Algebra Examples

$3 x + 12 = - 6$

Step 1

Find the x-intercepts.

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Step 1.1

Solve the equation for

$x$ .

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Step 1.1.1

Move all terms not containing

$x$ to the right side of the equation.

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Step 1.1.1.1

Subtract

$12$ from both sides of the equation.

$3 x = - 6 - 12$

Step 1.1.1.2

Subtract

$12$ from

$- 6$ .

$3 x = - 18$

Step 1.1.2

Divide each term in

$3 x = - 18$ by

$3$ and simplify.

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Step 1.1.2.1

Divide each term in

$3 x = - 18$ by

$3$ .

$\frac{3 x}{3} = \frac{- 18}{3}$

Step 1.1.2.2

Simplify the left side.

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Step 1.1.2.2.1

Cancel the common factor of

$3$ .

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Step 1.1.2.2.1.1

Cancel the common factor.

$\frac{3 x}{3} = \frac{- 18}{3}$

Step 1.1.2.2.1.2

Divide

$x$ by

$1$ .

$x = \frac{- 18}{3}$

Step 1.1.2.3

Simplify the right side.

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Step 1.1.2.3.1

Divide

$- 18$ by

$3$ .

$x = - 6$

Step 1.2

Since

$x = - 6$ is a vertical line, the x-intercept(s) is equal to the value of

$x$ .

x-intercept(s):

$- 6$

x-intercept(s):

$- 6$

Step 2

Since

$x = - 6$ is a vertical line, the y-intercept(s) is equal to the value of

$x$ .

y-intercept(s):

$None$

Step 3

List the intersections.

x-intercept(s):

$- 6$

y-intercept(s):

$None$

Step 4

$3 x + 12 = - 6$

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