Algebra Examples

$y = \frac{4}{3} {(x - 1)}^{3} + 6$

Step 1

Interchange the variables.

$x = \frac{4}{3} \cdot {(y - 1)}^{3} + 6$

Step 2

Solve for $y$ .

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Step 2.1

Rewrite the equation as $\frac{4}{3} \cdot {(y - 1)}^{3} + 6 = x$ .

$\frac{4}{3} \cdot {(y - 1)}^{3} + 6 = x$

Step 2.2

Subtract $6$ from both sides of the equation.

$\frac{4}{3} \cdot {(y - 1)}^{3} = x - 6$

Step 2.3

Combine $\frac{4}{3}$ and ${(y - 1)}^{3}$ .

$\frac{4 {(y - 1)}^{3}}{3} = x - 6$

Step 2.4

Multiply both sides of the equation by $\frac{3}{4}$ .

$\frac{3}{4} \cdot \frac{4 {(y - 1)}^{3}}{3} = \frac{3}{4} (x - 6)$

Step 2.5

Simplify both sides of the equation.

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Step 2.5.1

Simplify the left side.

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Step 2.5.1.1

Simplify $\frac{3}{4} \cdot \frac{4 {(y - 1)}^{3}}{3}$ .

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Step 2.5.1.1.1

Combine.

$\frac{3 (4 {(y - 1)}^{3})}{4 \cdot 3} = \frac{3}{4} (x - 6)$

Step 2.5.1.1.2

Cancel the common factor of $3$ .

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Step 2.5.1.1.2.1

Cancel the common factor.

$\frac{3 (4 {(y - 1)}^{3})}{4 \cdot 3} = \frac{3}{4} (x - 6)$

Step 2.5.1.1.2.2

Rewrite the expression.

$\frac{4 {(y - 1)}^{3}}{4} = \frac{3}{4} (x - 6)$

Step 2.5.1.1.3

Cancel the common factor of $4$ .

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Step 2.5.1.1.3.1

Cancel the common factor.

$\frac{4 {(y - 1)}^{3}}{4} = \frac{3}{4} (x - 6)$

Step 2.5.1.1.3.2

Divide ${(y - 1)}^{3}$ by $1$ .

${(y - 1)}^{3} = \frac{3}{4} (x - 6)$

Step 2.5.2

Simplify the right side.

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Step 2.5.2.1

Simplify $\frac{3}{4} (x - 6)$ .

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Step 2.5.2.1.1

Apply the distributive property.

${(y - 1)}^{3} = \frac{3}{4} x + \frac{3}{4} \cdot - 6$

Step 2.5.2.1.2

Combine $\frac{3}{4}$ and $x$ .

${(y - 1)}^{3} = \frac{3 x}{4} + \frac{3}{4} \cdot - 6$

Step 2.5.2.1.3

Cancel the common factor of $2$ .

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Step 2.5.2.1.3.1

Factor $2$ out of $4$ .

${(y - 1)}^{3} = \frac{3 x}{4} + \frac{3}{2 (2)} \cdot - 6$

Step 2.5.2.1.3.2

Factor $2$ out of $- 6$ .

${(y - 1)}^{3} = \frac{3 x}{4} + \frac{3}{2 \cdot 2} \cdot (2 \cdot - 3)$

Step 2.5.2.1.3.3

Cancel the common factor.

${(y - 1)}^{3} = \frac{3 x}{4} + \frac{3}{2 \cdot 2} \cdot (2 \cdot - 3)$

Step 2.5.2.1.3.4

Rewrite the expression.

${(y - 1)}^{3} = \frac{3 x}{4} + \frac{3}{2} \cdot - 3$

Step 2.5.2.1.4

Combine $\frac{3}{2}$ and $- 3$ .

${(y - 1)}^{3} = \frac{3 x}{4} + \frac{3 \cdot - 3}{2}$

Step 2.5.2.1.5

Simplify the expression.

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Step 2.5.2.1.5.1

Multiply $3$ by $- 3$ .

${(y - 1)}^{3} = \frac{3 x}{4} + \frac{- 9}{2}$

Step 2.5.2.1.5.2

Move the negative in front of the fraction.

${(y - 1)}^{3} = \frac{3 x}{4} - \frac{9}{2}$

Step 2.6

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$y - 1 = \sqrt[3]{\frac{3 x}{4} - \frac{9}{2}}$

Step 2.7

Simplify $\sqrt[3]{\frac{3 x}{4} - \frac{9}{2}}$ .

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Step 2.7.1

To write $- \frac{9}{2}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$y - 1 = \sqrt[3]{\frac{3 x}{4} - \frac{9}{2} \cdot \frac{2}{2}}$

Step 2.7.2

Write each expression with a common denominator of $4$ , by multiplying each by an appropriate factor of $1$ .

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Step 2.7.2.1

Multiply $\frac{9}{2}$ by $\frac{2}{2}$ .

$y - 1 = \sqrt[3]{\frac{3 x}{4} - \frac{9 \cdot 2}{2 \cdot 2}}$

Step 2.7.2.2

Multiply $2$ by $2$ .

$y - 1 = \sqrt[3]{\frac{3 x}{4} - \frac{9 \cdot 2}{4}}$

Step 2.7.3

Combine the numerators over the common denominator.

$y - 1 = \sqrt[3]{\frac{3 x - 9 \cdot 2}{4}}$

Step 2.7.4

Simplify the numerator.

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Step 2.7.4.1

Factor $3$ out of $3 x - 9 \cdot 2$ .

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Step 2.7.4.1.1

Factor $3$ out of $3 x$ .

$y - 1 = \sqrt[3]{\frac{3 (x) - 9 \cdot 2}{4}}$

Step 2.7.4.1.2

Factor $3$ out of $- 9 \cdot 2$ .

$y - 1 = \sqrt[3]{\frac{3 (x) + 3 (- 3 \cdot 2)}{4}}$

Step 2.7.4.1.3

Factor $3$ out of $3 (x) + 3 (- 3 \cdot 2)$ .

$y - 1 = \sqrt[3]{\frac{3 (x - 3 \cdot 2)}{4}}$

Step 2.7.4.2

Multiply $- 3$ by $2$ .

$y - 1 = \sqrt[3]{\frac{3 (x - 6)}{4}}$

Step 2.7.5

Rewrite $\sqrt[3]{\frac{3 (x - 6)}{4}}$ as $\frac{\sqrt[3]{3 (x - 6)}}{\sqrt[3]{4}}$ .

$y - 1 = \frac{\sqrt[3]{3 (x - 6)}}{\sqrt[3]{4}}$

Step 2.7.6

Multiply $\frac{\sqrt[3]{3 (x - 6)}}{\sqrt[3]{4}}$ by $\frac{{\sqrt[3]{4}}^{2}}{{\sqrt[3]{4}}^{2}}$ .

$y - 1 = \frac{\sqrt[3]{3 (x - 6)}}{\sqrt[3]{4}} \cdot \frac{{\sqrt[3]{4}}^{2}}{{\sqrt[3]{4}}^{2}}$

Step 2.7.7

Combine and simplify the denominator.

