Algebra Examples

Determine if Linear x/4-y/3=1
x4-y3=1
Step 1
Solve the equation for y.
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Step 1.1
Subtract x4 from both sides of the equation.
-y3=1-x4
Step 1.2
Multiply both sides of the equation by -3.
-3(-y3)=-3(1-x4)
Step 1.3
Simplify both sides of the equation.
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Step 1.3.1
Simplify the left side.
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Step 1.3.1.1
Simplify -3(-y3).
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Step 1.3.1.1.1
Cancel the common factor of 3.
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Step 1.3.1.1.1.1
Move the leading negative in -y3 into the numerator.
-3-y3=-3(1-x4)
Step 1.3.1.1.1.2
Factor 3 out of -3.
3(-1)-y3=-3(1-x4)
Step 1.3.1.1.1.3
Cancel the common factor.
3-1-y3=-3(1-x4)
Step 1.3.1.1.1.4
Rewrite the expression.
--y=-3(1-x4)
--y=-3(1-x4)
Step 1.3.1.1.2
Multiply.
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Step 1.3.1.1.2.1
Multiply -1 by -1.
1y=-3(1-x4)
Step 1.3.1.1.2.2
Multiply y by 1.
y=-3(1-x4)
y=-3(1-x4)
y=-3(1-x4)
y=-3(1-x4)
Step 1.3.2
Simplify the right side.
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Step 1.3.2.1
Simplify -3(1-x4).
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Step 1.3.2.1.1
Apply the distributive property.
y=-31-3(-x4)
Step 1.3.2.1.2
Multiply -3 by 1.
y=-3-3(-x4)
Step 1.3.2.1.3
Multiply -3(-x4).
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Step 1.3.2.1.3.1
Multiply -1 by -3.
y=-3+3x4
Step 1.3.2.1.3.2
Combine 3 and x4.
y=-3+3x4
y=-3+3x4
y=-3+3x4
y=-3+3x4
y=-3+3x4
Step 1.4
Reorder -3 and 3x4.
y=3x4-3
y=3x4-3
Step 2
A linear equation is an equation of a straight line, which means that the degree of a linear equation must be 0 or 1 for each of its variables. In this case, the degree of variable y is 1 and the degree of variable x is 1.
Linear
 [x2  12  π  xdx ]