Algebra Examples

$| 2 x - 3 | \leq - 1$

Step 1

Since $| 2 x - 3 |$ is always positive and $- 1$ is negative, $| 2 x - 3 |$ is always greater than $- 1$ so the inequality cannot be true.

No solution

Step 2

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$