Algebra Examples

$P_{1} = (5, 310 °)$ , $P_{2} = (6, 345 °)$

Step 1

Use the distance formula to determine the distance between the two points.

$Distance = \sqrt{{(x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2}}$

Step 2

Substitute the actual values of the points into the distance formula.

$\sqrt{{(6 - 5)}^{2} + {(345 ° - 310 °)}^{2}}$

Step 3

Simplify.

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Step 3.1

Subtract $5$ from $6$ .

$\sqrt{1^{2} + {(345 ° - 310 °)}^{2}}$

Step 3.2

One to any power is one.

$\sqrt{1 + {(345 ° - 310 °)}^{2}}$

Step 3.3

Subtract $310 °$ from $345 °$ .

$\sqrt{1 + 35^{2}}$

Step 3.4

Raise $35$ to the power of $2$ .

$\sqrt{1 + 1225}$

Step 3.5

Add $1$ and $1225$ .

$\sqrt{1226}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$\sqrt{1226}$

Decimal Form:

$35.01428280 \dots$

Step 5