Algebra Examples

$15 x + 5 y = 20$ $y = 8 - 3 x$

Step 1

Reorder $8$ and $- 3 x$ .

$y = - 3 x + 8$

$15 x + 5 y = 20$

Step 2

Replace all occurrences of $y$ with $- 3 x + 8$ in each equation.

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Step 2.1

Replace all occurrences of $y$ in $15 x + 5 y = 20$ with $- 3 x + 8$ .

$15 x + 5 (- 3 x + 8) = 20$

$y = - 3 x + 8$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify $15 x + 5 (- 3 x + 8)$ .

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Step 2.2.1.1

Simplify each term.

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Step 2.2.1.1.1

Apply the distributive property.

$15 x + 5 (- 3 x) + 5 \cdot 8 = 20$

$y = - 3 x + 8$

Step 2.2.1.1.2

Multiply $- 3$ by $5$ .

$15 x - 15 x + 5 \cdot 8 = 20$

$y = - 3 x + 8$

Step 2.2.1.1.3

Multiply $5$ by $8$ .

$15 x - 15 x + 40 = 20$

$y = - 3 x + 8$

$15 x - 15 x + 40 = 20$

$y = - 3 x + 8$

Step 2.2.1.2

Simplify by adding terms.

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Step 2.2.1.2.1

Subtract $15 x$ from $15 x$ .

$0 + 40 = 20$

$y = - 3 x + 8$

Step 2.2.1.2.2

Add $0$ and $40$ .

$40 = 20$

$y = - 3 x + 8$

$40 = 20$

$y = - 3 x + 8$

$40 = 20$

$y = - 3 x + 8$

$40 = 20$

$y = - 3 x + 8$

$40 = 20$

$y = - 3 x + 8$

Step 3

Since $40 = 20$ is not true, there is no solution.

No solution

Step 4