Algebra Examples

${(\frac{1}{16})}^{x + 7} \cdot 64^{x + 5} = {(\frac{1}{32})}^{4}$

Step 1

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

$\ln ({(\frac{1}{16})}^{x + 7} \cdot 64^{x + 5}) = \ln ({(\frac{1}{32})}^{4})$

Step 2

Expand the left side.

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Step 2.1

Rewrite $\ln ({(\frac{1}{16})}^{x + 7} \cdot 64^{x + 5})$ as $\ln ({(\frac{1}{16})}^{x + 7}) + \ln (64^{x + 5})$ .

$\ln ({(\frac{1}{16})}^{x + 7}) + \ln (64^{x + 5}) = \ln ({(\frac{1}{32})}^{4})$

Step 2.2

Expand $\ln ({(\frac{1}{16})}^{x + 7})$ by moving $x + 7$ outside the logarithm.

$(x + 7) \ln (\frac{1}{16}) + \ln (64^{x + 5}) = \ln ({(\frac{1}{32})}^{4})$

Step 2.3

Expand $\ln (64^{x + 5})$ by moving $x + 5$ outside the logarithm.

$(x + 7) \ln (\frac{1}{16}) + (x + 5) \ln (64) = \ln ({(\frac{1}{32})}^{4})$

Step 2.4

Rewrite $\ln (\frac{1}{16})$ as $\ln (1) - \ln (16)$ .

$(x + 7) (\ln (1) - \ln (16)) + (x + 5) \ln (64) = \ln ({(\frac{1}{32})}^{4})$

Step 2.5

The natural logarithm of $1$ is $0$ .

$(x + 7) (0 - \ln (16)) + (x + 5) \ln (64) = \ln ({(\frac{1}{32})}^{4})$

Step 2.6

Rewrite $\ln (16)$ as $\ln (2^{4})$ .

$(x + 7) (0 - \ln (2^{4})) + (x + 5) \ln (64) = \ln ({(\frac{1}{32})}^{4})$

Step 2.7

Expand $\ln (2^{4})$ by moving $4$ outside the logarithm.

$(x + 7) (0 - (4 \ln (2))) + (x + 5) \ln (64) = \ln ({(\frac{1}{32})}^{4})$

Step 2.8

Multiply $4$ by $- 1$ .

$(x + 7) (0 - 4 \ln (2)) + (x + 5) \ln (64) = \ln ({(\frac{1}{32})}^{4})$

Step 2.9

Subtract $4 \ln (2)$ from $0$ .

$(x + 7) (- 4 \ln (2)) + (x + 5) \ln (64) = \ln ({(\frac{1}{32})}^{4})$

Step 3

Simplify the left side.

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Step 3.1

Simplify $(x + 7) (- 4 \ln (2)) + (x + 5) \ln (64)$ .

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Step 3.1.1

Simplify each term.

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Step 3.1.1.1

Apply the distributive property.

$x (- 4 \ln (2)) + 7 (- 4 \ln (2)) + (x + 5) \ln (64) = \ln ({(\frac{1}{32})}^{4})$

Step 3.1.1.2

Multiply $- 4$ by $7$ .

$x (- 4 \ln (2)) - 28 \ln (2) + (x + 5) \ln (64) = \ln ({(\frac{1}{32})}^{4})$

Step 3.1.1.3

Apply the distributive property.

$x (- 4 \ln (2)) - 28 \ln (2) + x \ln (64) + 5 \ln (64) = \ln ({(\frac{1}{32})}^{4})$

Step 3.1.2

Reorder factors in $x (- 4 \ln (2)) - 28 \ln (2) + x \ln (64) + 5 \ln (64)$ .

$- 4 x \ln (2) - 28 \ln (2) + x \ln (64) + 5 \ln (64) = \ln ({(\frac{1}{32})}^{4})$

Step 4

Simplify the right side.

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Step 4.1

Simplify $\ln ({(\frac{1}{32})}^{4})$ .

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Step 4.1.1

Apply the product rule to $\frac{1}{32}$ .

$- 4 x \ln (2) - 28 \ln (2) + x \ln (64) + 5 \ln (64) = \ln (\frac{1^{4}}{32^{4}})$

Step 4.1.2

One to any power is one.

$- 4 x \ln (2) - 28 \ln (2) + x \ln (64) + 5 \ln (64) = \ln (\frac{1}{32^{4}})$

Step 4.1.3

Raise $32$ to the power of $4$ .

$- 4 x \ln (2) - 28 \ln (2) + x \ln (64) + 5 \ln (64) = \ln (\frac{1}{1048576})$

Step 5

Move $- 28 \ln (2)$ .

$- 4 x \ln (2) + x \ln (64) - 28 \ln (2) + 5 \ln (64) = \ln (\frac{1}{1048576})$

Step 6

Move all the terms containing a logarithm to the left side of the equation.

$- 4 x \ln (2) + x \ln (64) - 28 \ln (2) + 5 \ln (64) - \ln (\frac{1}{1048576}) = 0$

Step 7

Move all terms not containing $x$ to the right side of the equation.

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Step 7.1

Add $28 \ln (2)$ to both sides of the equation.