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Step 2.7.7.1

Multiply $\frac{\sqrt[3]{3 (x - 6)}}{\sqrt[3]{4}}$ by $\frac{{\sqrt[3]{4}}^{2}}{{\sqrt[3]{4}}^{2}}$ .

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} {\sqrt[3]{4}}^{2}}{\sqrt[3]{4} {\sqrt[3]{4}}^{2}}$

Step 2.7.7.2

Raise $\sqrt[3]{4}$ to the power of $1$ .

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} {\sqrt[3]{4}}^{2}}{{\sqrt[3]{4}}^{1} {\sqrt[3]{4}}^{2}}$

Step 2.7.7.3

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} {\sqrt[3]{4}}^{2}}{{\sqrt[3]{4}}^{1 + 2}}$

Step 2.7.7.4

Add $1$ and $2$ .

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} {\sqrt[3]{4}}^{2}}{{\sqrt[3]{4}}^{3}}$

Step 2.7.7.5

Rewrite ${\sqrt[3]{4}}^{3}$ as $4$ .

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Step 2.7.7.5.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{4}$ as $4^{\frac{1}{3}}$ .

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} {\sqrt[3]{4}}^{2}}{{(4^{\frac{1}{3}})}^{3}}$

Step 2.7.7.5.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} {\sqrt[3]{4}}^{2}}{4^{\frac{1}{3} \cdot 3}}$

Step 2.7.7.5.3

Combine $\frac{1}{3}$ and $3$ .

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} {\sqrt[3]{4}}^{2}}{4^{\frac{3}{3}}}$

Step 2.7.7.5.4

Cancel the common factor of $3$ .

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Step 2.7.7.5.4.1

Cancel the common factor.

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} {\sqrt[3]{4}}^{2}}{4^{\frac{3}{3}}}$

Step 2.7.7.5.4.2

Rewrite the expression.

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} {\sqrt[3]{4}}^{2}}{4^{1}}$

Step 2.7.7.5.5

Evaluate the exponent.

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} {\sqrt[3]{4}}^{2}}{4}$

Step 2.7.8

Simplify the numerator.

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Step 2.7.8.1

Rewrite ${\sqrt[3]{4}}^{2}$ as $\sqrt[3]{4^{2}}$ .

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} \sqrt[3]{4^{2}}}{4}$

Step 2.7.8.2

Raise $4$ to the power of $2$ .

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} \sqrt[3]{16}}{4}$

Step 2.7.8.3

Rewrite $16$ as $2^{3} \cdot 2$ .

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Step 2.7.8.3.1

Factor $8$ out of $16$ .

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} \sqrt[3]{8 (2)}}{4}$

Step 2.7.8.3.2

Rewrite $8$ as $2^{3}$ .

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} \sqrt[3]{2^{3} \cdot 2}}{4}$

Step 2.7.8.4

Pull terms out from under the radical.

$y - 1 = \frac{\sqrt[3]{3 (x - 6)} \cdot 2 \sqrt[3]{2}}{4}$

Step 2.7.8.5

Combine exponents.

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Step 2.7.8.5.1

Combine using the product rule for radicals.

$y - 1 = \frac{2 \sqrt[3]{3 (x - 6) \cdot 2}}{4}$

Step 2.7.8.5.2

Multiply $2$ by $3$ .

$y - 1 = \frac{2 \sqrt[3]{6 (x - 6)}}{4}$

Step 2.7.9

Cancel the common factor of $2$ and $4$ .

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Step 2.7.9.1

Factor $2$ out of $2 \sqrt[3]{6 (x - 6)}$ .

$y - 1 = \frac{2 (\sqrt[3]{6 (x - 6)})}{4}$

Step 2.7.9.2

Cancel the common factors.

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Step 2.7.9.2.1

Factor $2$ out of $4$ .

$y - 1 = \frac{2 \sqrt[3]{6 (x - 6)}}{2 \cdot 2}$

Step 2.7.9.2.2

Cancel the common factor.

$y - 1 = \frac{2 \sqrt[3]{6 (x - 6)}}{2 \cdot 2}$

Step 2.7.9.2.3

Rewrite the expression.

$y - 1 = \frac{\sqrt[3]{6 (x - 6)}}{2}$

Step 2.8

Add $1$ to both sides of the equation.

$y = \frac{\sqrt[3]{6 (x - 6)}}{2} + 1$

Step 2.9

Simplify $\frac{\sqrt[3]{6 (x - 6)}}{2} + 1$ .

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Step 2.9.1

Write $1$ as a fraction with a common denominator.

$y = \frac{\sqrt[3]{6 (x - 6)}}{2} + \frac{2}{2}$

Step 2.9.2

Combine the numerators over the common denominator.

$y = \frac{\sqrt[3]{6 (x - 6)} + 2}{2}$

Step 3

Replace $y$ with $f^{- 1} (x)$ to show the final answer.

$f^{- 1} (x) = \frac{\sqrt[3]{6 (x - 6)} + 2}{2}$

Step 4

Verify if $f^{- 1} (x) = \frac{\sqrt[3]{6 (x - 6)} + 2}{2}$ is the inverse of $f (x) = \frac{4}{3} \cdot {(x - 1)}^{3} + 6$ .

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Step 4.1

To verify the inverse, check if $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ .

Step 4.2

Evaluate $f^{- 1} (f (x))$ .

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Step 4.2.1

Set up the composite result function.

$f^{- 1} (f (x))$

Step 4.2.2

Evaluate $f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6)$ by substituting in the value of $f$ into $f^{- 1}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 ((\frac{4}{3} \cdot {(x - 1)}^{3} + 6) - 6)} + 2}{2}$

Step 4.2.3

Simplify the numerator.

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Step 4.2.3.1

Use the Binomial Theorem.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4}{3} \cdot (x^{3} + 3 x^{2} \cdot - 1 + 3 x {(- 1)}^{2} + {(- 1)}^{3}) + 6 - 6)} + 2}{2}$

Step 4.2.3.2

Simplify each term.

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Step 4.2.3.2.1

Multiply $- 1$ by $3$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4}{3} \cdot (x^{3} - 3 x^{2} + 3 x {(- 1)}^{2} + {(- 1)}^{3}) + 6 - 6)} + 2}{2}$

Step 4.2.3.2.2

Raise $- 1$ to the power of $2$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4}{3} \cdot (x^{3} - 3 x^{2} + 3 x \cdot 1 + {(- 1)}^{3}) + 6 - 6)} + 2}{2}$

Step 4.2.3.2.3

Multiply $3$ by $1$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4}{3} \cdot (x^{3} - 3 x^{2} + 3 x + {(- 1)}^{3}) + 6 - 6)} + 2}{2}$

Step 4.2.3.2.4

Raise $- 1$ to the power of $3$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4}{3} \cdot (x^{3} - 3 x^{2} + 3 x - 1) + 6 - 6)} + 2}{2}$

Step 4.2.3.3

Apply the distributive property.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4}{3} x^{3} + \frac{4}{3} \cdot (- 3 x^{2}) + \frac{4}{3} \cdot (3 x) + \frac{4}{3} \cdot - 1 + 6 - 6)} + 2}{2}$

Step 4.2.3.4

Simplify.

