8 i - 5 i}$

Step 2.5

Subtract $5 i$ from $8 i$ .

$\frac{i}{1 + 3 i}$

Step 3

Multiply the numerator and denominator of $\frac{i}{1 + 3 i}$ by the conjugate of $1 + 3 i$ to make the denominator real.

$\frac{i}{1 + 3 i} \cdot \frac{1 - 3 i}{1 - 3 i}$

Step 4

Multiply.

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Step 4.1

Combine.

$\frac{i (1 - 3 i)}{(1 + 3 i) (1 - 3 i)}$

Step 4.2

Simplify the numerator.

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Step 4.2.1

Apply the distributive property.

$\frac{i \cdot 1 + i (- 3 i)}{(1 + 3 i) (1 - 3 i)}$

Step 4.2.2

Multiply $i$ by $1$ .

$\frac{i + i (- 3 i)}{(1 + 3 i) (1 - 3 i)}$

Step 4.2.3

Multiply $i (- 3 i)$ .

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Step 4.2.3.1

Raise $i$ to the power of $1$ .

$\frac{i - 3 (i^{1} i)}{(1 + 3 i) (1 - 3 i)}$

Step 4.2.3.2

Raise $i$ to the power of $1$ .

$\frac{i - 3 (i^{1} i^{1})}{(1 + 3 i) (1 - 3 i)}$

Step 4.2.3.3

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{i - 3 i^{1 + 1}}{(1 + 3 i) (1 - 3 i)}$

Step 4.2.3.4

Add $1$ and $1$ .

$\frac{i - 3 i^{2}}{(1 + 3 i) (1 - 3 i)}$

Step 4.2.4

Simplify each term.

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Step 4.2.4.1

Rewrite $i^{2}$ as $- 1$ .

$\frac{i - 3 \cdot - 1}{(1 + 3 i) (1 - 3 i)}$

Step 4.2.4.2

Multiply $- 3$ by $- 1$ .

$\frac{i + 3}{(1 + 3 i) (1 - 3 i)}$

Step 4.2.5

Reorder $i$ and $3$ .

$\frac{3 + i}{(1 + 3 i) (1 - 3 i)}$

Step 4.3

Simplify the denominator.

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Step 4.3.1

Expand $(1 + 3 i) (1 - 3 i)$ using the FOIL Method.

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Step 4.3.1.1

Apply the distributive property.

$\frac{3 + i}{1 (1 - 3 i) + 3 i (1 - 3 i)}$

Step 4.3.1.2

Apply the distributive property.

$\frac{3 + i}{1 \cdot 1 + 1 (- 3 i) + 3 i (1 - 3 i)}$

Step 4.3.1.3

Apply the distributive property.

$\frac{3 + i}{1 \cdot 1 + 1 (- 3 i) + 3 i \cdot 1 + 3 i (- 3 i)}$

Step 4.3.2

Simplify.

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Step 4.3.2.1

Multiply $1$ by $1$ .

$\frac{3 + i}{1 + 1 (- 3 i) + 3 i \cdot 1 + 3 i (- 3 i)}$

Step 4.3.2.2

Multiply $- 3$ by $1$ .

$\frac{3 + i}{1 - 3 i + 3 i \cdot 1 + 3 i (- 3 i)}$

Step 4.3.2.3

Multiply $3$ by $1$ .

$\frac{3 + i}{1 - 3 i + 3 i + 3 i (- 3 i)}$

Step 4.3.2.4

Multiply $- 3$ by $3$ .

$\frac{3 + i}{1 - 3 i + 3 i - 9 i i}$

Step 4.3.2.5

Raise $i$ to the power of $1$ .

$\frac{3 + i}{1 - 3 i + 3 i - 9 (i^{1} i)}$

Step 4.3.2.6

Raise $i$ to the power of $1$ .

$\frac{3 + i}{1 - 3 i + 3 i - 9 (i^{1} i^{1})}$

Step 4.3.2.7

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{3 + i}{1 - 3 i + 3 i - 9 i^{1 + 1}}$

Step 4.3.2.8

Add $1$ and $1$ .

$\frac{3 + i}{1 - 3 i + 3 i - 9 i^{2}}$

Step 4.3.2.9

Add $- 3 i$ and $3 i$ .

$\frac{3 + i}{1 + 0 - 9 i^{2}}$

Step 4.3.2.10

Add $1$ and $0$ .

$\frac{3 + i}{1 - 9 i^{2}}$

Step 4.3.3

Simplify each term.

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Step 4.3.3.1

Rewrite $i^{2}$ as $- 1$ .

$\frac{3 + i}{1 - 9 \cdot - 1}$

Step 4.3.3.2

Multiply $- 9$ by $- 1$ .

$\frac{3 + i}{1 + 9}$

Step 4.3.4

Add $1$ and $9$ .

$\frac{3 + i}{10}$

Step 5

Split the fraction $\frac{3 + i}{10}$ into two fractions.

$\frac{3}{10} + \frac{i}{10}$