Algebra Examples

$- 1 + y = \frac{1}{5} x$

Step 1

The standard form of a linear equation is $A x + B y = C$ .

Step 2

Multiply both sides by $5$ .

$5 (- 1 + y) = 5 (\frac{1}{5} x)$

Step 3

Simplify the left side.

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Step 3.1

Simplify $5 (- 1 + y)$ .

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Step 3.1.1

Apply the distributive property.

$5 \cdot - 1 + 5 y = 5 (\frac{1}{5} x)$

Step 3.1.2

Multiply $5$ by $- 1$ .

$- 5 + 5 y = 5 (\frac{1}{5} x)$

$- 5 + 5 y = 5 (\frac{1}{5} x)$

$- 5 + 5 y = 5 (\frac{1}{5} x)$

Step 4

Simplify the right side.

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Step 4.1

Simplify $5 (\frac{1}{5} x)$ .

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Step 4.1.1

Combine $\frac{1}{5}$ and $x$ .

$- 5 + 5 y = 5 \frac{x}{5}$

Step 4.1.2

Cancel the common factor of $5$ .

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Step 4.1.2.1

Cancel the common factor.

$- 5 + 5 y = 5 \frac{x}{5}$

Step 4.1.2.2

Rewrite the expression.

$- 5 + 5 y = x$

$- 5 + 5 y = x$

$- 5 + 5 y = x$

$- 5 + 5 y = x$

Step 5

Rewrite the equation.

$x = - 5 + 5 y$

Step 6

Subtract $5 y$ from both sides of the equation.

$x - 5 y = - 5$

Step 7

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$