Algebra Examples

$10 x - 2 x + 12 = 2 (3 x + 5) + 2 x$

Step 1

Subtract $2 x$ from $10 x$ .

$8 x + 12 = 2 (3 x + 5) + 2 x$

Step 2

Simplify $2 (3 x + 5) + 2 x$ .

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Step 2.1

Simplify each term.

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Step 2.1.1

Apply the distributive property.

$8 x + 12 = 2 (3 x) + 2 \cdot 5 + 2 x$

Step 2.1.2

Multiply $3$ by $2$ .

$8 x + 12 = 6 x + 2 \cdot 5 + 2 x$

Step 2.1.3

Multiply $2$ by $5$ .

$8 x + 12 = 6 x + 10 + 2 x$

$8 x + 12 = 6 x + 10 + 2 x$

Step 2.2

Add $6 x$ and $2 x$ .

$8 x + 12 = 8 x + 10$

$8 x + 12 = 8 x + 10$

Step 3

Move all terms containing $x$ to the left side of the equation.

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Step 3.1

Subtract $8 x$ from both sides of the equation.

$8 x + 12 - 8 x = 10$

Step 3.2

Combine the opposite terms in $8 x + 12 - 8 x$ .

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Step 3.2.1

Subtract $8 x$ from $8 x$ .

$0 + 12 = 10$

Step 3.2.2

Add $0$ and $12$ .

$12 = 10$

$12 = 10$

$12 = 10$

Step 4

Since $12 \neq 10$ , there are no solutions.

No solution

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$