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Step 4.2.3.4.1

Combine $\frac{4}{3}$ and $x^{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} + \frac{4}{3} \cdot (- 3 x^{2}) + \frac{4}{3} \cdot (3 x) + \frac{4}{3} \cdot - 1 + 6 - 6)} + 2}{2}$

Step 4.2.3.4.2

Cancel the common factor of $3$ .

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Step 4.2.3.4.2.1

Factor $3$ out of $- 3 x^{2}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} + \frac{4}{3} \cdot (3 (- x^{2})) + \frac{4}{3} \cdot (3 x) + \frac{4}{3} \cdot - 1 + 6 - 6)} + 2}{2}$

Step 4.2.3.4.2.2

Cancel the common factor.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} + \frac{4}{3} \cdot (3 (- x^{2})) + \frac{4}{3} \cdot (3 x) + \frac{4}{3} \cdot - 1 + 6 - 6)} + 2}{2}$

Step 4.2.3.4.2.3

Rewrite the expression.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} + 4 (- x^{2}) + \frac{4}{3} \cdot (3 x) + \frac{4}{3} \cdot - 1 + 6 - 6)} + 2}{2}$

Step 4.2.3.4.3

Multiply $- 1$ by $4$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + \frac{4}{3} \cdot (3 x) + \frac{4}{3} \cdot - 1 + 6 - 6)} + 2}{2}$

Step 4.2.3.4.4

Cancel the common factor of $3$ .

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Step 4.2.3.4.4.1

Factor $3$ out of $3 x$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + \frac{4}{3} \cdot (3 (x)) + \frac{4}{3} \cdot - 1 + 6 - 6)} + 2}{2}$

Step 4.2.3.4.4.2

Cancel the common factor.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + \frac{4}{3} \cdot (3 x) + \frac{4}{3} \cdot - 1 + 6 - 6)} + 2}{2}$

Step 4.2.3.4.4.3

Rewrite the expression.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + 4 x + \frac{4}{3} \cdot - 1 + 6 - 6)} + 2}{2}$

Step 4.2.3.4.5

Multiply $\frac{4}{3} \cdot - 1$ .

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Step 4.2.3.4.5.1

Combine $\frac{4}{3}$ and $- 1$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + 4 x + \frac{4 \cdot - 1}{3} + 6 - 6)} + 2}{2}$

Step 4.2.3.4.5.2

Multiply $4$ by $- 1$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + 4 x + \frac{- 4}{3} + 6 - 6)} + 2}{2}$

Step 4.2.3.5

Move the negative in front of the fraction.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + 4 x - \frac{4}{3} + 6 - 6)} + 2}{2}$

Step 4.2.3.6

To write $6$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + 4 x - \frac{4}{3} + 6 \cdot \frac{3}{3} - 6)} + 2}{2}$

Step 4.2.3.7

Combine $6$ and $\frac{3}{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + 4 x - \frac{4}{3} + \frac{6 \cdot 3}{3} - 6)} + 2}{2}$

Step 4.2.3.8

Combine the numerators over the common denominator.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + 4 x + \frac{- 4 + 6 \cdot 3}{3} - 6)} + 2}{2}$

Step 4.2.3.9

Simplify the numerator.

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Step 4.2.3.9.1

Multiply $6$ by $3$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + 4 x + \frac{- 4 + 18}{3} - 6)} + 2}{2}$

Step 4.2.3.9.2

Add $- 4$ and $18$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + 4 x + \frac{14}{3} - 6)} + 2}{2}$

Step 4.2.3.10

To write $- 6$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + 4 x + \frac{14}{3} - 6 \cdot \frac{3}{3})} + 2}{2}$

Step 4.2.3.11

Combine $- 6$ and $\frac{3}{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + 4 x + \frac{14}{3} + \frac{- 6 \cdot 3}{3})} + 2}{2}$

Step 4.2.3.12

Combine the numerators over the common denominator.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + 4 x + \frac{14 - 6 \cdot 3}{3})} + 2}{2}$

Step 4.2.3.13

Simplify the numerator.

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Step 4.2.3.13.1

Multiply $- 6$ by $3$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + 4 x + \frac{14 - 18}{3})} + 2}{2}$

Step 4.2.3.13.2

Subtract $18$ from $14$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (\frac{4 x^{3}}{3} - 4 x^{2} + 4 x + \frac{- 4}{3})} + 2}{2}$

Step 4.2.3.14

Factor $4$ out of $\frac{4 x^{3}}{3} - 4 x^{2} + 4 x + \frac{- 4}{3}$ .

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Step 4.2.3.14.1

Factor $4$ out of $\frac{4 x^{3}}{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (4 (\frac{x^{3}}{3}) - 4 x^{2} + 4 x + \frac{- 4}{3})} + 2}{2}$

Step 4.2.3.14.2

Factor $4$ out of $- 4 x^{2}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (4 (\frac{x^{3}}{3}) + 4 (- x^{2}) + 4 x + \frac{- 4}{3})} + 2}{2}$

Step 4.2.3.14.3

Factor $4$ out of $4 x$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (4 (\frac{x^{3}}{3}) + 4 (- x^{2}) + 4 (x) + \frac{- 4}{3})} + 2}{2}$

Step 4.2.3.14.4

Factor $4$ out of $\frac{- 4}{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (4 (\frac{x^{3}}{3}) + 4 (- x^{2}) + 4 (x) + 4 (\frac{- 1}{3}))} + 2}{2}$

Step 4.2.3.14.5

Factor $4$ out of $4 \frac{x^{3}}{3} + 4 (- x^{2})$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (4 (\frac{x^{3}}{3} - x^{2}) + 4 (x) + 4 (\frac{- 1}{3}))} + 2}{2}$

Step 4.2.3.14.6

Factor $4$ out of $4 (\frac{x^{3}}{3} - x^{2}) + 4 (x)$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (4 (\frac{x^{3}}{3} - x^{2} + x) + 4 (\frac{- 1}{3}))} + 2}{2}$

Step 4.2.3.14.7

Factor $4$ out of $4 (\frac{x^{3}}{3} - x^{2} + x) + 4 (\frac{- 1}{3})$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 (4 (\frac{x^{3}}{3} - x^{2} + x + \frac{- 1}{3}))} + 2}{2}$

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{6 \cdot (4 (\frac{x^{3}}{3} - x^{2} + x + \frac{- 1}{3}))} + 2}{2}$

Step 4.2.3.15

Multiply $6$ by $4$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{3}}{3} - x^{2} + x + \frac{- 1}{3})} + 2}{2}$

Step 4.2.3.16

Move the negative in front of the fraction.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{3}}{3} - x^{2} + x - \frac{1}{3})} + 2}{2}$

Step 4.2.3.17

To write $- x^{2}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{3}}{3} - x^{2} \cdot \frac{3}{3} + x - \frac{1}{3})} + 2}{2}$

Step 4.2.3.18

Combine $- x^{2}$ and $\frac{3}{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{3}}{3} + \frac{- x^{2} \cdot 3}{3} + x - \frac{1}{3})} + 2}{2}$

Step 4.2.3.19

Combine the numerators over the common denominator.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{3} - x^{2} \cdot 3}{3} + x - \frac{1}{3})} + 2}{2}$

Step 4.2.3.20

Simplify the numerator.

