Algebra Examples

Graph y<=2x-4 2y-x>=2
y2x-4y2x4 2y-x22yx2
Step 1
Graph y2x-4y2x4.
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Step 1.1
Use the slope-intercept form to find the slope and y-intercept.
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Step 1.1.1
The slope-intercept form is y=mx+by=mx+b, where mm is the slope and bb is the y-intercept.
y=mx+by=mx+b
Step 1.1.2
Find the values of mm and bb using the form y=mx+by=mx+b.
m=2m=2
b=-4b=4
Step 1.1.3
The slope of the line is the value of mm, and the y-intercept is the value of bb.
Slope: 22
y-intercept: (0,-4)(0,4)
Slope: 22
y-intercept: (0,-4)(0,4)
Step 1.2
Graph a solid line, then shade the area below the boundary line since yy is less than 2x-42x4.
y2x-4y2x4
y2x-4y2x4
Step 2
Graph 2y-x22yx2.
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Step 2.1
Write in y=mx+by=mx+b form.
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Step 2.1.1
Solve for yy.
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Step 2.1.1.1
Add xx to both sides of the inequality.
2y2+x2y2+x
Step 2.1.1.2
Divide each term in 2y2+x2y2+x by 22 and simplify.
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Step 2.1.1.2.1
Divide each term in 2y2+x2y2+x by 22.
2y222+x22y222+x2
Step 2.1.1.2.2
Simplify the left side.
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Step 2.1.1.2.2.1
Cancel the common factor of 22.
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Step 2.1.1.2.2.1.1
Cancel the common factor.
2y222+x2
Step 2.1.1.2.2.1.2
Divide y by 1.
y22+x2
y22+x2
y22+x2
Step 2.1.1.2.3
Simplify the right side.
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Step 2.1.1.2.3.1
Divide 2 by 2.
y1+x2
y1+x2
y1+x2
y1+x2
Step 2.1.2
Rearrange terms.
yx2+1
Step 2.1.3
Reorder terms.
y12x+1
y12x+1
Step 2.2
Use the slope-intercept form to find the slope and y-intercept.
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Step 2.2.1
Find the values of m and b using the form y=mx+b.
m=12
b=1
Step 2.2.2
The slope of the line is the value of m, and the y-intercept is the value of b.
Slope: 12
y-intercept: (0,1)
Slope: 12
y-intercept: (0,1)
Step 2.3
Graph a solid line, then shade the area above the boundary line since y is greater than 12x+1.
y12x+1
y12x+1
Step 3
Plot each graph on the same coordinate system.
y2x-4
2y-x2
Step 4
 [x2  12  π  xdx ]