Algebra Examples

$y - | x - 2 |$

Step 1

Add $| x - 2 |$ to both sides of the equation.

$y = | x - 2 |$

Step 2

Find the absolute value vertex. In this case, the vertex for $y = | x - 2 |$ is $(2, 0)$ .

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Step 2.1

To find the $x$ coordinate of the vertex, set the inside of the absolute value $x - 2$ equal to $0$ . In this case, $x - 2 = 0$ .

$x - 2 = 0$

Step 2.2

Add $2$ to both sides of the equation.

$x = 2$

Step 2.3

Replace the variable $x$ with $2$ in the expression.

$y = | (2) - 2 |$

Step 2.4

Simplify $| (2) - 2 |$ .

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Step 2.4.1

Subtract $2$ from $2$ .

$y = | 0 |$

Step 2.4.2

The absolute value is the distance between a number and zero. The distance between $0$ and $0$ is $0$ .

$y = 0$

Step 2.5

The absolute value vertex is $(2, 0)$ .

$(2, 0)$

Step 3

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

$(- \infty, \infty)$

Set-Builder Notation:

${x | x \in ℝ}$

Step 4

For each $x$ value, there is one $y$ value. Select a few $x$ values from the domain. It would be more useful to select the values so that they are around the $x$ value of the absolute value vertex.

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Step 4.1

Substitute the $x$ value $0$ into $f (x) = | x - 2 |$ . In this case, the point is $(0, 2)$ .

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Step 4.1.1

Replace the variable $x$ with $0$ in the expression.

$f (0) = | (0) - 2 |$

Step 4.1.2

Simplify the result.

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Step 4.1.2.1

Subtract $2$ from $0$ .

$f (0) = | - 2 |$

Step 4.1.2.2

The absolute value is the distance between a number and zero. The distance between $- 2$ and $0$ is $2$ .

$f (0) = 2$

Step 4.1.2.3

The final answer is $2$ .

$y = 2$

Step 4.2

Substitute the $x$ value $1$ into $f (x) = | x - 2 |$ . In this case, the point is $(1, 1)$ .

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Step 4.2.1

Replace the variable $x$ with $1$ in the expression.

$f (1) = | (1) - 2 |$

Step 4.2.2

Simplify the result.

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Step 4.2.2.1

Subtract $2$ from $1$ .

$f (1) = | - 1 |$

Step 4.2.2.2

The absolute value is the distance between a number and zero. The distance between $- 1$ and $0$ is $1$ .

$f (1) = 1$

Step 4.2.2.3

The final answer is $1$ .

$y = 1$

Step 4.3

Substitute the $x$ value $4$ into $f (x) = | x - 2 |$ . In this case, the point is $(4, 2)$ .

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Step 4.3.1

Replace the variable $x$ with $4$ in the expression.

$f (4) = | (4) - 2 |$

Step 4.3.2

Simplify the result.

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Step 4.3.2.1

Subtract $2$ from $4$ .

$f (4) = | 2 |$

Step 4.3.2.2

The absolute value is the distance between a number and zero. The distance between $0$ and $2$ is $2$ .

$f (4) = 2$

Step 4.3.2.3

The final answer is $2$ .

$y = 2$

Step 4.4

The absolute value can be graphed using the points around the vertex $(2, 0), (0, 2), (1, 1), (3, 1), (4, 2)$

$\begin{array}{c} x & y \\ 0 & 2 \\ 1 & 1 \\ 2 & 0 \\ 3 & 1 \\ 4 & 2 \end{array}$

Step 5