Algebra Examples

4 m \leq - 32

$4 m \leq - 32$ and

m + 28 > 23

$m + 28 > 23$

Step 1

Divide each term in

4 m \leq - 32

$4 m \leq - 32$ by

4

$4$ and simplify.

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Step 1.1

Divide each term in

4 m \leq - 32

$4 m \leq - 32$ by

4

$4$ .

\frac{4 m}{4} \leq \frac{- 32}{4}

$\frac{4 m}{4} \leq \frac{- 32}{4}$ and

m + 28 > 23

$m + 28 > 23$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of

4

$4$ .

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Step 1.2.1.1

Cancel the common factor.

$\frac{4 m}{4} \leq \frac{- 32}{4}$ and

$m + 28 > 23$

Step 1.2.1.2

Divide

$m$ by

$1$ .

$m \leq \frac{- 32}{4}$ and

$m + 28 > 23$

$m \leq \frac{- 32}{4}$ and

$m + 28 > 23$

$m \leq \frac{- 32}{4}$ and

$m + 28 > 23$

Step 1.3

Simplify the right side.

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Step 1.3.1

Divide

$- 32$ by

$4$ .

$m \leq - 8$ and

$m + 28 > 23$

$m \leq - 8$ and

$m + 28 > 23$

$m \leq - 8$ and

$m + 28 > 23$

Step 2

Move all terms not containing

$m$ to the right side of the inequality.

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Step 2.1

Subtract

$28$ from both sides of the inequality.

$m \leq - 8$ and

$m > 23 - 28$

Step 2.2

Subtract

$28$ from

$23$ .

$m \leq - 8$ and

$m > - 5$

$m \leq - 8$ and

$m > - 5$

Step 3

The intersection consists of the elements that are contained in both intervals.

No solution

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$