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Step 4.2.3.20.1

Factor $x^{2}$ out of $x^{3} - x^{2} \cdot 3$ .

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Step 4.2.3.20.1.1

Factor $x^{2}$ out of $x^{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{2} x - x^{2} \cdot 3}{3} + x - \frac{1}{3})} + 2}{2}$

Step 4.2.3.20.1.2

Factor $x^{2}$ out of $- x^{2} \cdot 3$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{2} x + x^{2} (- 1 \cdot 3)}{3} + x - \frac{1}{3})} + 2}{2}$

Step 4.2.3.20.1.3

Factor $x^{2}$ out of $x^{2} x + x^{2} (- 1 \cdot 3)$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{2} (x - 1 \cdot 3)}{3} + x - \frac{1}{3})} + 2}{2}$

Step 4.2.3.20.2

Multiply $- 1$ by $3$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{2} (x - 3)}{3} + x - \frac{1}{3})} + 2}{2}$

Step 4.2.3.21

Find the common denominator.

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Step 4.2.3.21.1

Write $x$ as a fraction with denominator $1$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{2} (x - 3)}{3} + \frac{x}{1} - \frac{1}{3})} + 2}{2}$

Step 4.2.3.21.2

Multiply $\frac{x}{1}$ by $\frac{3}{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{2} (x - 3)}{3} + \frac{x}{1} \cdot \frac{3}{3} - \frac{1}{3})} + 2}{2}$

Step 4.2.3.21.3

Multiply $\frac{x}{1}$ by $\frac{3}{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{2} (x - 3)}{3} + \frac{x \cdot 3}{3} - \frac{1}{3})} + 2}{2}$

Step 4.2.3.22

Combine the numerators over the common denominator.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{2} (x - 3) + x \cdot 3 - 1}{3})} + 2}{2}$

Step 4.2.3.23

Move $3$ to the left of $x$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{2} (x - 3) + 3 x - 1}{3})} + 2}{2}$

Step 4.2.3.24

Simplify the numerator.

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Step 4.2.3.24.1

Apply the distributive property.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{2} x + x^{2} \cdot - 3 + 3 x - 1}{3})} + 2}{2}$

Step 4.2.3.24.2

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 4.2.3.24.2.1

Multiply $x^{2}$ by $x$ .

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Step 4.2.3.24.2.1.1

Raise $x$ to the power of $1$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{2} x + x^{2} \cdot - 3 + 3 x - 1}{3})} + 2}{2}$

Step 4.2.3.24.2.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{2 + 1} + x^{2} \cdot - 3 + 3 x - 1}{3})} + 2}{2}$

Step 4.2.3.24.2.2

Add $2$ and $1$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{3} + x^{2} \cdot - 3 + 3 x - 1}{3})} + 2}{2}$

Step 4.2.3.24.3

Move $- 3$ to the left of $x^{2}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{x^{3} - 3 \cdot x^{2} + 3 x - 1}{3})} + 2}{2}$

Step 4.2.3.24.4

Rewrite $x^{3} - 3 x^{2} + 3 x - 1$ in a factored form.

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Step 4.2.3.24.4.1

Factor $x^{3} - 3 x^{2} + 3 x - 1$ using the rational roots test.

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Step 4.2.3.24.4.1.1

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$p = \pm 1$

$q = \pm 1$

Step 4.2.3.24.4.1.2

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$\pm 1$

Step 4.2.3.24.4.1.3

Substitute $1$ and simplify the expression. In this case, the expression is equal to $0$ so $1$ is a root of the polynomial.

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Step 4.2.3.24.4.1.3.1

Substitute $1$ into the polynomial.

$1^{3} - 3 \cdot 1^{2} + 3 \cdot 1 - 1$

Step 4.2.3.24.4.1.3.2

Raise $1$ to the power of $3$ .

$1 - 3 \cdot 1^{2} + 3 \cdot 1 - 1$

Step 4.2.3.24.4.1.3.3

Raise $1$ to the power of $2$ .

$1 - 3 \cdot 1 + 3 \cdot 1 - 1$

Step 4.2.3.24.4.1.3.4

Multiply $- 3$ by $1$ .

$1 - 3 + 3 \cdot 1 - 1$

Step 4.2.3.24.4.1.3.5

Subtract $3$ from $1$ .

$- 2 + 3 \cdot 1 - 1$

Step 4.2.3.24.4.1.3.6

Multiply $3$ by $1$ .

$- 2 + 3 - 1$

Step 4.2.3.24.4.1.3.7

Add $- 2$ and $3$ .

$1 - 1$

Step 4.2.3.24.4.1.3.8

Subtract $1$ from $1$ .

$0$

Step 4.2.3.24.4.1.4

Since $1$ is a known root, divide the polynomial by $x - 1$ to find the quotient polynomial. This polynomial can then be used to find the remaining roots.

$\frac{x^{3} - 3 x^{2} + 3 x - 1}{x - 1}$

Step 4.2.3.24.4.1.5

Divide $x^{3} - 3 x^{2} + 3 x - 1$ by $x - 1$ .

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Step 4.2.3.24.4.1.5.1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x$

$1$

$x^{3}$

$3 x^{2}$

$3 x$

$1$

Step 4.2.3.24.4.1.5.2

Divide the highest order term in the dividend $x^{3}$ by the highest order term in divisor $x$ .

					$x^{2}$
	$x$	-	$1$		$x^{3}$	-	$3 x^{2}$	+	$3 x$	-	$1$

Step 4.2.3.24.4.1.5.3

Multiply the new quotient term by the divisor.

				$x^{2}$
$x$	-	$1$		$x^{3}$	-	$3 x^{2}$	+	$3 x$	-	$1$
			+	$x^{3}$	-	$x^{2}$

Step 4.2.3.24.4.1.5.4

The expression needs to be subtracted from the dividend, so change all the signs in $x^{3} - x^{2}$

				$x^{2}$
$x$	-	$1$		$x^{3}$	-	$3 x^{2}$	+	$3 x$	-	$1$
			-	$x^{3}$	+	$x^{2}$

Step 4.2.3.24.4.1.5.5

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$
$x$	-	$1$		$x^{3}$	-	$3 x^{2}$	+	$3 x$	-	$1$
			-	$x^{3}$	+	$x^{2}$
					-	$2 x^{2}$

Step 4.2.3.24.4.1.5.6

Pull the next terms from the original dividend down into the current dividend.

				$x^{2}$
$x$	-	$1$		$x^{3}$	-	$3 x^{2}$	+	$3 x$	-	$1$
			-	$x^{3}$	+	$x^{2}$
					-	$2 x^{2}$	+	$3 x$

Step 4.2.3.24.4.1.5.7

Divide the highest order term in the dividend $- 2 x^{2}$ by the highest order term in divisor $x$ .

				$x^{2}$	-	$2 x$
$x$	-	$1$		$x^{3}$	-	$3 x^{2}$	+	$3 x$	-	$1$
			-	$x^{3}$	+	$x^{2}$
					-	$2 x^{2}$	+	$3 x$

Step 4.2.3.24.4.1.5.8

Multiply the new quotient term by the divisor.

