Algebra Examples

$23 y + 50 + 27 y = 50 y + 50$

Step 1

Add $23 y$ and $27 y$ .

$50 y + 50 = 50 y + 50$

Step 2

Move all terms containing $y$ to the left side of the equation.

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Step 2.1

Subtract $50 y$ from both sides of the equation.

$50 y + 50 - 50 y = 50$

Step 2.2

Combine the opposite terms in $50 y + 50 - 50 y$ .

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Step 2.2.1

Subtract $50 y$ from $50 y$ .

$0 + 50 = 50$

Step 2.2.2

Add $0$ and $50$ .

$50 = 50$

Step 3

Since $50 = 50$ , the equation will always be true.

Always true

Step 4

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$