Enter a problem...
Algebra Examples
x2+3x-282x3÷x2-7x+12x-3
Step 1
To divide by a fraction, multiply by its reciprocal.
x2+3x-282x3⋅x-3x2-7x+12
Step 2
Step 2.1
Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -28 and whose sum is 3.
-4,7
Step 2.2
Write the factored form using these integers.
(x-4)(x+7)2x3⋅x-3x2-7x+12
(x-4)(x+7)2x3⋅x-3x2-7x+12
Step 3
Step 3.1
Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 12 and whose sum is -7.
-4,-3
Step 3.2
Write the factored form using these integers.
(x-4)(x+7)2x3⋅x-3(x-4)(x-3)
(x-4)(x+7)2x3⋅x-3(x-4)(x-3)
Step 4
Step 4.1
Cancel the common factor.
(x-4)(x+7)2x3⋅x-3(x-4)(x-3)
Step 4.2
Rewrite the expression.
x+72x3⋅x-3x-3
x+72x3⋅x-3x-3
Step 5
Multiply x+72x3 by x-3x-3.
(x+7)(x-3)2x3(x-3)
Step 6
Step 6.1
Cancel the common factor.
(x+7)(x-3)2x3(x-3)
Step 6.2
Rewrite the expression.
x+72x3
x+72x3
Step 7
Split the fraction x+72x3 into two fractions.
x2x3+72x3
Step 8
Step 8.1
Raise x to the power of 1.
x12x3+72x3
Step 8.2
Factor x out of x1.
x⋅12x3+72x3
Step 8.3
Cancel the common factors.
Step 8.3.1
Factor x out of 2x3.
x⋅1x(2x2)+72x3
Step 8.3.2
Cancel the common factor.
x⋅1x(2x2)+72x3
Step 8.3.3
Rewrite the expression.
12x2+72x3
12x2+72x3
12x2+72x3