				$x^{2}$	-	$2 x$
$x$	-	$1$		$x^{3}$	-	$3 x^{2}$	+	$3 x$	-	$1$
			-	$x^{3}$	+	$x^{2}$
					-	$2 x^{2}$	+	$3 x$
					-	$2 x^{2}$	+	$2 x$

Step 4.2.3.24.4.1.5.9

The expression needs to be subtracted from the dividend, so change all the signs in $- 2 x^{2} + 2 x$

				$x^{2}$	-	$2 x$
$x$	-	$1$		$x^{3}$	-	$3 x^{2}$	+	$3 x$	-	$1$
			-	$x^{3}$	+	$x^{2}$
					-	$2 x^{2}$	+	$3 x$
					+	$2 x^{2}$	-	$2 x$

Step 4.2.3.24.4.1.5.10

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$	-	$2 x$
$x$	-	$1$		$x^{3}$	-	$3 x^{2}$	+	$3 x$	-	$1$
			-	$x^{3}$	+	$x^{2}$
					-	$2 x^{2}$	+	$3 x$
					+	$2 x^{2}$	-	$2 x$
							+	$x$

Step 4.2.3.24.4.1.5.11

Pull the next terms from the original dividend down into the current dividend.

				$x^{2}$	-	$2 x$
$x$	-	$1$		$x^{3}$	-	$3 x^{2}$	+	$3 x$	-	$1$
			-	$x^{3}$	+	$x^{2}$
					-	$2 x^{2}$	+	$3 x$
					+	$2 x^{2}$	-	$2 x$
							+	$x$	-	$1$

Step 4.2.3.24.4.1.5.12

Divide the highest order term in the dividend $x$ by the highest order term in divisor $x$ .

				$x^{2}$	-	$2 x$	+	$1$
$x$	-	$1$		$x^{3}$	-	$3 x^{2}$	+	$3 x$	-	$1$
			-	$x^{3}$	+	$x^{2}$
					-	$2 x^{2}$	+	$3 x$
					+	$2 x^{2}$	-	$2 x$
							+	$x$	-	$1$

Step 4.2.3.24.4.1.5.13

Multiply the new quotient term by the divisor.

				$x^{2}$	-	$2 x$	+	$1$
$x$	-	$1$		$x^{3}$	-	$3 x^{2}$	+	$3 x$	-	$1$
			-	$x^{3}$	+	$x^{2}$
					-	$2 x^{2}$	+	$3 x$
					+	$2 x^{2}$	-	$2 x$
							+	$x$	-	$1$
							+	$x$	-	$1$

Step 4.2.3.24.4.1.5.14

The expression needs to be subtracted from the dividend, so change all the signs in $x - 1$

				$x^{2}$	-	$2 x$	+	$1$
$x$	-	$1$		$x^{3}$	-	$3 x^{2}$	+	$3 x$	-	$1$
			-	$x^{3}$	+	$x^{2}$
					-	$2 x^{2}$	+	$3 x$
					+	$2 x^{2}$	-	$2 x$
							+	$x$	-	$1$
							-	$x$	+	$1$

Step 4.2.3.24.4.1.5.15

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$	-	$2 x$	+	$1$
$x$	-	$1$		$x^{3}$	-	$3 x^{2}$	+	$3 x$	-	$1$
			-	$x^{3}$	+	$x^{2}$
					-	$2 x^{2}$	+	$3 x$
					+	$2 x^{2}$	-	$2 x$
							+	$x$	-	$1$
							-	$x$	+	$1$
										$0$

Step 4.2.3.24.4.1.5.16

Since the remander is $0$ , the final answer is the quotient.

$x^{2} - 2 x + 1$

Step 4.2.3.24.4.1.6

Write $x^{3} - 3 x^{2} + 3 x - 1$ as a set of factors.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{(x - 1) (x^{2} - 2 x + 1)}{3})} + 2}{2}$

Step 4.2.3.24.4.2

Factor using the perfect square rule.

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Step 4.2.3.24.4.2.1

Rewrite $1$ as $1^{2}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{(x - 1) (x^{2} - 2 x + 1^{2})}{3})} + 2}{2}$

Step 4.2.3.24.4.2.2

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$2 x = 2 \cdot x \cdot 1$

Step 4.2.3.24.4.2.3

Rewrite the polynomial.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{(x - 1) (x^{2} - 2 \cdot x \cdot 1 + 1^{2})}{3})} + 2}{2}$

Step 4.2.3.24.4.2.4

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = x$ and $b = 1$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{(x - 1) {(x - 1)}^{2}}{3})} + 2}{2}$

Step 4.2.3.24.4.3

Combine like factors.

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Step 4.2.3.24.4.3.1

Raise $x - 1$ to the power of $1$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{(x - 1) {(x - 1)}^{2}}{3})} + 2}{2}$

Step 4.2.3.24.4.3.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{{(x - 1)}^{1 + 2}}{3})} + 2}{2}$

Step 4.2.3.24.4.3.3

Add $1$ and $2$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{24 (\frac{{(x - 1)}^{3}}{3})} + 2}{2}$

Step 4.2.3.25

Combine $24$ and $\frac{{(x - 1)}^{3}}{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{\frac{24 {(x - 1)}^{3}}{3}} + 2}{2}$

Step 4.2.3.26

Reduce the expression by cancelling the common factors.

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Step 4.2.3.26.1

Reduce the expression $\frac{24 {(x - 1)}^{3}}{3}$ by cancelling the common factors.

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Step 4.2.3.26.1.1

Factor $3$ out of $24 {(x - 1)}^{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{\frac{3 (8 {(x - 1)}^{3})}{3}} + 2}{2}$

Step 4.2.3.26.1.2

Factor $3$ out of $3$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{\frac{3 (8 {(x - 1)}^{3})}{3 (1)}} + 2}{2}$

Step 4.2.3.26.1.3

Cancel the common factor.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{\frac{3 (8 {(x - 1)}^{3})}{3 \cdot 1}} + 2}{2}$

Step 4.2.3.26.1.4

Rewrite the expression.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{\frac{8 {(x - 1)}^{3}}{1}} + 2}{2}$

Step 4.2.3.26.2

Divide $8 {(x - 1)}^{3}$ by $1$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{8 {(x - 1)}^{3}} + 2}{2}$

Step 4.2.3.27

Rewrite $8 {(x - 1)}^{3}$ as ${(2 (x - 1))}^{3}$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{\sqrt[3]{{(2 (x - 1))}^{3}} + 2}{2}$

Step 4.2.3.28

Pull terms out from under the radical, assuming real numbers.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{2 (x - 1) + 2}{2}$

Step 4.2.3.29

Apply the distributive property.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{2 x + 2 \cdot - 1 + 2}{2}$

Step 4.2.3.30

Multiply $2$ by $- 1$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{2 x - 2 + 2}{2}$

Step 4.2.3.31

Add $- 2$ and $2$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{2 x + 0}{2}$

Step 4.2.3.32

Add $2 x$ and $0$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{2 x}{2}$

Step 4.2.4

Cancel the common factor of $2$ .

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Step 4.2.4.1

Cancel the common factor.

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = \frac{2 x}{2}$

Step 4.2.4.2

Divide $x$ by $1$ .

