Algebra Examples

Graph y>=2x^2-4 y<-0.5x-1 y<3x+2
y2x2-4 y<-0.5x-1 y<3x+2
Step 1
Graph y2x2-4.
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Step 1.1
The equation is not linear, so a constant slope does not exist.
Not Linear
Step 1.2
Graph a solid line, then shade the area above the boundary line since y is greater than 2x2-4.
y2x2-4
y2x2-4
Step 2
Graph y<-0.5x-1.
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Step 2.1
Use the slope-intercept form to find the slope and y-intercept.
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Step 2.1.1
The slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept.
y=mx+b
Step 2.1.2
Find the values of m and b using the form y=mx+b.
m=-0.5
b=-1
Step 2.1.3
The slope of the line is the value of m, and the y-intercept is the value of b.
Slope: -0.5
y-intercept: (0,-1)
Slope: -0.5
y-intercept: (0,-1)
Step 2.2
Graph a dashed line, then shade the area below the boundary line since y is less than -0.5x-1.
y<-0.5x-1
y<-0.5x-1
Step 3
Graph y<3x+2.
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Step 3.1
Use the slope-intercept form to find the slope and y-intercept.
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Step 3.1.1
The slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept.
y=mx+b
Step 3.1.2
Find the values of m and b using the form y=mx+b.
m=3
b=2
Step 3.1.3
The slope of the line is the value of m, and the y-intercept is the value of b.
Slope: 3
y-intercept: (0,2)
Slope: 3
y-intercept: (0,2)
Step 3.2
Graph a dashed line, then shade the area below the boundary line since y is less than 3x+2.
y<3x+2
y<3x+2
Step 4
Plot each graph on the same coordinate system.
y2x2-4
y<-0.5x-1
y<3x+2
Step 5
 [x2  12  π  xdx ]