Algebra Examples

$x^{3} + 7 x^{2} + 7 x - 15$ , $x + 5$

Step 1

Divide the first expression by the second expression.

$\frac{x^{3} + 7 x^{2} + 7 x - 15}{x + 5}$

Step 2

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x$

$5$

$x^{3}$

$7 x^{2}$

$7 x$

$15$

Step 3

Divide the highest order term in the dividend $x^{3}$ by the highest order term in divisor $x$ .

					$x^{2}$
	$x$	+	$5$		$x^{3}$	+	$7 x^{2}$	+	$7 x$	-	$15$

Step 4

Multiply the new quotient term by the divisor.

				$x^{2}$
$x$	+	$5$		$x^{3}$	+	$7 x^{2}$	+	$7 x$	-	$15$
			+	$x^{3}$	+	$5 x^{2}$

Step 5

The expression needs to be subtracted from the dividend, so change all the signs in $x^{3} + 5 x^{2}$

				$x^{2}$
$x$	+	$5$		$x^{3}$	+	$7 x^{2}$	+	$7 x$	-	$15$
			-	$x^{3}$	-	$5 x^{2}$

Step 6

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$
$x$	+	$5$		$x^{3}$	+	$7 x^{2}$	+	$7 x$	-	$15$
			-	$x^{3}$	-	$5 x^{2}$
					+	$2 x^{2}$

Step 7

Pull the next terms from the original dividend down into the current dividend.

				$x^{2}$
$x$	+	$5$		$x^{3}$	+	$7 x^{2}$	+	$7 x$	-	$15$
			-	$x^{3}$	-	$5 x^{2}$
					+	$2 x^{2}$	+	$7 x$

Step 8

Divide the highest order term in the dividend $2 x^{2}$ by the highest order term in divisor $x$ .

				$x^{2}$	+	$2 x$
$x$	+	$5$		$x^{3}$	+	$7 x^{2}$	+	$7 x$	-	$15$
			-	$x^{3}$	-	$5 x^{2}$
					+	$2 x^{2}$	+	$7 x$

Step 9

Multiply the new quotient term by the divisor.

				$x^{2}$	+	$2 x$
$x$	+	$5$		$x^{3}$	+	$7 x^{2}$	+	$7 x$	-	$15$
			-	$x^{3}$	-	$5 x^{2}$
					+	$2 x^{2}$	+	$7 x$
					+	$2 x^{2}$	+	$10 x$

Step 10

The expression needs to be subtracted from the dividend, so change all the signs in $2 x^{2} + 10 x$

				$x^{2}$	+	$2 x$
$x$	+	$5$		$x^{3}$	+	$7 x^{2}$	+	$7 x$	-	$15$
			-	$x^{3}$	-	$5 x^{2}$
					+	$2 x^{2}$	+	$7 x$
					-	$2 x^{2}$	-	$10 x$

Step 11

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$	+	$2 x$
$x$	+	$5$		$x^{3}$	+	$7 x^{2}$	+	$7 x$	-	$15$
			-	$x^{3}$	-	$5 x^{2}$
					+	$2 x^{2}$	+	$7 x$
					-	$2 x^{2}$	-	$10 x$
							-	$3 x$

Step 12

Pull the next terms from the original dividend down into the current dividend.

				$x^{2}$	+	$2 x$
$x$	+	$5$		$x^{3}$	+	$7 x^{2}$	+	$7 x$	-	$15$
			-	$x^{3}$	-	$5 x^{2}$
					+	$2 x^{2}$	+	$7 x$
					-	$2 x^{2}$	-	$10 x$
							-	$3 x$	-	$15$

Step 13

Divide the highest order term in the dividend $- 3 x$ by the highest order term in divisor $x$ .

				$x^{2}$	+	$2 x$	-	$3$
$x$	+	$5$		$x^{3}$	+	$7 x^{2}$	+	$7 x$	-	$15$
			-	$x^{3}$	-	$5 x^{2}$
					+	$2 x^{2}$	+	$7 x$
					-	$2 x^{2}$	-	$10 x$
							-	$3 x$	-	$15$

Step 14

Multiply the new quotient term by the divisor.

				$x^{2}$	+	$2 x$	-	$3$
$x$	+	$5$		$x^{3}$	+	$7 x^{2}$	+	$7 x$	-	$15$
			-	$x^{3}$	-	$5 x^{2}$
					+	$2 x^{2}$	+	$7 x$
					-	$2 x^{2}$	-	$10 x$
							-	$3 x$	-	$15$
							-	$3 x$	-	$15$

Step 15

The expression needs to be subtracted from the dividend, so change all the signs in $- 3 x - 15$

				$x^{2}$	+	$2 x$	-	$3$
$x$	+	$5$		$x^{3}$	+	$7 x^{2}$	+	$7 x$	-	$15$
			-	$x^{3}$	-	$5 x^{2}$
					+	$2 x^{2}$	+	$7 x$
					-	$2 x^{2}$	-	$10 x$
							-	$3 x$	-	$15$
							+	$3 x$	+	$15$

Step 16

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$	+	$2 x$	-	$3$
$x$	+	$5$		$x^{3}$	+	$7 x^{2}$	+	$7 x$	-	$15$
			-	$x^{3}$	-	$5 x^{2}$
					+	$2 x^{2}$	+	$7 x$
					-	$2 x^{2}$	-	$10 x$
							-	$3 x$	-	$15$
							+	$3 x$	+	$15$
										$0$

Step 17

Since the remander is $0$ , the final answer is the quotient.

$x^{2} + 2 x - 3$