Algebra Examples

$y = 4 - 3 \sin (\frac{2}{5} (x + 1))$

Step 1

The parent function is the simplest form of the type of function given.

$y = \sin (x)$

Step 2

Simplify each term.

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Step 2.1

Apply the distributive property.

$y = 4 - 3 \sin (\frac{2}{5} x + \frac{2}{5} \cdot 1)$

Step 2.2

Combine $\frac{2}{5}$ and $x$ .

$y = 4 - 3 \sin (\frac{2 x}{5} + \frac{2}{5} \cdot 1)$

Step 2.3

Multiply $\frac{2}{5}$ by $1$ .

$y = 4 - 3 \sin (\frac{2 x}{5} + \frac{2}{5})$

Step 3

Assume that $y = \sin (x)$ is $f (x) = \sin (x)$ and $y = 4 - 3 \sin (\frac{2}{5} \cdot (x + 1))$ is $g (x) = 4 - 3 \sin (\frac{2 x}{5} + \frac{2}{5})$ .

$f (x) = \sin (x)$

$g (x) = 4 - 3 \sin (\frac{2 x}{5} + \frac{2}{5})$

Step 4

Rewrite the expression as $- 3 \sin (\frac{2 x}{5} + \frac{2}{5}) + 4$ .

$- 3 \sin (\frac{2 x}{5} + \frac{2}{5}) + 4$

Step 5

Use the form $a \sin (b x - c) + d$ to find the variables used to find the amplitude, period, phase shift, and vertical shift.

$a = - 3$

$b = \frac{2}{5}$

$c = - \frac{2}{5}$

$d = 4$

Step 6

Find the amplitude $| a |$ .

Amplitude: $3$

Step 7

Find the period using the formula $\frac{2 π}{| b |}$ .

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Step 7.1

Find the period of $- 3 \sin (\frac{2 x}{5} + \frac{2}{5})$ .

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Step 7.1.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 7.1.2

Replace $b$ with $\frac{2}{5}$ in the formula for period.

$\frac{2 π}{| \frac{2}{5} |}$

Step 7.1.3

$\frac{2}{5}$ is approximately $0.4$ which is positive so remove the absolute value

$\frac{2 π}{\frac{2}{5}}$

Step 7.1.4

Multiply the numerator by the reciprocal of the denominator.

$2 π \frac{5}{2}$

Step 7.1.5

Cancel the common factor of $2$ .

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Step 7.1.5.1

Factor $2$ out of $2 π$ .

$2 (π) \frac{5}{2}$

Step 7.1.5.2

Cancel the common factor.

$2 π \frac{5}{2}$

Step 7.1.5.3

Rewrite the expression.

$π \cdot 5$

Step 7.1.6

Move $5$ to the left of $π$ .

$5 π$

Step 7.2

Find the period of $4$ .

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Step 7.2.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 7.2.2

Replace $b$ with $\frac{2}{5}$ in the formula for period.

$\frac{2 π}{| \frac{2}{5} |}$

Step 7.2.3

$\frac{2}{5}$ is approximately $0.4$ which is positive so remove the absolute value

$\frac{2 π}{\frac{2}{5}}$

Step 7.2.4

Multiply the numerator by the reciprocal of the denominator.

$2 π \frac{5}{2}$

Step 7.2.5

Cancel the common factor of $2$ .

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Step 7.2.5.1

Factor $2$ out of $2 π$ .

$2 (π) \frac{5}{2}$

Step 7.2.5.2

Cancel the common factor.

$2 π \frac{5}{2}$

Step 7.2.5.3

Rewrite the expression.

$π \cdot 5$

Step 7.2.6

Move $5$ to the left of $π$ .

$5 π$

Step 7.3

The period of addition/subtraction of trig functions is the maximum of the individual periods.

$5 π$

Step 8

Find the phase shift using the formula $\frac{c}{b}$ .

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Step 8.1

The phase shift of the function can be calculated from $\frac{c}{b}$ .

Phase Shift: $\frac{c}{b}$

Step 8.2

Replace the values of $c$ and $b$ in the equation for phase shift.

Phase Shift: $\frac{- \frac{2}{5}}{\frac{2}{5}}$

Step 8.3

Cancel the common factor of $\frac{2}{5}$ .

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Step 8.3.1

Cancel the common factor.

Phase Shift: $\frac{- \frac{2}{5}}{\frac{2}{5}}$

Step 8.3.2

Divide $- 1$ by $1$ .

Phase Shift: $- 1$

Step 9

List the properties of the trigonometric function.

Amplitude: $3$

Period: $5 π$

Phase Shift: $- 1$ ( $1$ to the left)

Vertical Shift: $4$

Step 10