Algebra Examples

$4 m \leq - 32$ and $m + 28 > 23$

Step 1

Divide each term in $4 m \leq - 32$ by $4$ and simplify.

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Step 1.1

Divide each term in $4 m \leq - 32$ by $4$ .

$\frac{4 m}{4} \leq \frac{- 32}{4}$ and $m + 28 > 23$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of $4$ .

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Step 1.2.1.1

Cancel the common factor.

$\frac{4 m}{4} \leq \frac{- 32}{4}$ and $m + 28 > 23$

Step 1.2.1.2

Divide $m$ by $1$ .

$m \leq \frac{- 32}{4}$ and $m + 28 > 23$

Step 1.3

Simplify the right side.

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Step 1.3.1

Divide $- 32$ by $4$ .

$m \leq - 8$ and $m + 28 > 23$

Step 2

Move all terms not containing $m$ to the right side of the inequality.

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Step 2.1

Subtract $28$ from both sides of the inequality.

$m \leq - 8$ and $m > 23 - 28$

Step 2.2

Subtract $28$ from $23$ .

$m \leq - 8$ and $m > - 5$

Step 3

The intersection consists of the elements that are contained in both intervals.

No solution