Algebra Examples

${(8 - 2)}^{2} + \frac{1}{4} (4 - 3 (6 - 10))$

Step 1

Simplify each term.

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Step 1.1

Subtract $2$ from $8$ .

$6^{2} + \frac{1}{4} \cdot (4 - 3 (6 - 10))$

Step 1.2

Raise $6$ to the power of $2$ .

$36 + \frac{1}{4} \cdot (4 - 3 (6 - 10))$

Step 1.3

Simplify each term.

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Step 1.3.1

Subtract $10$ from $6$ .

$36 + \frac{1}{4} \cdot (4 - 3 \cdot - 4)$

Step 1.3.2

Multiply $- 3$ by $- 4$ .

$36 + \frac{1}{4} \cdot (4 + 12)$

$36 + \frac{1}{4} \cdot (4 + 12)$

Step 1.4

Add $4$ and $12$ .

$36 + \frac{1}{4} \cdot 16$

Step 1.5

Cancel the common factor of $4$ .

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Step 1.5.1

Factor $4$ out of $16$ .

$36 + \frac{1}{4} \cdot (4 (4))$

Step 1.5.2

Cancel the common factor.

$36 + \frac{1}{4} \cdot (4 \cdot 4)$

Step 1.5.3

Rewrite the expression.

$36 + 4$

$36 + 4$

$36 + 4$

Step 2

Add $36$ and $4$ .

$40$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$