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Algebra Examples
Step 1
Step 1.1
Add to both sides of the equation.
Step 1.2
Reorder the polynomial.
Step 1.3
Multiply each equation by the value that makes the coefficients of opposite.
Step 1.4
Simplify.
Step 1.4.1
Simplify the left side.
Step 1.4.1.1
Simplify .
Step 1.4.1.1.1
Apply the distributive property.
Step 1.4.1.1.2
Multiply.
Step 1.4.1.1.2.1
Multiply by .
Step 1.4.1.1.2.2
Multiply by .
Step 1.4.2
Simplify the right side.
Step 1.4.2.1
Multiply by .
Step 1.5
Add the two equations together to eliminate from the system.
Step 1.6
Divide each term in by and simplify.
Step 1.6.1
Divide each term in by .
Step 1.6.2
Simplify the left side.
Step 1.6.2.1
Cancel the common factor of .
Step 1.6.2.1.1
Cancel the common factor.
Step 1.6.2.1.2
Divide by .
Step 1.6.3
Simplify the right side.
Step 1.6.3.1
Divide by .
Step 1.7
Substitute the value found for into one of the original equations, then solve for .
Step 1.7.1
Substitute the value found for into one of the original equations to solve for .
Step 1.7.2
Multiply by .
Step 1.7.3
Move all terms not containing to the right side of the equation.
Step 1.7.3.1
Add to both sides of the equation.
Step 1.7.3.2
Add and .
Step 1.7.4
Divide each term in by and simplify.
Step 1.7.4.1
Divide each term in by .
Step 1.7.4.2
Simplify the left side.
Step 1.7.4.2.1
Cancel the common factor of .
Step 1.7.4.2.1.1
Cancel the common factor.
Step 1.7.4.2.1.2
Divide by .
Step 1.7.4.3
Simplify the right side.
Step 1.7.4.3.1
Divide by .
Step 1.8
The solution to the independent system of equations can be represented as a point.
Step 2
Since the system has a point of intersection, the system is independent.
Independent
Step 3