Algebra Examples

$y = x e^{- x^{2}}$

Step 1

Find where the expression $x e^{- x^{2}}$ is undefined.

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Step 2

The vertical asymptotes occur at areas of infinite discontinuity.

No Vertical Asymptotes

Step 3

Evaluate $lim_{x \to \infty} x e^{- x^{2}}$ to find the horizontal asymptote.

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Step 3.1

Rewrite $x e^{- x^{2}}$ as $\frac{x}{e^{x^{2}}}$ .

$lim_{x \to \infty} \frac{x}{e^{x^{2}}}$

Step 3.2

Apply L'Hospital's rule.

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Step 3.2.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 3.2.1.1

Take the limit of the numerator and the limit of the denominator.

$\frac{lim_{x \to \infty} x}{lim_{x \to \infty} e^{x^{2}}}$

Step 3.2.1.2

The limit at infinity of a polynomial whose leading coefficient is positive is infinity.

$\frac{\infty}{lim_{x \to \infty} e^{x^{2}}}$

Step 3.2.1.3

Since the exponent $x^{2}$ approaches $\infty$ , the quantity $e^{x^{2}}$ approaches $\infty$ .

$\frac{\infty}{\infty}$

Step 3.2.1.4

Infinity divided by infinity is undefined.

Undefined

$\frac{\infty}{\infty}$

Step 3.2.2

Since $\frac{\infty}{\infty}$ is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to \infty} \frac{x}{e^{x^{2}}} = lim_{x \to \infty} \frac{\frac{d}{d x} [x]}{\frac{d}{d x} [e^{x^{2}}]}$

Step 3.2.3

Find the derivative of the numerator and denominator.

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Step 3.2.3.1

Differentiate the numerator and denominator.

$lim_{x \to \infty} \frac{\frac{d}{d x} [x]}{\frac{d}{d x} [e^{x^{2}}]}$

Step 3.2.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$lim_{x \to \infty} \frac{1}{\frac{d}{d x} [e^{x^{2}}]}$

Step 3.2.3.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = x^{2}$ .

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Step 3.2.3.3.1

To apply the Chain Rule, set $u$ as $x^{2}$ .

$lim_{x \to \infty} \frac{1}{\frac{d}{d u} [e^{u}] \frac{d}{d x} [x^{2}]}$

Step 3.2.3.3.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u} [a^{u}]$ is $a^{u} \ln (a)$ where $a$ = $e$ .

$lim_{x \to \infty} \frac{1}{e^{u} \frac{d}{d x} [x^{2}]}$

Step 3.2.3.3.3

Replace all occurrences of $u$ with $x^{2}$ .

$lim_{x \to \infty} \frac{1}{e^{x^{2}} \frac{d}{d x} [x^{2}]}$

Step 3.2.3.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$lim_{x \to \infty} \frac{1}{e^{x^{2}} (2 x)}$

Step 3.2.3.5

Simplify.

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Step 3.2.3.5.1

Reorder the factors of $e^{x^{2}} (2 x)$ .

$lim_{x \to \infty} \frac{1}{2 e^{x^{2}} x}$

Step 3.2.3.5.2

Reorder factors in $2 e^{x^{2}} x$ .

$lim_{x \to \infty} \frac{1}{2 x e^{x^{2}}}$

Step 3.3

Move the term $\frac{1}{2}$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{2} lim_{x \to \infty} \frac{1}{x e^{x^{2}}}$

Step 3.4

Since its numerator approaches a real number while its denominator is unbounded, the fraction $\frac{1}{x e^{x^{2}}}$ approaches $0$ .

$\frac{1}{2} \cdot 0$

Step 3.5

Multiply $\frac{1}{2}$ by $0$ .

$0$

Step 4

List the horizontal asymptotes:

$y = 0$

Step 5

There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.

No Oblique Asymptotes

Step 6

This is the set of all asymptotes.

No Vertical Asymptotes

Horizontal Asymptotes: $y = 0$

No Oblique Asymptotes

Step 7