Algebra Examples

$x^{2} - 6 x + 7 = - 2$

Step 1

Add $2$ to both sides of the equation.

$x^{2} - 6 x + 7 + 2 = 0$

Step 2

Add $7$ and $2$ .

$x^{2} - 6 x + 9 = 0$

Step 3

Factor using the perfect square rule.

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Step 3.1

Rewrite $9$ as $3^{2}$ .

$x^{2} - 6 x + 3^{2} = 0$

Step 3.2

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$6 x = 2 \cdot x \cdot 3$

Step 3.3

Rewrite the polynomial.

$x^{2} - 2 \cdot x \cdot 3 + 3^{2} = 0$

Step 3.4

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = x$ and $b = 3$ .

${(x - 3)}^{2} = 0$

Step 4

Set the $x - 3$ equal to $0$ .

$x - 3 = 0$

Step 5

Add $3$ to both sides of the equation.

$x = 3$