Algebra Examples

$\tan (θ) = \frac{4}{3}$

Step 1

Take the inverse tangent of both sides of the equation to extract $θ$ from inside the tangent.

$θ = \arctan (\frac{4}{3})$

Step 2

Simplify the right side.

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Step 2.1

Evaluate $\arctan (\frac{4}{3})$ .

$θ = 0.92729521$

Step 3

The tangent function is positive in the first and third quadrants. To find the second solution, add the reference angle from $π$ to find the solution in the fourth quadrant.

$θ = (3.14159265) + 0.92729521$

Step 4

Solve for $θ$ .

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Step 4.1

Remove parentheses.

$θ = 3.14159265 + 0.92729521$

Step 4.2

Remove parentheses.

$θ = (3.14159265) + 0.92729521$

Step 4.3

Add $3.14159265$ and $0.92729521$ .

$θ = 4.06888787$

Step 5

Find the period of $\tan (θ)$ .

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Step 5.1

The period of the function can be calculated using $\frac{π}{| b |}$ .

$\frac{π}{| b |}$

Step 5.2

Replace $b$ with $1$ in the formula for period.

$\frac{π}{| 1 |}$

Step 5.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{π}{1}$

Step 5.4

Divide $π$ by $1$ .

$π$

Step 6

The period of the $\tan (θ)$ function is $π$ so values will repeat every $π$ radians in both directions.

$θ = 0.92729521 + π n, 4.06888787 + π n$ , for any integer $n$

Step 7

Consolidate $0.92729521 + π n$ and $4.06888787 + π n$ to $0.92729521 + π n$ .

$θ = 0.92729521 + π n$ , for any integer $n$

Step 8

The result can be shown in multiple forms.

Exact Form:

$\tan (θ) = \frac{4}{3}$

Decimal Form:

$\tan (θ) = 1.\overline{3}$

Mixed Number Form:

$\tan (θ) = 1 \frac{1}{3}$