$f^{- 1} (\frac{4}{3} \cdot {(x - 1)}^{3} + 6) = x$

Step 4.3

Evaluate $f (f^{- 1} (x))$ .

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Step 4.3.1

Set up the composite result function.

$f (f^{- 1} (x))$

Step 4.3.2

Evaluate $f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2})$ by substituting in the value of $f^{- 1}$ into $f$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot {((\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) - 1)}^{3} + 6$

Step 4.3.3

Simplify each term.

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Step 4.3.3.1

Use the Binomial Theorem.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot ({(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{3} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2

Simplify each term.

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Step 4.3.3.2.1

Apply the product rule to $\frac{\sqrt[3]{6 (x - 6)} + 2}{2}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{{(\sqrt[3]{6 (x - 6)} + 2)}^{3}}{2^{3}} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.2

Raise $2$ to the power of $3$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{{(\sqrt[3]{6 (x - 6)} + 2)}^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3

Simplify ${(\sqrt[3]{6 (x - 6)} + 2)}^{3}$ .

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Step 4.3.3.2.3.1

Use the Binomial Theorem.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{{\sqrt[3]{6 (x - 6)}}^{3} + 3 {\sqrt[3]{6 (x - 6)}}^{2} \cdot 2 + 3 \sqrt[3]{6 (x - 6)} \cdot 2^{2} + 2^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.2

Simplify each term.

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Step 4.3.3.2.3.2.1

Rewrite ${\sqrt[3]{6 (x - 6)}}^{3}$ as $6 (x - 6)$ .

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Step 4.3.3.2.3.2.1.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{6 (x - 6)}$ as ${(6 (x - 6))}^{\frac{1}{3}}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{{({(6 (x - 6))}^{\frac{1}{3}})}^{3} + 3 {\sqrt[3]{6 (x - 6)}}^{2} \cdot 2 + 3 \sqrt[3]{6 (x - 6)} \cdot 2^{2} + 2^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.2.1.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{{(6 (x - 6))}^{\frac{1}{3} \cdot 3} + 3 {\sqrt[3]{6 (x - 6)}}^{2} \cdot 2 + 3 \sqrt[3]{6 (x - 6)} \cdot 2^{2} + 2^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.2.1.3

Combine $\frac{1}{3}$ and $3$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{{(6 (x - 6))}^{\frac{3}{3}} + 3 {\sqrt[3]{6 (x - 6)}}^{2} \cdot 2 + 3 \sqrt[3]{6 (x - 6)} \cdot 2^{2} + 2^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.2.1.4

Cancel the common factor of $3$ .

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Step 4.3.3.2.3.2.1.4.1

Cancel the common factor.

Step 4.3.3.2.3.2.1.4.2

Rewrite the expression.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{(6 (x - 6)) + 3 {\sqrt[3]{6 (x - 6)}}^{2} \cdot 2 + 3 \sqrt[3]{6 (x - 6)} \cdot 2^{2} + 2^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.2.1.5

Simplify.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{6 (x - 6) + 3 {\sqrt[3]{6 (x - 6)}}^{2} \cdot 2 + 3 \sqrt[3]{6 (x - 6)} \cdot 2^{2} + 2^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.2.2

Apply the distributive property.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{6 x + 6 \cdot - 6 + 3 {\sqrt[3]{6 (x - 6)}}^{2} \cdot 2 + 3 \sqrt[3]{6 (x - 6)} \cdot 2^{2} + 2^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.2.3

Multiply $6$ by $- 6$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{6 x - 36 + 3 {\sqrt[3]{6 (x - 6)}}^{2} \cdot 2 + 3 \sqrt[3]{6 (x - 6)} \cdot 2^{2} + 2^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.2.4

Rewrite ${\sqrt[3]{6 (x - 6)}}^{2}$ as $\sqrt[3]{{(6 (x - 6))}^{2}}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{6 x - 36 + 3 \sqrt[3]{{(6 (x - 6))}^{2}} \cdot 2 + 3 \sqrt[3]{6 (x - 6)} \cdot 2^{2} + 2^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.2.5

Apply the product rule to $6 (x - 6)$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{6 x - 36 + 3 \sqrt[3]{6^{2} {(x - 6)}^{2}} \cdot 2 + 3 \sqrt[3]{6 (x - 6)} \cdot 2^{2} + 2^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.2.6

Raise $6$ to the power of $2$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{6 x - 36 + 3 \sqrt[3]{36 {(x - 6)}^{2}} \cdot 2 + 3 \sqrt[3]{6 (x - 6)} \cdot 2^{2} + 2^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.2.7

Multiply $2$ by $3$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{6 x - 36 + 6 \sqrt[3]{36 {(x - 6)}^{2}} + 3 \sqrt[3]{6 (x - 6)} \cdot 2^{2} + 2^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.2.8

Raise $2$ to the power of $2$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{6 x - 36 + 6 \sqrt[3]{36 {(x - 6)}^{2}} + 3 \sqrt[3]{6 (x - 6)} \cdot 4 + 2^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.2.9

Multiply $4$ by $3$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{6 x - 36 + 6 \sqrt[3]{36 {(x - 6)}^{2}} + 12 \sqrt[3]{6 (x - 6)} + 2^{3}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.2.10

Raise $2$ to the power of $3$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{6 x - 36 + 6 \sqrt[3]{36 {(x - 6)}^{2}} + 12 \sqrt[3]{6 (x - 6)} + 8}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.3.3

Add $- 36$ and $8$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{6 x - 28 + 6 \sqrt[3]{36 {(x - 6)}^{2}} + 12 \sqrt[3]{6 (x - 6)}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.4

Cancel the common factor of $6 x - 28 + 6 \sqrt[3]{36 {(x - 6)}^{2}} + 12 \sqrt[3]{6 (x - 6)}$ and $8$ .

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Step 4.3.3.2.4.1

Factor $2$ out of $6 x$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{2 (3 x) - 28 + 6 \sqrt[3]{36 {(x - 6)}^{2}} + 12 \sqrt[3]{6 (x - 6)}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.4.2

Factor $2$ out of $- 28$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{2 (3 x) + 2 (- 14) + 6 \sqrt[3]{36 {(x - 6)}^{2}} + 12 \sqrt[3]{6 (x - 6)}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.4.3

Factor $2$ out of $2 (3 x) + 2 (- 14)$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{2 (3 x - 14) + 6 \sqrt[3]{36 {(x - 6)}^{2}} + 12 \sqrt[3]{6 (x - 6)}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.4.4

Factor $2$ out of $6 \sqrt[3]{36 {(x - 6)}^{2}}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{2 (3 x - 14) + 2 (3 \sqrt[3]{36 {(x - 6)}^{2}}) + 12 \sqrt[3]{6 (x - 6)}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.4.5

Factor $2$ out of $2 (3 x - 14) + 2 (3 \sqrt[3]{36 {(x - 6)}^{2}})$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{2 (3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}}) + 12 \sqrt[3]{6 (x - 6)}}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.4.6

Factor $2$ out of $12 \sqrt[3]{6 (x - 6)}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{2 (3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}}) + 2 (6 \sqrt[3]{6 (x - 6)})}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.4.7

Factor $2$ out of $2 (3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}}) + 2 (6 \sqrt[3]{6 (x - 6)})$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{2 (3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)})}{8} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.4.8

Cancel the common factors.

