Algebra Examples

Simplify $\frac{6 x^{2} - 24}{x^{2} + 9 x + 14} \div \frac{3 x^{2} + 6 x - 24}{x^{2} + 2 x - 35}$

Step 1

To divide by a fraction, multiply by its reciprocal.

$\frac{6 x^{2} - 24}{x^{2} + 9 x + 14} \cdot \frac{x^{2} + 2 x - 35}{3 x^{2} + 6 x - 24}$

Step 2

Simplify the numerator.

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Step 2.1

Factor $6$ out of $6 x^{2} - 24$ .

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Step 2.1.1

Factor $6$ out of $6 x^{2}$ .

$\frac{6 (x^{2}) - 24}{x^{2} + 9 x + 14} \cdot \frac{x^{2} + 2 x - 35}{3 x^{2} + 6 x - 24}$

Step 2.1.2

Factor $6$ out of $- 24$ .

$\frac{6 x^{2} + 6 \cdot - 4}{x^{2} + 9 x + 14} \cdot \frac{x^{2} + 2 x - 35}{3 x^{2} + 6 x - 24}$

Step 2.1.3

Factor $6$ out of $6 x^{2} + 6 \cdot - 4$ .

$\frac{6 (x^{2} - 4)}{x^{2} + 9 x + 14} \cdot \frac{x^{2} + 2 x - 35}{3 x^{2} + 6 x - 24}$

Step 2.2

Rewrite $4$ as $2^{2}$ .

$\frac{6 (x^{2} - 2^{2})}{x^{2} + 9 x + 14} \cdot \frac{x^{2} + 2 x - 35}{3 x^{2} + 6 x - 24}$

Step 2.3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 2$ .

$\frac{6 (x + 2) (x - 2)}{x^{2} + 9 x + 14} \cdot \frac{x^{2} + 2 x - 35}{3 x^{2} + 6 x - 24}$

Step 3

Factor $x^{2} + 9 x + 14$ using the AC method.

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Step 3.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $14$ and whose sum is $9$ .

$2, 7$

Step 3.2

Write the factored form using these integers.

$\frac{6 (x + 2) (x - 2)}{(x + 2) (x + 7)} \cdot \frac{x^{2} + 2 x - 35}{3 x^{2} + 6 x - 24}$

Step 4

Cancel the common factor of $x + 2$ .

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Step 4.1

Cancel the common factor.

$\frac{6 (x + 2) (x - 2)}{(x + 2) (x + 7)} \cdot \frac{x^{2} + 2 x - 35}{3 x^{2} + 6 x - 24}$

Step 4.2

Rewrite the expression.

$\frac{6 (x - 2)}{x + 7} \cdot \frac{x^{2} + 2 x - 35}{3 x^{2} + 6 x - 24}$

Step 5

Factor $x^{2} + 2 x - 35$ using the AC method.

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Step 5.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 35$ and whose sum is $2$ .

$- 5, 7$

Step 5.2

Write the factored form using these integers.

$\frac{6 (x - 2)}{x + 7} \cdot \frac{(x - 5) (x + 7)}{3 x^{2} + 6 x - 24}$

Step 6

Simplify the denominator.

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Step 6.1

Factor $3$ out of $3 x^{2} + 6 x - 24$ .

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Step 6.1.1

Factor $3$ out of $3 x^{2}$ .

$\frac{6 (x - 2)}{x + 7} \cdot \frac{(x - 5) (x + 7)}{3 (x^{2}) + 6 x - 24}$

Step 6.1.2

Factor $3$ out of $6 x$ .

$\frac{6 (x - 2)}{x + 7} \cdot \frac{(x - 5) (x + 7)}{3 (x^{2}) + 3 (2 x) - 24}$

Step 6.1.3

Factor $3$ out of $- 24$ .

$\frac{6 (x - 2)}{x + 7} \cdot \frac{(x - 5) (x + 7)}{3 x^{2} + 3 (2 x) + 3 \cdot - 8}$

Step 6.1.4

Factor $3$ out of $3 x^{2} + 3 (2 x)$ .

$\frac{6 (x - 2)}{x + 7} \cdot \frac{(x - 5) (x + 7)}{3 (x^{2} + 2 x) + 3 \cdot - 8}$

Step 6.1.5

Factor $3$ out of $3 (x^{2} + 2 x) + 3 \cdot - 8$ .

$\frac{6 (x - 2)}{x + 7} \cdot \frac{(x - 5) (x + 7)}{3 (x^{2} + 2 x - 8)}$

Step 6.2

Factor $x^{2} + 2 x - 8$ using the AC method.

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Step 6.2.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 8$ and whose sum is $2$ .

$- 2, 4$

Step 6.2.2

Write the factored form using these integers.

$\frac{6 (x - 2)}{x + 7} \cdot \frac{(x - 5) (x + 7)}{3 ((x - 2) (x + 4))}$

$\frac{6 (x - 2)}{x + 7} \cdot \frac{(x - 5) (x + 7)}{3 (x - 2) (x + 4)}$

Step 7

Simplify terms.

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Step 7.1

Cancel the common factor of $3 (x - 2)$ .

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Step 7.1.1

Factor $3 (x - 2)$ out of $6 (x - 2)$ .

$\frac{3 (x - 2) (2)}{x + 7} \cdot \frac{(x - 5) (x + 7)}{3 (x - 2) (x + 4)}$

Step 7.1.2

Cancel the common factor.

$\frac{3 (x - 2) \cdot 2}{x + 7} \cdot \frac{(x - 5) (x + 7)}{3 (x - 2) (x + 4)}$

Step 7.1.3

Rewrite the expression.

$\frac{2}{x + 7} \cdot \frac{(x - 5) (x + 7)}{x + 4}$

Step 7.2

Cancel the common factor of $x + 7$ .

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Step 7.2.1

Factor $x + 7$ out of $(x - 5) (x + 7)$ .

$\frac{2}{x + 7} \cdot \frac{(x + 7) (x - 5)}{x + 4}$

Step 7.2.2

Cancel the common factor.

$\frac{2}{x + 7} \cdot \frac{(x + 7) (x - 5)}{x + 4}$

Step 7.2.3

Rewrite the expression.

$2 \frac{x - 5}{x + 4}$

Step 7.3

Combine $2$ and $\frac{x - 5}{x + 4}$ .

$\frac{2 (x - 5)}{x + 4}$