$- 4 x \ln (2) + x \ln (64) + 5 \ln (64) - \ln (\frac{1}{1048576}) = 28 \ln (2)$

Step 7.2

Subtract $5 \ln (64)$ from both sides of the equation.

$- 4 x \ln (2) + x \ln (64) - \ln (\frac{1}{1048576}) = 28 \ln (2) - 5 \ln (64)$

Step 7.3

Add $\ln (\frac{1}{1048576})$ to both sides of the equation.

$- 4 x \ln (2) + x \ln (64) = 28 \ln (2) - 5 \ln (64) + \ln (\frac{1}{1048576})$

Step 8

Factor $x$ out of $- 4 x \ln (2) + x \ln (64)$ .

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Step 8.1

Factor $x$ out of $- 4 x \ln (2)$ .

$x (- 4 \ln (2)) + x \ln (64) = 28 \ln (2) - 5 \ln (64) + \ln (\frac{1}{1048576})$

Step 8.2

Factor $x$ out of $x \ln (64)$ .

$x (- 4 \ln (2)) + x (\ln (64)) = 28 \ln (2) - 5 \ln (64) + \ln (\frac{1}{1048576})$

Step 8.3

Factor $x$ out of $x (- 4 \ln (2)) + x (\ln (64))$ .

$x (- 4 \ln (2) + \ln (64)) = 28 \ln (2) - 5 \ln (64) + \ln (\frac{1}{1048576})$

Step 9

Divide each term in $x (- 4 \ln (2) + \ln (64)) = 28 \ln (2) - 5 \ln (64) + \ln (\frac{1}{1048576})$ by $- 4 \ln (2) + \ln (64)$ and simplify.

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Step 9.1

Divide each term in $x (- 4 \ln (2) + \ln (64)) = 28 \ln (2) - 5 \ln (64) + \ln (\frac{1}{1048576})$ by $- 4 \ln (2) + \ln (64)$ .

$\frac{x (- 4 \ln (2) + \ln (64))}{- 4 \ln (2) + \ln (64)} = \frac{28 \ln (2)}{- 4 \ln (2) + \ln (64)} + \frac{- 5 \ln (64)}{- 4 \ln (2) + \ln (64)} + \frac{\ln (\frac{1}{1048576})}{- 4 \ln (2) + \ln (64)}$

Step 9.2

Simplify the left side.

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Step 9.2.1

Cancel the common factor of $- 4 \ln (2) + \ln (64)$ .

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Step 9.2.1.1

Cancel the common factor.

Step 9.2.1.2

Divide $x$ by $1$ .

$x = \frac{28 \ln (2)}{- 4 \ln (2) + \ln (64)} + \frac{- 5 \ln (64)}{- 4 \ln (2) + \ln (64)} + \frac{\ln (\frac{1}{1048576})}{- 4 \ln (2) + \ln (64)}$

Step 9.3

Simplify the right side.

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Step 9.3.1

Move the negative in front of the fraction.

$x = \frac{28 \ln (2)}{- 4 \ln (2) + \ln (64)} - \frac{5 \ln (64)}{- 4 \ln (2) + \ln (64)} + \frac{\ln (\frac{1}{1048576})}{- 4 \ln (2) + \ln (64)}$

Step 9.3.2

Combine the numerators over the common denominator.

$x = \frac{28 \ln (2) - 5 \ln (64)}{- 4 \ln (2) + \ln (64)} + \frac{\ln (\frac{1}{1048576})}{- 4 \ln (2) + \ln (64)}$

Step 9.3.3

Combine the numerators over the common denominator.

$x = \frac{28 \ln (2) - 5 \ln (64) + \ln (\frac{1}{1048576})}{- 4 \ln (2) + \ln (64)}$

Step 9.3.4

Factor $- 1$ out of $- 4 \ln (2)$ .

$x = \frac{28 \ln (2) - 5 \ln (64) + \ln (\frac{1}{1048576})}{- (4 \ln (2)) + \ln (64)}$

Step 9.3.5

Factor $- 1$ out of $\ln (64)$ .

$x = \frac{28 \ln (2) - 5 \ln (64) + \ln (\frac{1}{1048576})}{- (4 \ln (2)) - 1 (- \ln (64))}$

Step 9.3.6

Factor $- 1$ out of $- (4 \ln (2)) - 1 (- \ln (64))$ .

$x = \frac{28 \ln (2) - 5 \ln (64) + \ln (\frac{1}{1048576})}{- (4 \ln (2) - \ln (64))}$

Step 9.3.7

Rewrite negatives.

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Step 9.3.7.1

Rewrite $- (4 \ln (2) - \ln (64))$ as $- 1 (4 \ln (2) - \ln (64))$ .

$x = \frac{28 \ln (2) - 5 \ln (64) + \ln (\frac{1}{1048576})}{- 1 (4 \ln (2) - \ln (64))}$

Step 9.3.7.2

Move the negative in front of the fraction.

$x = - \frac{28 \ln (2) - 5 \ln (64) + \ln (\frac{1}{1048576})}{4 \ln (2) - \ln (64)}$

Step 10

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{28 \ln (2) - 5 \ln (64) + \ln (\frac{1}{1048576})}{4 \ln (2) - \ln (64)}$

Decimal Form:

$x = - 11$