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Step 4.3.3.2.4.8.1

Factor $2$ out of $8$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{2 (3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)})}{2 (4)} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.4.8.2

Cancel the common factor.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{2 (3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)})}{2 \cdot 4} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.4.8.3

Rewrite the expression.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)}}{4} + 3 {(\frac{\sqrt[3]{6 (x - 6)} + 2}{2})}^{2} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.5

Apply the product rule to $\frac{\sqrt[3]{6 (x - 6)} + 2}{2}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)}}{4} + 3 (\frac{{(\sqrt[3]{6 (x - 6)} + 2)}^{2}}{2^{2}}) \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.6

Raise $2$ to the power of $2$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)}}{4} + 3 (\frac{{(\sqrt[3]{6 (x - 6)} + 2)}^{2}}{4}) \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.7

Combine $3$ and $\frac{{(\sqrt[3]{6 (x - 6)} + 2)}^{2}}{4}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)}}{4} + \frac{3 {(\sqrt[3]{6 (x - 6)} + 2)}^{2}}{4} \cdot - 1 + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.8

Multiply $\frac{3 {(\sqrt[3]{6 (x - 6)} + 2)}^{2}}{4} \cdot - 1$ .

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Step 4.3.3.2.8.1

Combine $\frac{3 {(\sqrt[3]{6 (x - 6)} + 2)}^{2}}{4}$ and $- 1$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)}}{4} + \frac{3 {(\sqrt[3]{6 (x - 6)} + 2)}^{2} \cdot - 1}{4} + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.8.2

Multiply $- 1$ by $3$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)}}{4} + \frac{- 3 {(\sqrt[3]{6 (x - 6)} + 2)}^{2}}{4} + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.9

Move the negative in front of the fraction.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)}}{4} - \frac{(3) {(\sqrt[3]{6 (x - 6)} + 2)}^{2}}{4} + 3 (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.10

Combine $3$ and $\frac{\sqrt[3]{6 (x - 6)} + 2}{2}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)}}{4} - \frac{3 {(\sqrt[3]{6 (x - 6)} + 2)}^{2}}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} \cdot {(- 1)}^{2} + {(- 1)}^{3}) + 6$

Step 4.3.3.2.11

Raise $- 1$ to the power of $2$ .

Step 4.3.3.2.12

Multiply $\frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2}$ by $1$ .

Step 4.3.3.2.13

Raise $- 1$ to the power of $3$ .

Step 4.3.3.3

Combine the numerators over the common denominator.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 {(\sqrt[3]{6 (x - 6)} + 2)}^{2}}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4

Simplify the numerator.

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Step 4.3.3.4.1

Rewrite ${(\sqrt[3]{6 (x - 6)} + 2)}^{2}$ as $(\sqrt[3]{6 (x - 6)} + 2) (\sqrt[3]{6 (x - 6)} + 2)$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 ((\sqrt[3]{6 (x - 6)} + 2) (\sqrt[3]{6 (x - 6)} + 2))}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.2

Expand $(\sqrt[3]{6 (x - 6)} + 2) (\sqrt[3]{6 (x - 6)} + 2)$ using the FOIL Method.

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Step 4.3.3.4.2.1

Apply the distributive property.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 (\sqrt[3]{6 (x - 6)} (\sqrt[3]{6 (x - 6)} + 2) + 2 (\sqrt[3]{6 (x - 6)} + 2))}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.2.2

Apply the distributive property.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 (\sqrt[3]{6 (x - 6)} \sqrt[3]{6 (x - 6)} + \sqrt[3]{6 (x - 6)} \cdot 2 + 2 (\sqrt[3]{6 (x - 6)} + 2))}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.2.3

Apply the distributive property.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 (\sqrt[3]{6 (x - 6)} \sqrt[3]{6 (x - 6)} + \sqrt[3]{6 (x - 6)} \cdot 2 + 2 \sqrt[3]{6 (x - 6)} + 2 \cdot 2)}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.3

Simplify and combine like terms.

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Step 4.3.3.4.3.1

Simplify each term.

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Step 4.3.3.4.3.1.1

Multiply $\sqrt[3]{6 (x - 6)} \sqrt[3]{6 (x - 6)}$ .

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Step 4.3.3.4.3.1.1.1

Raise $\sqrt[3]{6 (x - 6)}$ to the power of $1$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 (\sqrt[3]{6 (x - 6)} \sqrt[3]{6 (x - 6)} + \sqrt[3]{6 (x - 6)} \cdot 2 + 2 \sqrt[3]{6 (x - 6)} + 2 \cdot 2)}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.3.1.1.2

Raise $\sqrt[3]{6 (x - 6)}$ to the power of $1$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 (\sqrt[3]{6 (x - 6)} \sqrt[3]{6 (x - 6)} + \sqrt[3]{6 (x - 6)} \cdot 2 + 2 \sqrt[3]{6 (x - 6)} + 2 \cdot 2)}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.3.1.1.3

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 ({\sqrt[3]{6 (x - 6)}}^{1 + 1} + \sqrt[3]{6 (x - 6)} \cdot 2 + 2 \sqrt[3]{6 (x - 6)} + 2 \cdot 2)}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.3.1.1.4

Add $1$ and $1$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 ({\sqrt[3]{6 (x - 6)}}^{2} + \sqrt[3]{6 (x - 6)} \cdot 2 + 2 \sqrt[3]{6 (x - 6)} + 2 \cdot 2)}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.3.1.2

Rewrite ${\sqrt[3]{6 (x - 6)}}^{2}$ as $\sqrt[3]{{(6 (x - 6))}^{2}}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 (\sqrt[3]{{(6 (x - 6))}^{2}} + \sqrt[3]{6 (x - 6)} \cdot 2 + 2 \sqrt[3]{6 (x - 6)} + 2 \cdot 2)}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.3.1.3

Apply the product rule to $6 (x - 6)$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 (\sqrt[3]{6^{2} {(x - 6)}^{2}} + \sqrt[3]{6 (x - 6)} \cdot 2 + 2 \sqrt[3]{6 (x - 6)} + 2 \cdot 2)}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.3.1.4

Raise $6$ to the power of $2$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 (\sqrt[3]{36 {(x - 6)}^{2}} + \sqrt[3]{6 (x - 6)} \cdot 2 + 2 \sqrt[3]{6 (x - 6)} + 2 \cdot 2)}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.3.1.5

Move $2$ to the left of $\sqrt[3]{6 (x - 6)}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 (\sqrt[3]{36 {(x - 6)}^{2}} + 2 \cdot \sqrt[3]{6 (x - 6)} + 2 \sqrt[3]{6 (x - 6)} + 2 \cdot 2)}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.3.1.6

Multiply $2$ by $2$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 (\sqrt[3]{36 {(x - 6)}^{2}} + 2 \sqrt[3]{6 (x - 6)} + 2 \sqrt[3]{6 (x - 6)} + 4)}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.3.2

Add $2 \sqrt[3]{6 (x - 6)}$ and $2 \sqrt[3]{6 (x - 6)}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 (\sqrt[3]{36 {(x - 6)}^{2}} + 4 \sqrt[3]{6 (x - 6)} + 4)}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.4

Apply the distributive property.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 \sqrt[3]{36 {(x - 6)}^{2}} - 3 (4 \sqrt[3]{6 (x - 6)}) - 3 \cdot 4}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.5

Simplify.

