Algebra Examples

$(6 x^{4} - 20 x^{3} + 15 x^{2} - 8) \div (- x^{2} + 2 x - 1)$

Step 1

To calculate the remainder, first divide the polynomials.

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Step 1.1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x^{2}$

$2 x$

$1$

$6 x^{4}$

$20 x^{3}$

$15 x^{2}$

$0 x$

$8$

Step 1.2

Divide the highest order term in the dividend $6 x^{4}$ by the highest order term in divisor $- x^{2}$ .

						-	$6 x^{2}$
-	$x^{2}$	+	$2 x$	-	$1$		$6 x^{4}$	-	$20 x^{3}$	+	$15 x^{2}$	+	$0 x$	-	$8$

Step 1.3

Multiply the new quotient term by the divisor.

$6 x^{2}$

$x^{2}$

$2 x$

$1$

$6 x^{4}$

$20 x^{3}$

$15 x^{2}$

$0 x$

$8$

$6 x^{4}$

$12 x^{3}$

$6 x^{2}$

Step 1.4

The expression needs to be subtracted from the dividend, so change all the signs in $6 x^{4} - 12 x^{3} + 6 x^{2}$

$6 x^{2}$

$x^{2}$

$2 x$

$1$

$6 x^{4}$

$20 x^{3}$

$15 x^{2}$

$0 x$

$8$

$6 x^{4}$

$12 x^{3}$

$6 x^{2}$

Step 1.5

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$6 x^{2}$

$x^{2}$

$2 x$

$1$

$6 x^{4}$

$20 x^{3}$

$15 x^{2}$

$0 x$

$8$

$6 x^{4}$

$12 x^{3}$

$6 x^{2}$

$8 x^{3}$

$9 x^{2}$

Step 1.6

Pull the next terms from the original dividend down into the current dividend.

$6 x^{2}$

$x^{2}$

$2 x$

$1$

$6 x^{4}$

$20 x^{3}$

$15 x^{2}$

$0 x$

$8$

$6 x^{4}$

$12 x^{3}$

$6 x^{2}$

$8 x^{3}$

$9 x^{2}$

$0 x$

Step 1.7

Divide the highest order term in the dividend $- 8 x^{3}$ by the highest order term in divisor $- x^{2}$ .

$6 x^{2}$

$8 x$

$x^{2}$

$2 x$

$1$

$6 x^{4}$

$20 x^{3}$

$15 x^{2}$

$0 x$

$8$

$6 x^{4}$

$12 x^{3}$

$6 x^{2}$

$8 x^{3}$

$9 x^{2}$

$0 x$

Step 1.8

Multiply the new quotient term by the divisor.

$6 x^{2}$

$8 x$

$x^{2}$

$2 x$

$1$

$6 x^{4}$

$20 x^{3}$

$15 x^{2}$

$0 x$

$8$

$6 x^{4}$

$12 x^{3}$

$6 x^{2}$

$8 x^{3}$

$9 x^{2}$

$0 x$

$8 x^{3}$

$16 x^{2}$

$8 x$

Step 1.9

The expression needs to be subtracted from the dividend, so change all the signs in $- 8 x^{3} + 16 x^{2} - 8 x$

$6 x^{2}$

$8 x$

$x^{2}$

$2 x$

$1$

$6 x^{4}$

$20 x^{3}$

$15 x^{2}$

$0 x$

$8$

$6 x^{4}$

$12 x^{3}$

$6 x^{2}$

$8 x^{3}$

$9 x^{2}$

$0 x$

$8 x^{3}$

$16 x^{2}$

$8 x$

Step 1.10

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$6 x^{2}$

$8 x$

$x^{2}$

$2 x$

$1$

$6 x^{4}$

$20 x^{3}$

$15 x^{2}$

$0 x$

$8$

$6 x^{4}$

$12 x^{3}$

$6 x^{2}$

$8 x^{3}$

$9 x^{2}$

$0 x$

$8 x^{3}$

$16 x^{2}$

$8 x$

$7 x^{2}$

$8 x$

Step 1.11

Pull the next terms from the original dividend down into the current dividend.

$6 x^{2}$

$8 x$

$x^{2}$

$2 x$

$1$

$6 x^{4}$

$20 x^{3}$

$15 x^{2}$

$0 x$

$8$

$6 x^{4}$

$12 x^{3}$

$6 x^{2}$

$8 x^{3}$

$9 x^{2}$

$0 x$

$8 x^{3}$

$16 x^{2}$

$8 x$

$7 x^{2}$

$8 x$

$8$

Step 1.12

Divide the highest order term in the dividend $- 7 x^{2}$ by the highest order term in divisor $- x^{2}$ .

$6 x^{2}$

$8 x$

$7$

$x^{2}$

$2 x$

$1$

$6 x^{4}$

$20 x^{3}$

$15 x^{2}$

$0 x$

$8$

$6 x^{4}$

$12 x^{3}$

$6 x^{2}$

$8 x^{3}$

$9 x^{2}$

$0 x$

$8 x^{3}$

$16 x^{2}$

$8 x$

$7 x^{2}$

$8 x$

$8$

Step 1.13

Multiply the new quotient term by the divisor.

$6 x^{2}$

$8 x$

$7$

$x^{2}$

$2 x$

$1$

$6 x^{4}$

$20 x^{3}$

$15 x^{2}$

$0 x$

$8$

$6 x^{4}$

$12 x^{3}$

$6 x^{2}$

$8 x^{3}$

$9 x^{2}$

$0 x$

$8 x^{3}$

$16 x^{2}$

$8 x$

$7 x^{2}$

$8 x$

$8$

$7 x^{2}$

$14 x$

$7$

Step 1.14

The expression needs to be subtracted from the dividend, so change all the signs in $- 7 x^{2} + 14 x - 7$

$6 x^{2}$

$8 x$

$7$

$x^{2}$

$2 x$

$1$

$6 x^{4}$

$20 x^{3}$

$15 x^{2}$

$0 x$

$8$

$6 x^{4}$

$12 x^{3}$

$6 x^{2}$

$8 x^{3}$

$9 x^{2}$

$0 x$

$8 x^{3}$

$16 x^{2}$

$8 x$

$7 x^{2}$

$8 x$

$8$

$7 x^{2}$

$14 x$

$7$

Step 1.15

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$6 x^{2}$

$8 x$

$7$

$x^{2}$

$2 x$

$1$

$6 x^{4}$

$20 x^{3}$

$15 x^{2}$

$0 x$

$8$

$6 x^{4}$

$12 x^{3}$

$6 x^{2}$

$8 x^{3}$

$9 x^{2}$

$0 x$

$8 x^{3}$

$16 x^{2}$

$8 x$

$7 x^{2}$

$8 x$

$8$

$7 x^{2}$

$14 x$

$7$

$6 x$

$1$

Step 1.16

The final answer is the quotient plus the remainder over the divisor.

$- 6 x^{2} + 8 x + 7 + \frac{- 6 x - 1}{- x^{2} + 2 x - 1}$

Step 2

Since the last term in the resulting expression is a fraction, the numerator of the fraction is the remainder.

$- 6 x - 1$