Algebra Examples

$\frac{8 k + 9}{18} - \frac{2 k + 1}{18}$

Step 1

Combine the numerators over the common denominator.

$\frac{8 k + 9 - (2 k + 1)}{18}$

Step 2

Simplify each term.

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Step 2.1

Apply the distributive property.

$\frac{8 k + 9 - (2 k) - 1 \cdot 1}{18}$

Step 2.2

Multiply $2$ by $- 1$ .

$\frac{8 k + 9 - 2 k - 1 \cdot 1}{18}$

Step 2.3

Multiply $- 1$ by $1$ .

$\frac{8 k + 9 - 2 k - 1}{18}$

$\frac{8 k + 9 - 2 k - 1}{18}$

Step 3

Simplify terms.

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Step 3.1

Subtract $2 k$ from $8 k$ .

$\frac{6 k + 9 - 1}{18}$

Step 3.2

Subtract $1$ from $9$ .

$\frac{6 k + 8}{18}$

Step 3.3

Cancel the common factor of $6 k + 8$ and $18$ .

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Step 3.3.1

Factor $2$ out of $6 k$ .

$\frac{2 (3 k) + 8}{18}$

Step 3.3.2

Factor $2$ out of $8$ .

$\frac{2 (3 k) + 2 (4)}{18}$

Step 3.3.3

Factor $2$ out of $2 (3 k) + 2 (4)$ .

$\frac{2 (3 k + 4)}{18}$

Step 3.3.4

Cancel the common factors.

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Step 3.3.4.1

Factor $2$ out of $18$ .

$\frac{2 (3 k + 4)}{2 (9)}$

Step 3.3.4.2

Cancel the common factor.

$\frac{2 (3 k + 4)}{2 \cdot 9}$

Step 3.3.4.3

Rewrite the expression.

$\frac{3 k + 4}{9}$

$\frac{3 k + 4}{9}$

$\frac{3 k + 4}{9}$

$\frac{3 k + 4}{9}$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$