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Step 4.3.3.4.5.1

Multiply $4$ by $- 3$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 \sqrt[3]{36 {(x - 6)}^{2}} - 12 \sqrt[3]{6 (x - 6)} - 3 \cdot 4}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.5.2

Multiply $- 3$ by $4$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 \sqrt[3]{36 {(x - 6)}^{2}} - 12 \sqrt[3]{6 (x - 6)} - 12}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.6

Subtract $12$ from $- 14$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 26 + 3 \sqrt[3]{36 {(x - 6)}^{2}} + 6 \sqrt[3]{6 (x - 6)} - 3 \sqrt[3]{36 {(x - 6)}^{2}} - 12 \sqrt[3]{6 (x - 6)}}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.7

Subtract $3 \sqrt[3]{36 {(x - 6)}^{2}}$ from $3 \sqrt[3]{36 {(x - 6)}^{2}}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 26 + 0 + 6 \sqrt[3]{6 (x - 6)} - 12 \sqrt[3]{6 (x - 6)}}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.8

Add $3 x$ and $0$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 26 + 6 \sqrt[3]{6 (x - 6)} - 12 \sqrt[3]{6 (x - 6)}}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.4.9

Subtract $12 \sqrt[3]{6 (x - 6)}$ from $6 \sqrt[3]{6 (x - 6)}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 26 - 6 \sqrt[3]{6 (x - 6)}}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} - 1) + 6$

Step 4.3.3.5

To write $\frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 26 - 6 \sqrt[3]{6 (x - 6)}}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2} \cdot \frac{2}{2} - 1) + 6$

Step 4.3.3.6

Write each expression with a common denominator of $4$ , by multiplying each by an appropriate factor of $1$ .

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Step 4.3.3.6.1

Multiply $\frac{3 (\sqrt[3]{6 (x - 6)} + 2)}{2}$ by $\frac{2}{2}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 26 - 6 \sqrt[3]{6 (x - 6)}}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2) \cdot 2}{2 \cdot 2} - 1) + 6$

Step 4.3.3.6.2

Multiply $2$ by $2$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 26 - 6 \sqrt[3]{6 (x - 6)}}{4} + \frac{3 (\sqrt[3]{6 (x - 6)} + 2) \cdot 2}{4} - 1) + 6$

Step 4.3.3.7

Combine the numerators over the common denominator.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 26 - 6 \sqrt[3]{6 (x - 6)} + 3 (\sqrt[3]{6 (x - 6)} + 2) \cdot 2}{4} - 1) + 6$

Step 4.3.3.8

Simplify the numerator.

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Step 4.3.3.8.1

Apply the distributive property.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 26 - 6 \sqrt[3]{6 (x - 6)} + (3 \sqrt[3]{6 (x - 6)} + 3 \cdot 2) \cdot 2}{4} - 1) + 6$

Step 4.3.3.8.2

Multiply $3$ by $2$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 26 - 6 \sqrt[3]{6 (x - 6)} + (3 \sqrt[3]{6 (x - 6)} + 6) \cdot 2}{4} - 1) + 6$

Step 4.3.3.8.3

Apply the distributive property.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 26 - 6 \sqrt[3]{6 (x - 6)} + 3 \sqrt[3]{6 (x - 6)} \cdot 2 + 6 \cdot 2}{4} - 1) + 6$

Step 4.3.3.8.4

Multiply $2$ by $3$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 26 - 6 \sqrt[3]{6 (x - 6)} + 6 \sqrt[3]{6 (x - 6)} + 6 \cdot 2}{4} - 1) + 6$

Step 4.3.3.8.5

Multiply $6$ by $2$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 26 - 6 \sqrt[3]{6 (x - 6)} + 6 \sqrt[3]{6 (x - 6)} + 12}{4} - 1) + 6$

Step 4.3.3.8.6

Add $- 26$ and $12$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 - 6 \sqrt[3]{6 (x - 6)} + 6 \sqrt[3]{6 (x - 6)}}{4} - 1) + 6$

Step 4.3.3.8.7

Add $- 6 \sqrt[3]{6 (x - 6)}$ and $6 \sqrt[3]{6 (x - 6)}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14 + 0}{4} - 1) + 6$

Step 4.3.3.8.8

Add $3 x - 14$ and $0$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14}{4} - 1) + 6$

Step 4.3.3.9

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14}{4} - 1 \cdot \frac{4}{4}) + 6$

Step 4.3.3.10

Combine $- 1$ and $\frac{4}{4}$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot (\frac{3 x - 14}{4} + \frac{- 1 \cdot 4}{4}) + 6$

Step 4.3.3.11

Combine the numerators over the common denominator.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot \frac{3 x - 14 - 1 \cdot 4}{4} + 6$

Step 4.3.3.12

Simplify the numerator.

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Step 4.3.3.12.1

Multiply $- 1$ by $4$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot \frac{3 x - 14 - 4}{4} + 6$

Step 4.3.3.12.2

Subtract $4$ from $- 14$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot \frac{3 x - 18}{4} + 6$

Step 4.3.3.12.3

Factor $3$ out of $3 x - 18$ .

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Step 4.3.3.12.3.1

Factor $3$ out of $3 x$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot \frac{3 (x) - 18}{4} + 6$

Step 4.3.3.12.3.2

Factor $3$ out of $- 18$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot \frac{3 x + 3 \cdot - 6}{4} + 6$

Step 4.3.3.12.3.3

Factor $3$ out of $3 x + 3 \cdot - 6$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot \frac{3 (x - 6)}{4} + 6$

Step 4.3.3.13

Cancel the common factor of $4$ .

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Step 4.3.3.13.1

Cancel the common factor.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{4}{3} \cdot \frac{3 (x - 6)}{4} + 6$

Step 4.3.3.13.2

Rewrite the expression.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{1}{3} \cdot (3 (x - 6)) + 6$

Step 4.3.3.14

Cancel the common factor of $3$ .

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Step 4.3.3.14.1

Cancel the common factor.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = \frac{1}{3} \cdot (3 (x - 6)) + 6$

Step 4.3.3.14.2

Rewrite the expression.

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = x - 6 + 6$

Step 4.3.4

Combine the opposite terms in $x - 6 + 6$ .

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Step 4.3.4.1

Add $- 6$ and $6$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = x + 0$

Step 4.3.4.2

Add $x$ and $0$ .

$f (\frac{\sqrt[3]{6 (x - 6)} + 2}{2}) = x$

Step 4.4

Since $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ , then $f^{- 1} (x) = \frac{\sqrt[3]{6 (x - 6)} + 2}{2}$ is the inverse of $f (x) = \frac{4}{3} \cdot {(x - 1)}^{3} + 6$ .

$f^{- 1} (x) = \frac{\sqrt[3]{6 (x - 6)} + 2}{2}$