Algebra Examples

$F (X) = 10 X$ , $G (X) = X + 3$

Step 1

Set up the composite result function.

$F (G (X))$

Step 2

Evaluate $F (X + 3)$ by substituting in the value of $G$ into $F$ .

$F (X + 3) = 10 (X + 3)$

Step 3

Apply the distributive property.

$F (X + 3) = 10 X + 10 \cdot 3$

Step 4

Multiply $10$ by $3$ .

$F (X + 3) = 10 X + 30$