Algebra Examples

$\frac{2 (4 t - 6 t)}{40} = \frac{(7 + 2)}{3}$

Step 1

Cancel the common factors.

Tap for more steps...

Step 1.1

Factor $2$ out of $40$ .

$\frac{2 (4 t - 6 t)}{2 \cdot 20} = \frac{7 + 2}{3}$

Step 1.2

Cancel the common factor.

$\frac{2 (4 t - 6 t)}{2 \cdot 20} = \frac{7 + 2}{3}$

Step 1.3

Rewrite the expression.

$\frac{4 t - 6 t}{20} = \frac{7 + 2}{3}$

Step 2

Multiply both sides by $20$ .

$\frac{4 t - 6 t}{20} \cdot 20 = \frac{7 + 2}{3} \cdot 20$

Step 3

Simplify.

Tap for more steps...

Step 3.1

Simplify the left side.

Tap for more steps...

Step 3.1.1

Simplify $\frac{4 t - 6 t}{20} \cdot 20$ .

Tap for more steps...

Step 3.1.1.1

Subtract $6 t$ from $4 t$ .

$\frac{- 2 t}{20} \cdot 20 = \frac{7 + 2}{3} \cdot 20$

Step 3.1.1.2

Cancel the common factor of $20$ .

Tap for more steps...

Step 3.1.1.2.1

Cancel the common factor.

$\frac{- 2 t}{20} \cdot 20 = \frac{7 + 2}{3} \cdot 20$

Step 3.1.1.2.2

Rewrite the expression.

$- 2 t = \frac{7 + 2}{3} \cdot 20$

Step 3.2

Simplify the right side.

Tap for more steps...

Step 3.2.1

Simplify $\frac{7 + 2}{3} \cdot 20$ .

Tap for more steps...

Step 3.2.1.1

Add $7$ and $2$ .

$- 2 t = \frac{9}{3} \cdot 20$

Step 3.2.1.2

Divide $9$ by $3$ .

$- 2 t = 3 \cdot 20$

Step 3.2.1.3

Multiply $3$ by $20$ .

$- 2 t = 60$

Step 4

Divide each term in $- 2 t = 60$ by $- 2$ and simplify.

Tap for more steps...

Step 4.1

Divide each term in $- 2 t = 60$ by $- 2$ .

$\frac{- 2 t}{- 2} = \frac{60}{- 2}$

Step 4.2

Simplify the left side.

Tap for more steps...

Step 4.2.1

Cancel the common factor of $- 2$ .

Tap for more steps...

Step 4.2.1.1

Cancel the common factor.

$\frac{- 2 t}{- 2} = \frac{60}{- 2}$

Step 4.2.1.2

Divide $t$ by $1$ .

$t = \frac{60}{- 2}$

Step 4.3

Simplify the right side.

Tap for more steps...

Step 4.3.1

Divide $60$ by $- 2$ .

$t = - 30$