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Algebra Examples
Use synthetic division to find the result when 2x3-5x2-x+62x3−5x2−x+6 is divided by x+1x+1
Step 1
Write the problem as a mathematical expression.
Use synthetic division to find the result when 2x3-5x2-x+6x+12x3−5x2−x+6x+1
Step 2
Place the numbers representing the divisor and the dividend into a division-like configuration.
-1−1 | 22 | -5−5 | -1−1 | 66 |
Step 3
The first number in the dividend (2)(2) is put into the first position of the result area (below the horizontal line).
-1−1 | 22 | -5−5 | -1−1 | 66 |
22 |
Step 4
Multiply the newest entry in the result (2)(2) by the divisor (-1)(−1) and place the result of (-2)(−2) under the next term in the dividend (-5)(−5).
-1−1 | 22 | -5−5 | -1−1 | 66 |
-2−2 | ||||
22 |
Step 5
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
-1−1 | 22 | -5−5 | -1−1 | 66 |
-2−2 | ||||
22 | -7−7 |
Step 6
Multiply the newest entry in the result (-7)(−7) by the divisor (-1)(−1) and place the result of (7)(7) under the next term in the dividend (-1)(−1).
-1−1 | 22 | -5−5 | -1−1 | 66 |
-2−2 | 77 | |||
22 | -7−7 |
Step 7
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
-1−1 | 22 | -5−5 | -1−1 | 66 |
-2−2 | 77 | |||
22 | -7−7 | 66 |
Step 8
Multiply the newest entry in the result (6)(6) by the divisor (-1)(−1) and place the result of (-6)(−6) under the next term in the dividend (6)(6).
-1−1 | 22 | -5−5 | -1−1 | 66 |
-2−2 | 77 | -6−6 | ||
22 | -7−7 | 66 |
Step 9
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
-1−1 | 22 | -5−5 | -1−1 | 66 |
-2−2 | 77 | -6−6 | ||
22 | -7−7 | 66 | 00 |
Step 10
All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.
2x2+-7x+62x2+−7x+6
Step 11
Simplify the quotient polynomial.
2x2-7x+62x2−7x+6