Algebra Examples

$3 x y^{3} + 5 - x - 2 x y^{3} = x y^{3} + 11$

Step 1

Simplify $3 x y^{3} + 5 - x - 2 x y^{3}$ .

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Step 1.1

Subtract $2 x y^{3}$ from $3 x y^{3}$ .

$1 x y^{3} + 5 - x = x y^{3} + 11$

Step 1.2

Multiply $x$ by $1$ .

$x y^{3} + 5 - x = x y^{3} + 11$

Step 2

Move all terms containing $x$ to the left side of the equation.

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Step 2.1

Subtract $x y^{3}$ from both sides of the equation.

$x y^{3} + 5 - x - x y^{3} = 11$

Step 2.2

Combine the opposite terms in $x y^{3} + 5 - x - x y^{3}$ .

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Step 2.2.1

Subtract $x y^{3}$ from $x y^{3}$ .

$5 - x + 0 = 11$

Step 2.2.2

Add $5 - x$ and $0$ .

$5 - x = 11$

Step 3

Move all terms not containing $x$ to the right side of the equation.

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Step 3.1

Subtract $5$ from both sides of the equation.

$- x = 11 - 5$

Step 3.2

Subtract $5$ from $11$ .

$- x = 6$

Step 4

Divide each term in $- x = 6$ by $- 1$ and simplify.

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Step 4.1

Divide each term in $- x = 6$ by $- 1$ .

$\frac{- x}{- 1} = \frac{6}{- 1}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{6}{- 1}$

Step 4.2.2

Divide $x$ by $1$ .

$x = \frac{6}{- 1}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Divide $6$ by $- 1$ .

$x = - 6$