Algebra Examples

$5 (c - b x) = 10$

Step 1

Divide each term in $5 (c - b x) = 10$ by $5$ and simplify.

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Step 1.1

Divide each term in $5 (c - b x) = 10$ by $5$ .

$\frac{5 (c - b x)}{5} = \frac{10}{5}$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of $5$ .

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Step 1.2.1.1

Cancel the common factor.

$\frac{5 (c - b x)}{5} = \frac{10}{5}$

Step 1.2.1.2

Divide $c - b x$ by $1$ .

$c - b x = \frac{10}{5}$

Step 1.3

Simplify the right side.

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Step 1.3.1

Divide $10$ by $5$ .

$c - b x = 2$

Step 2

Subtract $c$ from both sides of the equation.

$- b x = 2 - c$

Step 3

Divide each term in $- b x = 2 - c$ by $- b$ and simplify.

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Step 3.1

Divide each term in $- b x = 2 - c$ by $- b$ .

$\frac{- b x}{- b} = \frac{2}{- b} + \frac{- c}{- b}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Dividing two negative values results in a positive value.

$\frac{b x}{b} = \frac{2}{- b} + \frac{- c}{- b}$

Step 3.2.2

Cancel the common factor of $b$ .

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Step 3.2.2.1

Cancel the common factor.

$\frac{b x}{b} = \frac{2}{- b} + \frac{- c}{- b}$

Step 3.2.2.2

Divide $x$ by $1$ .

$x = \frac{2}{- b} + \frac{- c}{- b}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Simplify each term.

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Step 3.3.1.1

Move the negative in front of the fraction.

$x = - \frac{2}{b} + \frac{- c}{- b}$

Step 3.3.1.2

Dividing two negative values results in a positive value.

$x = - \frac{2}{b} + \frac{c}{b}$